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Article

Bernoulli Polynomials and Their Some New Congruence Properties

School of Mathematics, Northwest University, Xi’an 710127, China
*
Author to whom correspondence should be addressed.
Symmetry2019,11(3), 365;https://doi.org/10.3390/sym11030365
Submission received: 18 February 2019 /Revised: 7 March 2019 /Accepted: 8 March 2019 /Published: 11 March 2019
(This article belongs to the Special IssueCurrent Trends in Symmetric Polynomials with their Applications)

Abstract

:
The aim of this article is to use the fundamental modus and the properties of the Euler polynomials and Bernoulli polynomials to prove some new congruences related to Bernoulli polynomials. One of them is that for any integerh or any non-negative integern, we obtain the congruenceB2n+1(2h)0mod(2n+1), whereBn(x) are Bernoulli polynomials.

    1. Introduction

    As usual, for the real numberx, ifm0 denotes any integer, the famous Bernoulli polynomialsBm(x) (see [1,2,3,4]) and Euler polynomialsEm(x) (see [2,3,4,5]) are decided by the coefficients of the series of powers:
    z·ezxez1=m=0Bm(x)m!·zm
    and:
    2ezxez+1=m=0Em(x)m!·zm.
    Ifx=0, thenEm=Em(0) andBm=Bm(0) are known as themth Euler numbers andmth Bernoulli numbers, respectively. For example, some values ofBm andEm areB0=1,B1=12,B2=16,B3=0,B4=130,B5=0,B6=142 andE0=1,E1=12,E2=0,E3=14,E4=0,E5=12,E6=0, etc. These polynomials and numbers occupy a very important position in number theory and combinatorics; this is not only because Bernoulli and Euler polynomials are well known, but also because they have a wide range of theoretical and applied values. Because of this, many scholars have studied the properties of these polynomials and numbers, and they also have obtained some valuable research conclusions. For instance, Zhang Wenpeng [6] studied a few combinational identities. As a continuation of the conclusion in [6], he showed that ifp is a prime, one can obtain the congruence expression:
    (1)p12·2p1·Ep1120modpifp1mod4;2modpifp3mod4.
    Hou Yiwei and Shen Shimeng [3] proved the identity:
    E2n1=22n1n·B2n.
    As some corollaries of [3], Hou Yiwei and Shen Shimeng obtained several interesting congruences. For example, forp in an odd prime, one can obtain the expression:
    Ep320modp,ifp1mod8
    .
    Zhao Jianhong and Chen Zhuoyu [7] obtained the following deduction: ifm is a positive integer,k2, one obtains the equation:
    a1+a2++ak=mEa1(a1)!·Ea2(a2)!Eak(ak)!=2k1(k1)!·1m!i=0k1C(k1,i)Em+k1i,
    for which the summation is taken over allk-dimensional nonnegative integer coordinates(a1,a2,,ak) such that the equationa1+a2++ak=m, and the sequence{C(k,i)} is decided as follows: for any integers0ik,C(k,k)=k!,C(k,0)=1,
    C(k+1,i+1)=C(k,i+1)+(k+1)C(k,i),forall0i<k,
    providingC(k,i)=0, ifi>k, andk is a positive integer.
    T.Kim et al. did a good deal of research work and obtained a series of significant results; see [5,8,9,10,11,12,13,14]. Specifically, in [5], T. Kim found many valuable results involving Euler numbers and polynomials connected with zeta functions. Other papers in regard to the Bernoulli polynomials and Euler polynomials can be found in [15,16,17,18,19]; we will not go into detail here.
    Here, we will make use of the properties of the Euler numbers, Euler polynomials, Bernoulli numbers, and Bernoulli polynomials to verify a special relationship between the Bernoulli polynomials and Euler polynomials. As some of the applications of our conclusions, we also deduce two unusual congruences involving the Bernoulli polynomials.
    Theorem 1.
    For any positive integers m and h, the following identity should be obtained, that is:
    2·B2m+1(2h)=2m+1·E2m(2h)+2i=02h1E2m(i).
    Theorem 2.
    For any positive integers m and h, we derive the identity as below:
    B2m(2h)B2n+mE2m1(2h)E2m1=2m·i=12hE2m1(i).
    From these deductions, the following several corollaries can be inferred:
    Corollary 1.
    Let m be a non-negative integer. Thus, for any integer h, we obtain the congruence:
    B2m+1(2h)0mod(2m+1),
    whereab0modk implies(a,b)=1 andka for any integers b(b0) and a.
    Corollary 2.
    For any positive integer m and integer h,22m1·B2m(2h)B2m must be an integer, and:
    22m1·B2m(2h)B2m0modm.
    Corollary 3.
    For any integer h, let p be an odd prime; as a result, we have:
    Bp(2h)0modpandB2p(2h)B2pmodp.
    Corollary 4.
    Let p be an odd prime. In this way, there exits an integer N withN1modp such that the polynomial congruence:
    N·Bp(x)(x2)(x1)x·(xp+1)x·xp11modp.
    Some notes: It is well known that congruences regarding Bernoulli numbers have interesting applications in number theory; in particular, for studying the class numbers of class-groups of number fields. Therefore, our corollaries will promote the further development of research in this field. Some important results in this field can also be found in [20,21,22,23]. Here, we will not list them one by one.

    2. Several Lemmas

    In this part, we will provide three straightforward lemmas. Henceforth, we will handle certain mathematical analysis knowledge and the properties of the Euler polynomials and Bernoulli polynomials, all of which can be discovered from [1,2,3]. Thus, they will not be repeated here.
    Lemma 1.
    Ifm0 is an integer, polynomial2m·Em(x) denotes the integral coefficient polynomial of x.
    Proof. 
    First, from Definition 2 of the Euler polynomialsEm(x), we have:
    2exz=ez+1·2exzez+1=1+m=01n!·zmm=0Em(x)m!·zm.
    On the other hand, we also have:
    2exz=2·m=0xmm!·zm.
    uniting (3) and (4), then comparing the coefficients of the power series, we obtain that:
    2xm=Em(x)+k=0mmkEk(x)
    or identity:
    2Em(x)=2xmk=0m1mkEk(x).
    Note thatE0(x)=1,E1(x)=x12, so from (5) and mathematical induction, we may immediately deduce that2m·Em(x) is an integral coefficient polynomial ofx.
    Lemma 2.
    If m is a positive integer, the following equation can be obtained:
    2m·Bm(x)=Bm(2x)12·m·Em1(2x).
    Proof. 
    From Definitions 1 and 2 of the Euler polynomials and Bernoulli polynomials, we discover the identity as below:
    2ze2xze2z1=m=02m·Bm(x)m!·zm=z·e2xzez1z·e2xzez+1=m=0Bm(2x)m!·zm12m=0Em(2x)m!·zm+1.
    Relating the coefficients of the power series in (6), we obtain:
    2m·Bm(x)=Bm(2x)m2·Em1(2x).
    This proves Lemma 2. □
    Lemma 3.
    If m is a positive integer, then for any positive integer M, we will be able to obtain the identities:
    2m·BmMBm=m·i=02M1Em1(i).
    Proof. 
    On the basis of Definition 2 of the Euler polynomials, we obtain:
    i=0N12zeizez+1=m=01n!i=0N1Em(i)·zm+1.
    In another aspect, we also obtain:
    i=0N12zeizez+1=2zeNz1ez+1ez1=2zeNz2ze2z1=m=02m·BmN2m!·zmm=02m·Bmm!·zm.
    Combining (7) and (8), then comparing the coefficients of the power series, we will obtain:
    2m·BmN2Bm=m·i=0N1Em1(i).
    Now, Lemma 3 follows from (9) withN=2M. □

    3. Proofs of the Theorems

    Applying three simple lemmas inSection 2, we can easily finish the proofs of our theorems. Above all, we study Theorem 1. For any positive integerm, from Lemma 2, we have:
    22m+1·B2m+1(M)=B2m+1(2M)2m+12·E2m(2M).
    Note thatB2m+1=0. From Lemma 3, we also have:
    22m+1·B2m+1M=(2m+1)·i=02M1E2m(i).
    Combining (10) and (11), we have:
    B2m+1(2M)=2m+12·E2m(2M)+2m+1·i=02M1E2m(i).
    Afterwards, we prove Theorem 2. According to Lemma 2 withx=M andx=0, we have:
    22m·B2m(M)=B2m(2M)m·E2m1(2M)
    and:
    22m·B2m=B2mm·E2m1.
    Applying Lemma 3, we also have:
    22m·B2mMB2m=(2m)·i=02M1E2m1(i).
    Combining (12), (13), and (14), we have the identity:
    B2m2MB2m=m·E2m1(2M)m·E2m1+2m·i=02M1E2m1(i).
    This proves Theorem 2.
    From Lemma 1, we know that all22m·E2m(i) (i=0,1,,2M) are integers, and(22m,2m+1)=1, so on the basis of Theorem 1, we may directly deduce the congruence:
    B2m+1(2M)0mod(2m+1).
    SinceB2m+1(x) is an odd function (that is,B2m+1(x)=B2m+1(x)), andB2m+1=0, so (15) also holds for any integerM and non-negative integerm.
    This completes the proof of Corollary 1.
    Now, we study Corollary 2. On the basis of Lemma 1, we know that22m1·E2m1(i) is an integer for all1i2M, so from Theorem 1, we know that22m1·B2m2MB2m must be an integer, and it can be divided bym, that is,
    22m1·B2m2MB2m0modm.
    Note thatB2m(x) is an even function, and ifM=0, after that, the left-hand side of (16) becomes zero; thus, the congruence (16) is correct for all integersM.
    This completes the proof of Corollary 2.
    Corollary 3 is a special case of Corollary 1 with2m+1=p and Corollary 2 with2m=2p.
    Now, we prove Corollary 4. SinceBp(x) is apth rational coefficient polynomial ofx and its first item isxp, from Lemma 3, we know that the congruence equationBp(2x)0modp has exactlyp different solutionsx=0,1,2,p1, so there exits an integerN withN1modp satisfied withN·Bp(x), an integral coefficient polynomial ofx. From [1] (see Theorem 5.23), we have the congruence:
    N·Bp(x)x(x1)(x2)·(xp+1)modp.
    This completes the proofs of our all results.

    4. Conclusions

    As we all know, the congruences of Bernoulli numbers have important applications in number theory; in particular, for studying the class numbers of class-groups of number fields. The main results of this paper are two theorems involving Bernoulli and Euler polynomials and numbers and four corollaries (or congruences). Two theorems gave some new equations regarding Bernoulli polynomials and Euler polynomials. As some applications of these theorems, we gave four interesting congruences involving Bernoulli polynomials. Especially, Corollaries 1 and 4 are very simple and beautiful. It is clear that Corollary 4 is a good reference for further research on Bernoulli polynomials.

    Author Contributions

    All authors have equally contributed to this work. All authors read and approved the final manuscript.

    Funding

    This work is supported by the NSF (11771351) and (11826205) of P. R. China.

    Acknowledgments

    The authors would like to thank the Editor and referee for their very helpful and detailed comments, which have significantly improved the presentation of this paper.

    Conflicts of Interest

    The authors declare that there are no conflicts of interest regarding the publication of this paper.

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    © 2019 by the authors. Licensee MDPI, Basel, Switzerland. This article is an open access article distributed under the terms and conditions of the Creative Commons Attribution (CC BY) license (http://creativecommons.org/licenses/by/4.0/).

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    Duan, R.; Shen, S. Bernoulli Polynomials and Their Some New Congruence Properties.Symmetry2019,11, 365. https://doi.org/10.3390/sym11030365

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    Duan R, Shen S. Bernoulli Polynomials and Their Some New Congruence Properties.Symmetry. 2019; 11(3):365. https://doi.org/10.3390/sym11030365

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    Duan, Ran, and Shimeng Shen. 2019. "Bernoulli Polynomials and Their Some New Congruence Properties"Symmetry 11, no. 3: 365. https://doi.org/10.3390/sym11030365

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    Duan, R., & Shen, S. (2019). Bernoulli Polynomials and Their Some New Congruence Properties.Symmetry,11(3), 365. https://doi.org/10.3390/sym11030365

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