Class Double
- All Implemented Interfaces:
Serializable,Comparable<Double>,Constable,ConstantDesc
Double class is thewrapper class for values of the primitive typedouble. An object of typeDouble contains a single field whose type isdouble.In addition, this class provides several methods for converting adouble to aString and aString to adouble, as well as other constants and methods useful when dealing with adouble.
This is avalue-based class; programmers should treat instances that areequal as interchangeable and should not use instances for synchronization, or unpredictable behavior may occur. For example, in a future release, synchronization may fail.
Floating-point Equality, Equivalence, and Comparison
IEEE 754 floating-point values include finite nonzero values, signed zeros (+0.0 and-0.0), signed infinities (positive infinity andnegative infinity), andNaN (not-a-number).Anequivalence relation on a set of values is a boolean relation on pairs of values that is reflexive, symmetric, and transitive. For more discussion of equivalence relations and object equality, see theObject.equals specification. An equivalence relation partitions the values it operates over into sets calledequivalence classes. All the members of the equivalence class are equal to each other under the relation. An equivalence class may contain only a single member. At least for some purposes, all the members of an equivalence class are substitutable for each other. In particular, in a numeric expression equivalent values can besubstituted for one another without changing the result of the expression, meaning changing the equivalence class of the result of the expression.
Notably, the built-in== operation on floating-point values isnot an equivalence relation. Despite not defining an equivalence relation, the semantics of the IEEE 754== operator were deliberately designed to meet other needs of numerical computation. There are two exceptions where the properties of an equivalence relation are not satisfied by == on floating-point values:
- If
v1andv2are both NaN, thenv1 == v2has the valuefalse. Therefore, for two NaN arguments thereflexive property of an equivalence relation isnot satisfied by the==operator. - If
v1represents+0.0whilev2represents-0.0, or vice versa, thenv1 == v2has the valuetrueeven though+0.0and-0.0are distinguishable under various floating-point operations. For example,1.0/+0.0evaluates to positive infinity while1.0/-0.0evaluates tonegative infinity and positive infinity and negative infinity are neither equal to each other nor equivalent to each other. Thus, while a signed zero input most commonly determines the sign of a zero result, because of dividing by zero,+0.0and-0.0may not be substituted for each other in general. The sign of a zero input also has a non-substitutable effect on the result of some math library methods.
For ordered comparisons using the built-in comparison operators (<,<=, etc.), NaN values have another anomalous situation: a NaN is neither less than, nor greater than, nor equal to any value, including itself. This means thetrichotomy of comparison doesnot hold.
To provide the appropriate semantics forequals andcompareTo methods, those methods cannot simply be wrappers around== or ordered comparison operations. Instead,equals usesrepresentation equivalence, defining NaN arguments to be equal to each other, restoring reflexivity, and defining+0.0 tonot be equal to-0.0. For comparisons,compareTo defines a total order where-0.0 is less than+0.0 and where a NaN is equal to itself and considered greater than positive infinity.
The operational semantics ofequals and compareTo are expressed in terms ofbit-wise converting the floating-point values to integral values.
Thenatural ordering implemented bycompareTo isconsistent with equals. That is, two objects are reported as equal byequals if and only ifcompareTo on those objects returns zero.
The adjusted behaviors defined forequals and compareTo allow instances of wrapper classes to work properly with conventional data structures. For example, defining NaN values to beequals to one another allows NaN to be used as an element of aHashSet or as the key of aHashMap. Similarly, defining compareTo as a total ordering, including+0.0, -0.0, and NaN, allows instances of wrapper classes to be used as elements of aSortedSet or as keys of aSortedMap.
Comparing numerical equality to various useful equivalence relations that can be defined over floating-point values:
- numerical equality (
==operator): (Not an equivalence relation) - Two floating-point values represent the same extended real number. The extended real numbers are the real numbers augmented with positive infinity and negative infinity. Under numerical equality,
+0.0and-0.0are equal since they both map to the same real value, 0. A NaN does not map to any real number and is not equal to any value, including itself. - bit-wise equivalence:
- The bits of the two floating-point values are the same. This equivalence relation for
doublevaluesaandbis implemented by the expressionDouble.doubleToRawLongBits(a) == Double.doubleToRawLongBits(b)
Under this relation,+0.0and-0.0are distinguished from each other and every bit pattern encoding a NaN is distinguished from every other bit pattern encoding a NaN. - representation equivalence:
- The two floating-point values represent the same IEEE 754datum. In particular, forfinite values, the sign,exponent, and significand components of the floating-point values are the same. Under this relation:
+0.0and-0.0are distinguished from each other.- every bit pattern encoding a NaN is considered equivalent to each other
- positive infinity is equivalent to positive infinity; negative infinity is equivalent to negative infinity.
Double.doubleToLongBits(a) == Double.doubleToLongBits(b)Double.valueOf(a).equals(Double.valueOf(b))Double.compare(a, b) == 0
a andb, if neither ofa andb is zero or NaN, then the three relations numerical equality, bit-wise equivalence, and representation equivalence ofa andb have the sametrue/false value. In other words, for binary floating-point values, the three relations only differ if at least one argument is zero or NaN.Decimal ↔ Binary Conversion Issues
Many surprising results of binary floating-point arithmetic trace back to aspects of decimal to binary conversion and binary to decimal conversion. While integer values can be exactly represented in any base, which fractional values can be exactly represented in a base is a function of the base. For example, in base 10, 1/3 is a repeating fraction (0.33333....); but in base 3, 1/3 is exactly 0.1(3), that is 1 × 3-1. Similarly, in base 10, 1/10 is exactly representable as 0.1 (1 × 10-1), but in base 2, it is a repeating fraction (0.0001100110011...(2)).Values of thefloat type have24 bits of precision and values of thedouble type have53 bits of precision. Therefore, since 0.1 is a repeating fraction in base 2 with a four-bit repeat, 0.1f !=0.1d. In more detail, including hexadecimal floating-point literals:
- The exact numerical value of
0.1f(0x1.99999a0000000p-4f) is 0.100000001490116119384765625. - The exact numerical value of
0.1d(0x1.999999999999ap-4d) is 0.1000000000000000055511151231257827021181583404541015625.
float anddouble values, respectively, to the numerical value of 0.1. These results are consistent with afloat value having the equivalent of 6 to 9 digits of decimal precision and adouble value having the equivalent of 15 to 17 digits of decimal precision. (The equivalent precision varies according to the different relative densities of binary and decimal values at different points along the real number line.)This representation hazard of decimal fractions is one reason to use caution when storing monetary values asfloat or double. Alternatives include:
- using
BigDecimalto store decimal fractional values exactly - scaling up so the monetary value is an integer — for example, multiplying by 100 if the value is denominated in cents or multiplying by 1000 if the value is denominated in mills — and then storing that scaled value in an integer type
For each finite floating-point value and a given floating-point type, there is a contiguous region of the real number line which maps to that value. Under the default round to nearest rounding policy (JLS15.4), this contiguous region for a value is typically oneulp (unit in the last place) wide and centered around the exactly representable value. (At exponent boundaries, the region is asymmetrical and larger on the side with the larger exponent.) For example, for0.1f, the region can be computed as follows:
// Numeric values listed are exact values
oneTenthApproxAsFloat = 0.100000001490116119384765625;
ulpOfoneTenthApproxAsFloat = Math.ulp(0.1f) = 7.450580596923828125E-9;
// Numeric range that is converted to the float closest to 0.1, _excludes_ endpoints
(oneTenthApproxAsFloat - ½ulpOfoneTenthApproxAsFloat, oneTenthApproxAsFloat + ½ulpOfoneTenthApproxAsFloat) =
(0.0999999977648258209228515625, 0.1000000052154064178466796875)
In particular, a correctly rounded decimal to binary conversion of any string representing a number in this range, say byFloat.parseFloat(String), will be converted to the same value:
Float.parseFloat("0.0999999977648258209228515625000001"); // rounds up to oneTenthApproxAsFloatFloat.parseFloat("0.099999998"); // rounds up to oneTenthApproxAsFloatFloat.parseFloat("0.1"); // rounds up to oneTenthApproxAsFloatFloat.parseFloat("0.100000001490116119384765625"); // exact conversionFloat.parseFloat("0.100000005215406417846679687"); // rounds down to oneTenthApproxAsFloatFloat.parseFloat("0.100000005215406417846679687499999"); // rounds down to oneTenthApproxAsFloatSimilarly, an analogous range can be constructed for the double type based on the exact value ofdouble approximation to0.1d and the numerical value of Math.ulp(0.1d) and likewise for other particular numerical values in thefloat anddouble types.
As seen in the above conversions, compared to the exact numerical value the operation would have without rounding, the same floating-point value as a result can be:
- greater than the exact result
- equal to the exact result
- less than the exact result
0.1f + 0.1f + 0.1f + 0.1f + 0.1f + 0.1f + 0.1f + 0.1f + 0.1f + 0.1f;// Numerical value of computed sum: 1.00000011920928955078125,// the next floating-point value larger than 1.0f, equal to Math.nextUp(1.0f).0.1d + 0.1d + 0.1d + 0.1d + 0.1d + 0.1d + 0.1d + 0.1d + 0.1d + 0.1d;// Numerical value of computed sum: 0.99999999999999988897769753748434595763683319091796875,// the next floating-point value smaller than 1.0d, equal to Math.nextDown(1.0d).double d = 0.0;while (d != 1.0) { // Surprising infinite loop d += 0.1; // Sum never _exactly_ equals 1.0}double d = 0.0;for (int i = 0; i < 10; i++) { d += 0.1;} // Value of d is equal to Math.nextDown(1.0).<,<=,>,>=):double d = 0.0;while (d <= 1.0) { d += 0.1;} // Value of d approximately 1.0999999999999999- SeeJava Language Specification:
- 4.2.3 Floating-Point Types and Values
4.2.4 Floating-Point Operations
15.21.1 Numerical Equality Operators == and !=
15.20.1 Numerical Comparison Operators<,<=,>, and>= - Since:
- 1.0
- External Specifications
- See Also:
Field Summary
FieldsModifier and TypeFieldDescriptionstatic final intThe number of bytes used to represent adoublevalue,8.static final intMaximum exponent a finitedoublevariable may have,1023.static final doubleA constant holding the largest positive finite value of typedouble,(2-2-52)·21023.static final intMinimum exponent a normalizeddoublevariable may have,-1022.static final doubleA constant holding the smallest positive normal value of typedouble, 2-1022.static final doubleA constant holding the smallest positive nonzero value of typedouble, 2-1074.static final doubleA constant holding a Not-a-Number (NaN) value of typedouble.static final doubleA constant holding the negative infinity of typedouble.static final doubleA constant holding the positive infinity of typedouble.static final intThe number of bits in the significand of adoublevalue, 53.static final intThe number of bits used to represent adoublevalue,64.TheClassinstance representing the primitive typedouble.Constructor Summary
ConstructorsMethod Summary
Modifier and TypeMethodDescriptionbyteReturns the value of thisDoubleas abyteafter a narrowing primitive conversion.static intcompare(double d1, double d2) Compares the two specifieddoublevalues.intCompares twoDoubleobjects numerically.Returns anOptionalcontaining the nominal descriptor for thisinstance, which is the instance itself.static longdoubleToLongBits(double value) Returns a representation of the specified floating-point valueaccording to the IEEE 754 floating-point "doubleformat" bit layout.static longdoubleToRawLongBits(double value) Returns a representation of the specified floating-point valueaccording to the IEEE 754 floating-point "doubleformat" bit layout, preserving Not-a-Number (NaN) values.doubleReturns thedoublevalue of thisDoubleobject.booleanCompares this object against the specified object.floatReturns the value of thisDoubleas afloatafter a narrowing primitive conversion.inthashCode()Returns a hash code for thisDoubleobject.static inthashCode(double value) Returns a hash code for adoublevalue; compatible withDouble.hashCode().intintValue()Returns the value of thisDoubleas anintafter a narrowing primitive conversion.static booleanisFinite(double d) Returnstrueif the argument is a finite floating-pointvalue; returnsfalseotherwise (for NaN and infinityarguments).booleanReturnstrueif thisDoublevalue isinfinitely large in magnitude,falseotherwise.static booleanisInfinite(double v) Returnstrueif the specified number is infinitelylarge in magnitude,falseotherwise.booleanisNaN()Returnstrueif thisDoublevalue isa Not-a-Number (NaN),falseotherwise.static booleanisNaN(double v) Returnstrueif the specified number is aNot-a-Number (NaN) value,falseotherwise.static doublelongBitsToDouble(long bits) Returns thedoublevalue corresponding to a givenbit representation.longReturns the value of thisDoubleas alongafter a narrowing primitive conversion.static doublemax(double a, double b) Returns the greater of twodoublevaluesas if by callingMath.max.static doublemin(double a, double b) Returns the smaller of twodoublevaluesas if by callingMath.min.static doubleReturns a newdoubleinitialized to the valuerepresented by the specifiedString, as performedby thevalueOfmethod of classDouble.Resolves this instance as aConstantDesc, the result of which isthe instance itself.shortReturns the value of thisDoubleas ashortafter a narrowing primitive conversion.static doublesum(double a, double b) Adds twodoublevalues together as per the + operator.staticStringtoHexString(double d) Returns a hexadecimal string representation of thedoubleargument.toString()Returns a string representation of thisDoubleobject.staticStringtoString(double d) Returns a string representation of thedoubleargument.staticDoublevalueOf(double d) Returns aDoubleinstance representing the specifieddoublevalue.staticDoubleReturns aDoubleobject holding thedoublevalue represented by the argument strings.
Field Details
POSITIVE_INFINITY
public static final double POSITIVE_INFINITYA constant holding the positive infinity of typedouble. It is equal to the value returned byDouble.longBitsToDouble(0x7ff0000000000000L).- See Also:
NEGATIVE_INFINITY
public static final double NEGATIVE_INFINITYA constant holding the negative infinity of typedouble. It is equal to the value returned byDouble.longBitsToDouble(0xfff0000000000000L).- See Also:
NaN
public static final double NaNA constant holding a Not-a-Number (NaN) value of typedouble.It isequivalent to thevalue returned byDouble.longBitsToDouble(0x7ff8000000000000L).- See Also:
MAX_VALUE
public static final double MAX_VALUEA constant holding the largest positive finite value of typedouble,(2-2-52)·21023. It is equal tothe hexadecimal floating-point literal0x1.fffffffffffffP+1023and also equal toDouble.longBitsToDouble(0x7fefffffffffffffL).- See Also:
MIN_NORMAL
public static final double MIN_NORMALA constant holding the smallest positive normal value of typedouble, 2-1022. It is equal to thehexadecimal floating-point literal0x1.0p-1022and alsoequal toDouble.longBitsToDouble(0x0010000000000000L).- Since:
- 1.6
- See Also:
MIN_VALUE
public static final double MIN_VALUEA constant holding the smallest positive nonzero value of typedouble, 2-1074. It is equal to thehexadecimal floating-point literal0x0.0000000000001P-1022and also equal toDouble.longBitsToDouble(0x1L).- See Also:
SIZE
public static final int SIZEThe number of bits used to represent adoublevalue,64.- Since:
- 1.5
- See Also:
PRECISION
public static final int PRECISIONThe number of bits in the significand of adoublevalue, 53. This is the parameter N in section4.2.3 ofThe Java Language Specification.- Since:
- 19
- See Also:
MAX_EXPONENT
public static final int MAX_EXPONENTMaximum exponent a finitedoublevariable may have,1023. It is equal to the value returned byMath.getExponent(Double.MAX_VALUE).- Since:
- 1.6
- See Also:
MIN_EXPONENT
public static final int MIN_EXPONENTMinimum exponent a normalizeddoublevariable may have,-1022. It is equal to the value returned byMath.getExponent(Double.MIN_NORMAL).- Since:
- 1.6
- See Also:
BYTES
public static final int BYTESThe number of bytes used to represent adoublevalue,8.- Since:
- 1.8
- See Also:
TYPE
Constructor Details
Double
Deprecated.It is rarely appropriate to use this constructor. The static factoryvalueOf(double)is generally a better choice, as it islikely to yield significantly better space and time performance.Constructs a newly allocatedDoubleobject thatrepresents the primitivedoubleargument.- Parameters:
value- the value to be represented by theDouble.
Double
Deprecated.It is rarely appropriate to use this constructor.UseparseDouble(String)to convert a string to adoubleprimitive, or usevalueOf(String)to convert a string to aDoubleobject.Constructs a newly allocatedDoubleobject thatrepresents the floating-point value of typedoublerepresented by the string. The string is converted to adoublevalue as if by thevalueOfmethod.- Parameters:
s- a string to be converted to aDouble.- Throws:
NumberFormatException- if the string does not contain a parsable number.
Method Details
toString
Returns a string representation of thedoubleargument. All characters mentioned below are ASCII characters.- If the argument is NaN, the result is the string "
NaN". - Otherwise, the result is a string that represents the sign andmagnitude (absolute value) of the argument. If the sign is negative,the first character of the result is '
-'('\u002D'); if the sign is positive, no sign characterappears in the result. As for the magnitudem:- Ifm is infinity, it is represented by the characters
"Infinity"; thus, positive infinity produces the result"Infinity"and negative infinity produces the result"-Infinity". - Ifm is zero, it is represented by the characters
"0.0"; thus, negative zero produces the result"-0.0"and positive zero produces the result"0.0". - Otherwisem is positive and finite.It is converted to a string in two stages:
- Selection of a decimal:A well-defined decimaldmis selected to representm.This decimal is (almost always) theshortest one thatrounds tom according to the round to nearestrounding policy of IEEE 754 floating-point arithmetic.
- Formatting as a string:The decimaldm is formatted as a string,either in plain or in computerized scientific notation,depending on its value.
- Ifm is infinity, it is represented by the characters
Adecimal is a number of the forms×10ifor some (unique) integerss > 0 andi such thats is not a multiple of 10.These integers are thesignificand andtheexponent, respectively, of the decimal.Thelength of the decimal is the (unique)positive integern meeting10n-1 ≤s < 10n.
The decimaldm for a finite positivemis defined as follows:
- LetR be the set of all decimals that round tomaccording to the usualround to nearest rounding policy ofIEEE 754 floating-point arithmetic.
- Letp be the minimal length over all decimals inR.
- Whenp ≥ 2, letT be the set of all decimalsinR with lengthp.Otherwise, letT be the set of all decimalsinR with length 1 or 2.
- Definedm as the decimal inTthat is closest tom.Or if there are two such decimals inT,select the one with the even significand.
The (uniquely) selected decimaldmis then formatted.Lets,i andn be the significand, exponent andlength ofdm, respectively.Further, lete =n +i - 1 and lets1…snbe the usual decimal expansion ofs.Note thats1 ≠ 0andsn ≠ 0.Below, the decimal point
'.'is'\u002E'and the exponent indicator'E'is'\u0045'.- Case -3 ≤e < 0:dm is formatted as
0.0…0s1…sn,where there are exactly -(n +i) zeroes betweenthe decimal point ands1.For example, 123 × 10-4 is formatted as0.0123. - Case 0 ≤e < 7:
- Subcasei ≥ 0:dm is formatted ass1…sn
0…0.0,where there are exactlyi zeroesbetweensn and the decimal point.For example, 123 × 102 is formatted as12300.0. - Subcasei < 0:dm is formatted ass1…sn+i
.sn+i+1…sn,where there are exactly -i digits to the right ofthe decimal point.For example, 123 × 10-1 is formatted as12.3.
- Subcasei ≥ 0:dm is formatted ass1…sn
- Casee < -3 ore ≥ 7:computerized scientific notation is used to formatdm.Heree is formatted as by
Integer.toString(int).- Subcasen = 1:dm is formatted ass1
.0Ee.For example, 1 × 1023 is formatted as1.0E23. - Subcasen > 1:dm is formatted ass1
.s2…snEe.For example, 123 × 10-21 is formatted as1.23E-19.
- Subcasen = 1:dm is formatted ass1
To create localized string representations of a floating-pointvalue, use subclasses of
NumberFormat.- API Note:
- This method corresponds to the general functionality of theconvertToDecimalCharacter operation defined in IEEE 754;however, that operation is defined in terms of specifying thenumber of significand digits used in the conversion.Code to do such a conversion in the Java platform includesconverting the
doubleto aBigDecimalexactly and then rounding theBigDecimaltothe desired number of digits; sample code:double d = 0.1;int digits = 25;BigDecimal bd = new BigDecimal(d);String result = bd.round(new MathContext(digits, RoundingMode.HALF_UP));// 0.1000000000000000055511151 - Parameters:
d- thedoubleto be converted.- Returns:
- a string representation of the argument.
- If the argument is NaN, the result is the string "
toHexString
Returns a hexadecimal string representation of thedoubleargument. All characters mentioned beloware ASCII characters.- If the argument is NaN, the result is the string "
NaN". - Otherwise, the result is a string that represents the signand magnitude of the argument. If the sign is negative, thefirst character of the result is '
-'('\u002D'); if the sign is positive, no signcharacter appears in the result. As for the magnitudem:- Ifm is infinity, it is represented by the string
"Infinity"; thus, positive infinity produces theresult"Infinity"and negative infinity producesthe result"-Infinity". - Ifm is zero, it is represented by the string
"0x0.0p0"; thus, negative zero produces the result"-0x0.0p0"and positive zero produces the result"0x0.0p0". - Ifm is a
doublevalue with anormalized representation, substrings are used to represent thesignificand and exponent fields. The significand isrepresented by the characters"0x1."followed by a lowercase hexadecimal representation of the restof the significand as a fraction. Trailing zeros in thehexadecimal representation are removed unless all the digitsare zero, in which case a single zero is used. Next, theexponent is represented by"p"followedby a decimal string of the unbiased exponent as if produced bya call toInteger.toStringon theexponent value. - Ifm is a
doublevalue with a subnormalrepresentation, the significand is represented by thecharacters"0x0."followed by ahexadecimal representation of the rest of the significand as afraction. Trailing zeros in the hexadecimal representation areremoved. Next, the exponent is represented by"p-1022". Note that there must be atleast one nonzero digit in a subnormal significand.
- Ifm is infinity, it is represented by the string
Examples Floating-point Value Hexadecimal String 1.00x1.0p0-1.0-0x1.0p02.00x1.0p13.00x1.8p10.50x1.0p-10.250x1.0p-2Double.MAX_VALUE0x1.fffffffffffffp1023Minimum Normal Value0x1.0p-1022Maximum Subnormal Value0x0.fffffffffffffp-1022Double.MIN_VALUE0x0.0000000000001p-1022- API Note:
- This method corresponds to the convertToHexCharacter operationdefined in IEEE 754.
- Parameters:
d- thedoubleto be converted.- Returns:
- a hex string representation of the argument.
- Since:
- 1.5
- If the argument is NaN, the result is the string "
valueOf
Returns aDoubleobject holding thedoublevalue represented by the argument strings.If
sisnull, then aNullPointerExceptionis thrown.Leading and trailing whitespace characters in
sare ignored. Whitespace is removed as if by theString.trim()method; that is, both ASCII space and controlcharacters are removed. The rest ofsshouldconstitute aFloatValue as described by the lexicalsyntax rules:
whereSign,FloatingPointLiteral,HexNumeral,HexDigits,SignedInteger andFloatTypeSuffix are as defined in the lexical structuresections ofThe Java Language Specification,except that underscores are not accepted between digits.If- FloatValue:
- Signopt
NaN- Signopt
Infinity- Signopt FloatingPointLiteral
- Signopt HexFloatingPointLiteral
- SignedInteger
- Signopt
- HexFloatingPointLiteral:
- HexSignificand BinaryExponent FloatTypeSuffixopt
- HexSignificand:
- HexNumeral
- HexNumeral
.0xHexDigitsopt.HexDigits0XHexDigitsopt.HexDigits - HexNumeral
- BinaryExponent:
- BinaryExponentIndicator SignedInteger
- BinaryExponentIndicator:
pP
sdoes not have the form ofaFloatValue, then aNumberFormatExceptionis thrown. Otherwise,sis regarded asrepresenting an exact decimal value in the usual"computerized scientific notation" or as an exacthexadecimal value; this exact numerical value is thenconceptually converted to an "infinitely precise"binary value that is then rounded to typedoubleby the usual round-to-nearest rule of IEEE 754 floating-pointarithmetic, which includes preserving the sign of a zerovalue.Note that the round-to-nearest rule also implies overflow andunderflow behaviour; if the exact value ofsis largeenough in magnitude (greater than or equal to (MAX_VALUE+ulp(MAX_VALUE)/2),rounding todoublewill result in an infinity and if theexact value ofsis small enough in magnitude (lessthan or equal toMIN_VALUE/2), rounding to float willresult in a zero.Finally, after rounding aDoubleobject representingthisdoublevalue is returned.Note that trailing format specifiers, specifiers thatdetermine the type of a floating-point literal(
1.0fis afloatvalue;1.0dis adoublevalue), donot influence the results of this method. In otherwords, the numerical value of the input string is converteddirectly to the target floating-point type. The two-stepsequence of conversions, string tofloatfollowedbyfloattodouble, isnotequivalent to converting a string directly todouble. For example, thefloatliteral0.1fis equal to thedoublevalue0.10000000149011612; thefloatliteral0.1frepresents a different numericalvalue than thedoubleliteral0.1. (The numerical value 0.1 cannot be exactlyrepresented in a binary floating-point number.)To avoid calling this method on an invalid string and havinga
NumberFormatExceptionbe thrown, the regularexpression below can be used to screen the input string:final String Digits = "(\\p{Digit}+)"; final String HexDigits = "(\\p{XDigit}+)"; // an exponent is 'e' or 'E' followed by an optionally // signed decimal integer. final String Exp = "[eE][+-]?"+Digits; final String fpRegex = ("[\\x00-\\x20]*"+ // Optional leading "whitespace" "[+-]?(" + // Optional sign character "NaN|" + // "NaN" string "Infinity|" + // "Infinity" string // A decimal floating-point string representing a finite positive // number without a leading sign has at most five basic pieces: // Digits . Digits ExponentPart FloatTypeSuffix // // Since this method allows integer-only strings as input // in addition to strings of floating-point literals, the // two sub-patterns below are simplifications of the grammar // productions from section 3.10.2 of // The Java Language Specification. // Digits ._opt Digits_opt ExponentPart_opt FloatTypeSuffix_opt "((("+Digits+"(\\.)?("+Digits+"?)("+Exp+")?)|"+ // . Digits ExponentPart_opt FloatTypeSuffix_opt "(\\.("+Digits+")("+Exp+")?)|"+ // Hexadecimal strings "((" + // 0[xX] HexDigits ._opt BinaryExponent FloatTypeSuffix_opt "(0[xX]" + HexDigits + "(\\.)?)|" + // 0[xX] HexDigits_opt . HexDigits BinaryExponent FloatTypeSuffix_opt "(0[xX]" + HexDigits + "?(\\.)" + HexDigits + ")" + ")[pP][+-]?" + Digits + "))" + "[fFdD]?))" + "[\\x00-\\x20]*");// Optional trailing "whitespace" if (Pattern.matches(fpRegex, myString)) Double.valueOf(myString); // Will not throw NumberFormatException else { // Perform suitable alternative action }- API Note:
- To interpret localized string representations of afloating-point value, or string representations that havenon-ASCII digits, use
NumberFormat. Forexample,whereNumberFormat.getInstance(l).parse(s).doubleValue();lis the desired locale, orLocale.ROOTif locale insensitive., This method corresponds to the convertFromDecimalCharacter andconvertFromHexCharacter operations defined in IEEE 754. - Parameters:
s- the string to be parsed.- Returns:
- a
Doubleobject holding the value represented by theStringargument. - Throws:
NumberFormatException- if the string does not contain a parsable number.- See Also:
valueOf
Returns aDoubleinstance representing the specifieddoublevalue.If a newDoubleinstance is not required, this methodshould generally be used in preference to the constructorDouble(double), as this method is likely to yieldsignificantly better space and time performance by cachingfrequently requested values.- Parameters:
d- a double value.- Returns:
- a
Doubleinstance representingd. - Since:
- 1.5
parseDouble
Returns a newdoubleinitialized to the valuerepresented by the specifiedString, as performedby thevalueOfmethod of classDouble.- Parameters:
s- the string to be parsed.- Returns:
- the
doublevalue represented by the string argument. - Throws:
NullPointerException- if the string is nullNumberFormatException- if the string does not contain a parsabledouble.- Since:
- 1.2
- See Also:
isNaN
public static boolean isNaN(double v) Returnstrueif the specified number is aNot-a-Number (NaN) value,falseotherwise.- API Note:
- This method corresponds to the isNaN operation defined in IEEE754.
- Parameters:
v- the value to be tested.- Returns:
trueif the value of the argument is NaN;falseotherwise.
isInfinite
public static boolean isInfinite(double v) Returnstrueif the specified number is infinitelylarge in magnitude,falseotherwise.- API Note:
- This method corresponds to the isInfinite operation defined inIEEE 754.
- Parameters:
v- the value to be tested.- Returns:
trueif the value of the argument is positive infinity or negative infinity;falseotherwise.
isFinite
public static boolean isFinite(double d) Returnstrueif the argument is a finite floating-pointvalue; returnsfalseotherwise (for NaN and infinityarguments).- API Note:
- This method corresponds to the isFinite operation defined inIEEE 754.
- Parameters:
d- thedoublevalue to be tested- Returns:
trueif the argument is a finitefloating-point value,falseotherwise.- Since:
- 1.8
isNaN
public boolean isNaN()Returnstrueif thisDoublevalue isa Not-a-Number (NaN),falseotherwise.- Returns:
trueif the value represented by this object is NaN;falseotherwise.
isInfinite
public boolean isInfinite()Returnstrueif thisDoublevalue isinfinitely large in magnitude,falseotherwise.- Returns:
trueif the value represented by this object is positive infinity or negative infinity;falseotherwise.
toString
byteValue
public byte byteValue()Returns the value of thisDoubleas abyteafter a narrowing primitive conversion.- Overrides:
byteValuein classNumber- Returns:
- the
doublevalue represented by this object converted to typebyte - SeeJava Language Specification:
- 5.1.3 Narrowing Primitive Conversion
- Since:
- 1.1
shortValue
public short shortValue()Returns the value of thisDoubleas ashortafter a narrowing primitive conversion.- Overrides:
shortValuein classNumber- Returns:
- the
doublevalue represented by this object converted to typeshort - SeeJava Language Specification:
- 5.1.3 Narrowing Primitive Conversion
- Since:
- 1.1
intValue
public int intValue()Returns the value of thisDoubleas anintafter a narrowing primitive conversion.- Specified by:
intValuein classNumber- API Note:
- This method corresponds to the convertToIntegerTowardZerooperation defined in IEEE 754.
- Returns:
- the
doublevalue represented by this object converted to typeint - SeeJava Language Specification:
- 5.1.3 Narrowing Primitive Conversion
longValue
public long longValue()Returns the value of thisDoubleas alongafter a narrowing primitive conversion.- Specified by:
longValuein classNumber- API Note:
- This method corresponds to the convertToIntegerTowardZerooperation defined in IEEE 754.
- Returns:
- the
doublevalue represented by this object converted to typelong - SeeJava Language Specification:
- 5.1.3 Narrowing Primitive Conversion
floatValue
public float floatValue()Returns the value of thisDoubleas afloatafter a narrowing primitive conversion.- Specified by:
floatValuein classNumber- API Note:
- This method corresponds to the convertFormat operation definedin IEEE 754.
- Returns:
- the
doublevalue represented by this object converted to typefloat - SeeJava Language Specification:
- 5.1.3 Narrowing Primitive Conversion
- Since:
- 1.0
doubleValue
public double doubleValue()Returns thedoublevalue of thisDoubleobject.- Specified by:
doubleValuein classNumber- Returns:
- the
doublevalue represented by this object
hashCode
public int hashCode()Returns a hash code for thisDoubleobject. Theresult is the exclusive OR of the two halves of thelonginteger bit representation, exactly asproduced by the methoddoubleToLongBits(double), ofthe primitivedoublevalue represented by thisDoubleobject. That is, the hash code is the valueof the expression:
where(int)(v^(v>>>32))vis defined by:long v = Double.doubleToLongBits(this.doubleValue());hashCode
public static int hashCode(double value) Returns a hash code for adoublevalue; compatible withDouble.hashCode().- Parameters:
value- the value to hash- Returns:
- a hash code value for a
doublevalue. - Since:
- 1.8
equals
Compares this object against the specified object. The resultistrueif and only if the argument is notnulland is aDoubleobject thatrepresents adoublethat has the same value as thedoublerepresented by this object. For thispurpose, twodoublevalues are considered to bethe same if and only if the methoddoubleToLongBits(double)returns the identicallongvalue when applied to each.- Overrides:
equalsin classObject- API Note:
- This method is defined in terms of
doubleToLongBits(double)rather than the==operatorondoublevalues since the==operator doesnot define an equivalence relation and to satisfy theequals contract an equivalencerelation must be implemented; seethis discussion for details of floating-point equality and equivalence. - Parameters:
obj- the reference object with which to compare.- Returns:
trueif this object is the same as the obj argument;falseotherwise.- SeeJava Language Specification:
- 15.21.1 Numerical Equality Operators == and !=
- See Also:
doubleToLongBits
public static long doubleToLongBits(double value) Returns a representation of the specified floating-point valueaccording to the IEEE 754 floating-point "doubleformat" bit layout.Bit 63 (the bit that is selected by the mask
0x8000000000000000L) represents the sign of thefloating-point number. Bits62-52 (the bits that are selected by the mask0x7ff0000000000000L) represent the exponent. Bits 51-0(the bits that are selected by the mask0x000fffffffffffffL) represent the significand(sometimes called the mantissa) of the floating-point number.If the argument is positive infinity, the result is
0x7ff0000000000000L.If the argument is negative infinity, the result is
0xfff0000000000000L.If the argument is NaN, the result is
0x7ff8000000000000L.In all cases, the result is a
longinteger that, whengiven to thelongBitsToDouble(long)method, will produce afloating-point value the same as the argument todoubleToLongBits(except all NaN values arecollapsed to a single "canonical" NaN value).- Parameters:
value- adoubleprecision floating-point number.- Returns:
- the bits that represent the floating-point number.
doubleToRawLongBits
public static long doubleToRawLongBits(double value) Returns a representation of the specified floating-point valueaccording to the IEEE 754 floating-point "doubleformat" bit layout, preserving Not-a-Number (NaN) values.Bit 63 (the bit that is selected by the mask
0x8000000000000000L) represents the sign of thefloating-point number. Bits62-52 (the bits that are selected by the mask0x7ff0000000000000L) represent the exponent. Bits 51-0(the bits that are selected by the mask0x000fffffffffffffL) represent the significand(sometimes called the mantissa) of the floating-point number.If the argument is positive infinity, the result is
0x7ff0000000000000L.If the argument is negative infinity, the result is
0xfff0000000000000L.If the argument is NaN, the result is the
longinteger representing the actual NaN value. Unlike thedoubleToLongBitsmethod,doubleToRawLongBitsdoes not collapse all the bitpatterns encoding a NaN to a single "canonical" NaNvalue.In all cases, the result is a
longinteger that,when given to thelongBitsToDouble(long)method, willproduce a floating-point value the same as the argument todoubleToRawLongBits.- Parameters:
value- adoubleprecision floating-point number.- Returns:
- the bits that represent the floating-point number.
- Since:
- 1.3
longBitsToDouble
public static double longBitsToDouble(long bits) Returns thedoublevalue corresponding to a givenbit representation.The argument is considered to be a representation of afloating-point value according to the IEEE 754 floating-point"double format" bit layout.If the argument is
0x7ff0000000000000L, the resultis positive infinity.If the argument is
0xfff0000000000000L, the resultis negative infinity.If the argument is any value in the range
0x7ff0000000000001Lthrough0x7fffffffffffffffLor in the range0xfff0000000000001Lthrough0xffffffffffffffffL, the result is a NaN. No IEEE754 floating-point operation provided by Java can distinguishbetween two NaN values of the same type with different bitpatterns. Distinct values of NaN are only distinguishable byuse of theDouble.doubleToRawLongBitsmethod.In all other cases, lets,e, andm be threevalues that can be computed from the argument:
Then the floating-point result equals the value of the mathematicalexpressions·m·2e-1075.int s = ((bits >> 63) == 0) ? 1 : -1;int e = (int)((bits >> 52) & 0x7ffL);long m = (e == 0) ? (bits & 0xfffffffffffffL) << 1 : (bits & 0xfffffffffffffL) | 0x10000000000000L;Note that this method may not be able to return a
doubleNaN with exactly same bit pattern as thelongargument. IEEE 754 distinguishes between twokinds of NaNs, quiet NaNs andsignaling NaNs. Thedifferences between the two kinds of NaN are generally notvisible in Java. Arithmetic operations on signaling NaNs turnthem into quiet NaNs with a different, but often similar, bitpattern. However, on some processors merely copying asignaling NaN also performs that conversion. In particular,copying a signaling NaN to return it to the calling methodmay perform this conversion. SolongBitsToDoublemay not be able to return adoublewith asignaling NaN bit pattern. Consequently, for somelongvalues,doubleToRawLongBits(longBitsToDouble(start))maynot equalstart. Moreover, whichparticular bit patterns represent signaling NaNs is platformdependent; although all NaN bit patterns, quiet or signaling,must be in the NaN range identified above.- Parameters:
bits- anylonginteger.- Returns:
- the
doublefloating-point value with the same bit pattern.
compareTo
Compares twoDoubleobjects numerically.This method imposes a total order onDoubleobjectswith two differences compared to the incomplete order defined bythe Java language numerical comparison operators (<, <=,==, >=, >) ondoublevalues.- A NaN isunordered with respect to other values and unequal to itself under the comparison operators. This method chooses to define
Double.NaNto be equal to itself and greater than all otherdoublevalues (includingDouble.POSITIVE_INFINITY). - Positive zero and negative zero compare equal numerically, but are distinct and distinguishable values. This method chooses to define positive zero (
+0.0d), to be greater than negative zero (-0.0d).
Doubleobjects imposed by this method isconsistent withequals; seethisdiscussion for details of floating-point comparison andordering.- Specified by:
compareToin interfaceComparable<Double>- Parameters:
anotherDouble- theDoubleto be compared.- Returns:
- the value
0ifanotherDoubleis numerically equal to thisDouble; a value less than0if thisDoubleis numerically less thananotherDouble; and a value greater than0if thisDoubleis numerically greater thananotherDouble. - SeeJava Language Specification:
- 15.20.1 Numerical Comparison Operators
<,<=,>, and>= - Since:
- 1.2
- A NaN isunordered with respect to other values and unequal to itself under the comparison operators. This method chooses to define
compare
public static int compare(double d1, double d2) Compares the two specifieddoublevalues. The signof the integer value returned is the same as that of theinteger that would be returned by the call:Double.valueOf(d1).compareTo(Double.valueOf(d2))
- Parameters:
d1- the firstdoubleto compared2- the seconddoubleto compare- Returns:
- the value
0ifd1is numerically equal tod2; a value less than0ifd1is numerically less thand2; and a value greater than0ifd1is numerically greater thand2. - Since:
- 1.4
sum
public static double sum(double a, double b) Adds twodoublevalues together as per the + operator.- API Note:
- This method corresponds to the addition operationdefined in IEEE 754.
- Parameters:
a- the first operandb- the second operand- Returns:
- the sum of
aandb - SeeJava Language Specification:
- 4.2.4 Floating-Point Operations
- Since:
- 1.8
- See Also:
max
public static double max(double a, double b) Returns the greater of twodoublevaluesas if by callingMath.max.- API Note:
- This method corresponds to the maximum operation defined inIEEE 754.
- Parameters:
a- the first operandb- the second operand- Returns:
- the greater of
aandb - Since:
- 1.8
- See Also:
min
public static double min(double a, double b) Returns the smaller of twodoublevaluesas if by callingMath.min.- API Note:
- This method corresponds to the minimum operation defined inIEEE 754.
- Parameters:
a- the first operandb- the second operand- Returns:
- the smaller of
aandb. - Since:
- 1.8
- See Also:
describeConstable
resolveConstantDesc
Resolves this instance as aConstantDesc, the result of which isthe instance itself.- Specified by:
resolveConstantDescin interfaceConstantDesc- Parameters:
lookup- ignored- Returns:
- theDouble instance
- Since:
- 12