parseInt()
BaselineWidely available
This feature is well established and works across many devices and browser versions. It’s been available across browsers since July 2015.
TheparseInt()
function parses a string argument and returns an integer of the specifiedradix (the base in mathematical numeral systems).
Try it
console.log(parseInt("123"));// 123 (default base-10)console.log(parseInt("123", 10));// 123 (explicitly specify base-10)console.log(parseInt(" 123 "));// 123 (whitespace is ignored)console.log(parseInt("077"));// 77 (leading zeros are ignored)console.log(parseInt("1.9"));// 1 (decimal part is truncated)console.log(parseInt("ff", 16));// 255 (lower-case hexadecimal)console.log(parseInt("0xFF", 16));// 255 (upper-case hexadecimal with "0x" prefix)console.log(parseInt("xyz"));// NaN (input can't be converted to an integer)
Syntax
parseInt(string)parseInt(string, radix)
Parameters
string
A string starting with an integer. Leadingwhitespace in this argument is ignored.
radix
OptionalAn integer between
2
and36
that represents theradix (the base in mathematical numeral systems) of thestring
. It is converted to a32-bit integer; if it's nonzero and outside the range of [2, 36] after conversion, the function will always returnNaN
. If0
or not provided, the radix will be inferred based onstring
's value. Be careful — this doesnot always default to10
! Thedescription below explains in more detail what happens whenradix
is not provided.
Return value
An integer parsed from the givenstring
, orNaN
when
- the
radix
as a 32-bit integer is smaller than2
or bigger than36
, or - the first non-whitespace character cannot be converted to a number.
Note:JavaScript does not have the distinction of "floating point numbers" and "integers" on the language level.parseInt()
andparseFloat()
only differ in their parsing behavior, but not necessarily their return values. For example,parseInt("42")
andparseFloat("42")
would return the same value: aNumber
42.
Description
TheparseInt
functionconverts its first argument to a string, parses that string, then returns an integer orNaN
.
If notNaN
, the return value will be the integer that is the first argument taken as a number in the specifiedradix
. (For example, aradix
of10
converts from a decimal number,8
converts from octal,16
from hexadecimal, and so on.)
Theradix
argument isconverted to a number. If it's unprovided, or if the value becomes 0,NaN
orInfinity
(undefined
is coerced toNaN
), JavaScript assumes the following:
- If the input
string
, with leading whitespace and possible+
/-
signs removed, begins with0x
or0X
(a zero, followed by lowercase or uppercase X),radix
is assumed to be16
and the rest of the string is parsed as a hexadecimal number. - If the input
string
begins with any other value, the radix is10
(decimal).
Note:Other prefixes like0b
, which are valid innumber literals, are treated as normal digits byparseInt()
.parseInt()
doesnot treat strings beginning with a0
character as octal values either. The only prefix thatparseInt()
recognizes is0x
or0X
for hexadecimal values — everything else is parsed as a decimal value ifradix
is missing.Number()
orBigInt()
can be used instead to parse these prefixes.
If the radix is16
,parseInt()
allows the string to be optionally prefixed by0x
or0X
after the optional sign character (+
/-
).
If the radix value (coerced if necessary) is not in range [2, 36] (inclusive)parseInt
returnsNaN
.
For radices above10
, letters of the English alphabet indicate numerals greater than9
. For example, for hexadecimal numbers (base16
),A
throughF
are used. The letters are case-insensitive.
parseInt
understands exactly two signs:+
for positive, and-
for negative. It is done as an initial step in the parsing after whitespace is removed. If no signs are found, the algorithm moves to the following step; otherwise, it removes the sign and runs the number-parsing on the rest of the string.
IfparseInt
encounters a character in the input string that is not a valid numeral in the specifiedradix
, it ignores it and all succeeding characters and returns the integer value parsed up to that point. For example,parseInt("2", 2)
returnsNaN
because2
is not a valid numeral in the binary number system. Likewise, although1e3
technically encodes an integer (and will be correctly parsed to the integer1000
byparseFloat()
),parseInt("1e3", 10)
returns1
, becausee
is not a valid numeral in base 10. Because.
is not a numeral either, the return value will always be an integer.
If the first character cannot be converted to a number with the radix in use,parseInt
returnsNaN
. Leading whitespace is allowed.
For arithmetic purposes, theNaN
value is not a number in any radix. You can call theNumber.isNaN
function to determine if the result ofparseInt
isNaN
. IfNaN
is passed on to arithmetic operations, the operation result will also beNaN
.
Because large numbers use thee
character in their string representation (e.g.,6.022e23
for 6.022 × 1023), usingparseInt
to truncate numbers will produce unexpected results when used on very large or very small numbers.parseInt
shouldnot be used as a substitute forMath.trunc()
.
To convert a number to its string literal in a particular radix, usethatNumber.toString(radix)
.
BecauseparseInt()
returns a number, it may suffer from loss of precision if the integer represented by the string isoutside the safe range. TheBigInt()
function supports parsing integers of arbitrary length accurately, by returning aBigInt
.
Examples
Using parseInt()
The following examples all return15
:
parseInt("0xF", 16);parseInt("F", 16);parseInt("17", 8);parseInt("015", 10);parseInt("15,123", 10);parseInt("FXX123", 16);parseInt("1111", 2);parseInt("15 * 3", 10);parseInt("15e2", 10);parseInt("15px", 10);parseInt("12", 13);
The following examples all returnNaN
:
parseInt("Hello", 8); // Not a number at allparseInt("546", 2); // Digits other than 0 or 1 are invalid for binary radix
The following examples all return-15
:
parseInt("-F", 16);parseInt("-0F", 16);parseInt("-0XF", 16);parseInt("-17", 8);parseInt("-15", 10);parseInt("-1111", 2);parseInt("-15e1", 10);parseInt("-12", 13);
The following example returns224
:
parseInt("0e0", 16);
parseInt()
does not handleBigInt
values. It stops at then
character, and treats the preceding string as a normal integer, with possible loss of precision.
parseInt("900719925474099267n");// 900719925474099300
You should pass the string to theBigInt()
function instead, without the trailingn
character.
BigInt("900719925474099267");// 900719925474099267n
parseInt
doesn't work withnumeric separators:
parseInt("123_456"); // 123
Using parseInt() on non-strings
parseInt()
can have interesting results when working on non-strings combined with a high radix; for example,36
(which makes all alphanumeric characters valid numeric digits).
parseInt(null, 36); // 1112745: The string "null" is 1112745 in base 36parseInt(undefined, 36); // 86464843759093: The string "undefined" is 86464843759093 in base 36
In general, it's a bad idea to useparseInt()
on non-strings, especially to use it as a substitution forMath.trunc()
. It may work on small numbers:
parseInt(15.99, 10); // 15parseInt(-15.1, 10); // -15
However, it only happens to work because the string representation of these numbers uses basic fractional notation ("15.99"
,"-15.1"
), whereparseInt()
stops at the decimal point. Numbers greater than or equal to 1e+21 or less than or equal to 1e-7 use exponential notation ("1.5e+22"
,"1.51e-8"
) in their string representation, andparseInt()
will stop at thee
character or decimal point, which always comes after the first digit. This means for large and small numbers,parseInt()
will return a one-digit integer:
parseInt(4.7 * 1e22, 10); // Very large number becomes 4parseInt(0.00000000000434, 10); // Very small number becomes 4parseInt(0.0000001, 10); // 1parseInt(0.000000123, 10); // 1parseInt(1e-7, 10); // 1parseInt(1000000000000000000000, 10); // 1parseInt(123000000000000000000000, 10); // 1parseInt(1e21, 10); // 1
Specifications
Specification |
---|
ECMAScript® 2026 Language Specification # sec-parseint-string-radix |