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      std::list<T,Allocator>::size

      From cppreference.com
      <cpp‎ |container‎ |list

      [edit template]
       
       
       
      std::list
      Member functions
      Non-member functions
      (until C++20)(until C++20)(until C++20)(until C++20)(until C++20)
      Deduction guides(C++17)
       
      size_type size()const;
      		(noexcept since C++11)
      (constexpr since C++26)

      Returns the number of elements in the container.

      Contents

      [edit]Return value

      std::distance(begin(), end())

      [edit]Complexity

      Constant or linear.

      		(until C++11)

      Constant.

      		(since C++11)

      [edit]Example

      [edit]

      The following code usessize to display the number of elements in astd::list:

      Run this code
      #include <list>#include <iostream> int main(){std::list<int> nums{1,3,5,7}; std::cout<<"nums contains "<< nums.size()<<" elements.\n";}

      Output:

      nums contains 4 elements.

      [edit]See also

      checks whether the container is empty
      (public member function)[edit]
      returns the maximum possible number of elements
      (public member function)[edit]
      changes the number of elements stored
      (public member function)[edit]
      (C++17)(C++20)
      		 returns the size of a container or array
      (function template)[edit]
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