Date.prototype.setFullYear()
Baseline Widely available
This feature is well established and works across many devices and browser versions. It’s been available across browsers since July 2015.
ThesetFullYear() method ofDate instances changes the year, month, and/or day of month for this date according to local time.
In this article
Try it
const event = new Date("August 19, 1975 23:15:30");event.setFullYear(1969);console.log(event.getFullYear());// Expected output: 1969event.setFullYear(0);console.log(event.getFullYear());// Expected output: 0Syntax
setFullYear(yearValue)setFullYear(yearValue, monthValue)setFullYear(yearValue, monthValue, dateValue)Parameters
yearValueAn integer representing the year. For example, 1995.
monthValueOptionalAn integer representing the month: 0 for January, 1 for February, and so on.
dateValueOptionalAn integer between 1 and 31 representing the day of the month. If you specify
dateValue, you must also specifymonthValue.
Return value
Changes theDate object in place, and returns its newtimestamp. If a parameter isNaN (or other values that getcoerced toNaN, such asundefined), the date is set toInvalid Date andNaN is returned.
Description
If you do not specify themonthValue anddateValue parameters, the same values as what are returned bygetMonth() andgetDate() are used.
If a parameter you specify is outside of the expected range, other parameters and the date information in theDate object are updated accordingly. For example, if you specify 15 formonthValue, the year is incremented by 1 (yearValue + 1), and 3 is used for the month.
BecausesetFullYear() operates on the local time, crossing a Daylight Saving Time (DST) boundary may result in a different elapsed time than expected. For example, if setting the date crosses a spring-forward transition (losing an hour), the difference in timestamps between the new and old date is one hour less than the nominal day difference multiplied by 24 hours. Conversely, crossing a fall-back transition (gaining an hour) result in an extra hour. If you need to adjust the date by a fixed amount of time, consider usingsetUTCFullYear() orsetTime().
If the new local time falls within an offset transition, the exact time is derived using the same behavior asTemporal'sdisambiguation: "compatible" option. That is, if the local time corresponds to two instants, the earlier one is chosen; if the local time does not exist (there is a gap), we go forward by the gap duration.
Examples
>Using setFullYear()
const theBigDay = new Date();theBigDay.setFullYear(1997);Specifications
| Specification |
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| ECMAScript® 2026 Language Specification> # sec-date.prototype.setfullyear> |