If you're here in 2024 (or later), here's an updated blog post!](https://lydiahallie.com/blog/event-loop)

Oh boi the event loop. It’s one of those things that every JavaScript developer has to deal with in one way or another, but it can be a bit confusing to understand at first. I’m a visual learner so I thought I’d try to help you by explaining it in a visual way through low-res gifs because it's 2019 and gifs are somehow still pixelated and blurry.

But first, what is the event loop and why should you care?

JavaScript issingle-threaded: only one task can run at a time. Usually that’s no big deal, but now imagine you’re running a task which takes 30 seconds.. Ya.. During that task we’re waiting for 30 seconds before anything else can happen (JavaScript runs on the browser’s main thread by default, so the entire UI is stuck) 😬 It’s 2019, no one wants a slow, unresponsive website.

Luckily, the browser gives us some features that the JavaScript engine itself doesn’t provide: a Web API. This includes the DOM API,setTimeout, HTTP requests, and so on. This can help us create some async, non-blocking behavior 🚀

When we invoke a function, it gets added to something called the call stack. The call stack is part of the JS engine, this isn’t browser specific. It’s a stack, meaning that it’s first in, last out (think of a pile of pancakes). When a function returns a value, it gets popped off the stack 👋

Therespond function returns asetTimeout function. ThesetTimeout is provided to us by the Web API: it lets us delay tasks without blocking the main thread. The callback function that we passed to thesetTimeout function, the arrow function() => { return'Hey' } gets added to the Web API. In the meantime, thesetTimeout function and the respond function get popped off the stack, they both returned their values!

In the Web API, a timer runs for as long as the second argument we passed to it, 1000ms. The callback doesn’t immediately get added to the call stack, instead it’s passed to something called the queue.

This can be a confusing part: it doesn't mean that the callback function gets added to the callstack(thus returns a value) after 1000ms! It simply gets added to thequeue after 1000ms. But it’s a queue, the function has got to wait for its turn!

Now this is the part we’ve all been waiting for… Time for the event loop to do its only task:connecting the queue with the call stack! If the call stack isempty, so if all previously invoked functions have returned their values and have been popped off the stack, thefirst item in the queue gets added to the call stack. In this case, no other functions were invoked, meaning that the call stack was empty by the time the callback function was the first item in the queue.

The callback is added to the call stack, gets invoked, and returns a value, and gets popped off the stack.

Reading an article is fun, but you'll only get entirely comfortable with this by actually working with it over and over. Try to figure out what gets logged to the console if we run the following:

constfoo=()=>console.log("First");constbar=()=>setTimeout(()=>console.log("Second"),500);constbaz=()=>console.log("Third");bar();foo();baz();

Got it? Let's quickly take a look at what's happening when we're running this code in a browser:

1. We invokebar.bar returns asetTimeout function.
2. The callback we passed tosetTimeout gets added to the Web API, thesetTimeout function andbar get popped off the callstack.
3. The timer runs, in the meantimefoo gets invoked and logsFirst.foo returns (undefined),baz gets invoked, and the callback gets added to the queue.
4. baz logsThird. The event loop sees the callstack is empty afterbaz returned, after which the callback gets added to the call stack.
5. The callback logsSecond.

Hope that this makes you feel a bit more comfortable with the event loop! Don't worry if it still seems confusing, the most important thing is tounderstand where certain errors/behavior can come from in order toGoogle the right terms efficiently and end up on the correct Stack Overflow page 💪🏼 Feel free to reach out to me if you have any questions!