Array.prototype.reduceRight()
Baseline Widely available
This feature is well established and works across many devices and browser versions. It’s been available across browsers since July 2015.
ThereduceRight() method ofArray instances applies a function against an accumulator and each value of the array (from right-to-left) to reduce it to a single value.
See alsoArray.prototype.reduce() for left-to-right.
In this article
Try it
const array = [ [0, 1], [2, 3], [4, 5],];const result = array.reduceRight((accumulator, currentValue) => accumulator.concat(currentValue),);console.log(result);// Expected output: Array [4, 5, 2, 3, 0, 1]Syntax
reduceRight(callbackFn)reduceRight(callbackFn, initialValue)Parameters
callbackFnA function to execute for each element in the array. Its return value becomes the value of the
accumulatorparameter on the next invocation ofcallbackFn. For the last invocation, the return value becomes the return value ofreduceRight(). The function is called with the following arguments:accumulatorThe value resulting from the previous call to
callbackFn. On the first call, its value isinitialValueif the latter is specified; otherwise its value is the last element of the array.currentValueThe value of the current element. On the first call, its value is the last element if
initialValueis specified; otherwise its value is the second-to-last element.currentIndexThe index position of
currentValuein the array. On the first call, its value isarray.length - 1ifinitialValueis specified, otherwisearray.length - 2.arrayThe array
reduceRight()was called upon.
initialValueOptionalValue to use as accumulator to the first call of the
callbackFn. If no initial value is supplied, the last element in the array will be used and skipped. CallingreduceRight()on an empty array without an initial value creates aTypeError.
Return value
The value that results from the reduction.
Description
ThereduceRight() method is aniterative method. It runs a "reducer" callback function over all elements in the array, in descending-index order, and accumulates them into a single value. Read theiterative methods section for more information about how these methods work in general.
callbackFn is invoked only for array indexes which have assigned values. It is not invoked for empty slots insparse arrays.
Unlike otheriterative methods,reduceRight() does not accept athisArg argument.callbackFn is always called withundefined asthis, which gets substituted withglobalThis ifcallbackFn is non-strict.
ThereduceRight() method isgeneric. It only expects thethis value to have alength property and integer-keyed properties.
All caveats aboutreduce discussed inwhen to not use reduce() apply toreduceRight as well. Because JavaScript has no lazy evaluation semantics, there is no performance difference betweenreduce andreduceRight.
Examples
>How reduceRight() works without an initial value
The call to the reduceRightcallbackFn would look something like this:
arr.reduceRight((accumulator, currentValue, index, array) => { // …});The first time the function is called, theaccumulator andcurrentValue can be one of two values. If aninitialValue was provided in the call toreduceRight, thenaccumulator will be equal toinitialValue andcurrentValue will be equal to the last value in the array. If noinitialValue was provided, thenaccumulator will be equal to the last value in the array andcurrentValue will be equal to the second-to-last value.
If the array is empty and noinitialValue was provided,TypeError would be thrown. If the array has only one element (regardless of position) and noinitialValue was provided, or ifinitialValue is provided but the array is empty, the solo value would be returned without callingcallbackFn.
Some example run-throughs of the function would look like this:
[0, 1, 2, 3, 4].reduceRight( (accumulator, currentValue, index, array) => accumulator + currentValue,);The callback would be invoked four times, with the arguments and return values in each call being as follows:
accumulator | currentValue | index | Return value | |
|---|---|---|---|---|
| First call | 4 | 3 | 3 | 7 |
| Second call | 7 | 2 | 2 | 9 |
| Third call | 9 | 1 | 1 | 10 |
| Fourth call | 10 | 0 | 0 | 10 |
Thearray parameter never changes through the process — it's always[0, 1, 2, 3, 4]. The value returned byreduceRight would be that of the last callback invocation (10).
How reduceRight() works with an initial value
Here we reduce the same array using the same algorithm, but with aninitialValue of10 passed as the second argument toreduceRight():
[0, 1, 2, 3, 4].reduceRight( (accumulator, currentValue, index, array) => accumulator + currentValue, 10,);accumulator | currentValue | index | Return value | |
|---|---|---|---|---|
| First call | 10 | 4 | 4 | 14 |
| Second call | 14 | 3 | 3 | 17 |
| Third call | 17 | 2 | 2 | 19 |
| Fourth call | 19 | 1 | 1 | 20 |
| Fifth call | 20 | 0 | 0 | 20 |
The value returned byreduceRight this time would be, of course,20.
Sum up all values within an array
const sum = [0, 1, 2, 3].reduceRight((a, b) => a + b);// sum is 6Run a list of asynchronous functions with callbacks in series each passing their results to the next
const waterfall = (...functions) => (callback, ...args) => functions.reduceRight( (composition, fn) => (...results) => fn(composition, ...results), callback, )(...args);const randInt = (max) => Math.floor(Math.random() * max);const add5 = (callback, x) => { setTimeout(callback, randInt(1000), x + 5);};const mul3 = (callback, x) => { setTimeout(callback, randInt(1000), x * 3);};const sub2 = (callback, x) => { setTimeout(callback, randInt(1000), x - 2);};const split = (callback, x) => { setTimeout(callback, randInt(1000), x, x);};const add = (callback, x, y) => { setTimeout(callback, randInt(1000), x + y);};const div4 = (callback, x) => { setTimeout(callback, randInt(1000), x / 4);};const computation = waterfall(add5, mul3, sub2, split, add, div4);computation(console.log, 5); // Logs 14// same as:const computation2 = (input, callback) => { const f6 = (x) => div4(callback, x); const f5 = (x, y) => add(f6, x, y); const f4 = (x) => split(f5, x); const f3 = (x) => sub2(f4, x); const f2 = (x) => mul3(f3, x); add5(f2, input);};Difference between reduce and reduceRight
const a = ["1", "2", "3", "4", "5"];const left = a.reduce((prev, cur) => prev + cur);const right = a.reduceRight((prev, cur) => prev + cur);console.log(left); // "12345"console.log(right); // "54321"Defining composable functions
Function composition is a mechanism for combining functions, in which the output of each function is passed into the next one, and the output of the last function is the final result. In this example we usereduceRight() to implement function composition.
See alsoFunction composition on Wikipedia.
const compose = (...args) => (value) => args.reduceRight((acc, fn) => fn(acc), value);// Increment passed numberconst inc = (n) => n + 1;// Doubles the passed valueconst double = (n) => n * 2;// using composition functionconsole.log(compose(double, inc)(2)); // 6// using composition functionconsole.log(compose(inc, double)(2)); // 5Using reduceRight() with sparse arrays
reduceRight() skips missing elements in sparse arrays, but it does not skipundefined values.
console.log([1, 2, , 4].reduceRight((a, b) => a + b)); // 7console.log([1, 2, undefined, 4].reduceRight((a, b) => a + b)); // NaNCalling reduceRight() on non-array objects
ThereduceRight() method reads thelength property ofthis and then accesses each property whose key is a nonnegative integer less thanlength.
const arrayLike = { length: 3, 0: 2, 1: 3, 2: 4, 3: 99, // ignored by reduceRight() since length is 3};console.log(Array.prototype.reduceRight.call(arrayLike, (x, y) => x - y));// -1, which is 4 - 3 - 2Specifications
| Specification |
|---|
| ECMAScript® 2026 Language Specification> # sec-array.prototype.reduceright> |