alignof operator(since C++11)| General topics | ||||||||||||||||
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Queries alignment requirements of a type.
Contents |
alignof(type-id) | |||||||||
Returns a value of typestd::size_t.
Returnsthe alignment, in bytes, required for any instance of the type indicated bytype-id, which is eithercomplete object type, an array type whose element type is complete, or a reference type to one of those types.
If the type is reference type, the operator returns the alignment of referenced type; if the type is array type, alignment requirement of the element type is returned.
Seealignment for the meaning and properties of the value returned byalignof.
#include <iostream> struct Foo{int i;float f;char c;}; // Note: alignas(alignof(long double)) below can be// simplified to alignas(long double) if desired.struct alignas(alignof(longdouble)) Foo2{// put your definition here}; struct Empty{}; struct alignas(64) Empty64{}; #define SHOW(expr) std::cout << #expr << " = " << (expr) << '\n' int main(){ SHOW(alignof(char)); SHOW(alignof(int*)); SHOW(alignof(Foo)); SHOW(alignof(Foo2)); SHOW(alignof(Empty)); SHOW(alignof(Empty64));}
Possible output:
alignof(char) = 1alignof(int*) = 8alignof(Foo) = 4alignof(Foo2) = 16alignof(Empty) = 1alignof(Empty64) = 64
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| CWG 1305 | C++11 | type-id could not represent a reference to an array with an unknown bound but a complete element type | allowed |
| Alignment requirement | restricts the addresses at which an object may be allocated |
alignas(C++11) | specifies that the storage for the variable should be aligned by specific amount (specifier)[edit] |
(C++11) | obtains the type's alignment requirements (class template)[edit] |
C documentation for _Alignof,alignof operator | |