List Comprehension:
It's a syntactically elegant method to create or manipulate lists in a single line of code.
Write a program to print the fruits contains letter 'a'(using for loop):
fruits = ["apple", "banana", "cherry", "kiwi", "mango"]newlist = []for x in fruits: if "a" in x: newlist.append(x)print(newlist)['apple', 'banana', 'mango'](Using list comprehension):
fruits = ["apple", "banana", "cherry", "kiwi", "mango"]newlist = [x for x in fruits if "a" in x]print(newlist)['apple', 'banana', 'mango']Write a program to find the square root of given number:
l = [10,20,30,40]newlist = []#using for loopfor num in l: newlist.append(num**2)print(newlist)#using loop in comprehensive waynewlist = [num**2 for num in l]print(newlist)[100, 400, 900, 1600][100, 400, 900, 1600]Find similar numbers from 2 lists and different numbers from the same 2 lists:
l1 = [10,20,30,40]l2 = [30,40,50,60]#for loopfor num in l1: for no in l2: if num== no: print(num,end=' ')#comprehensiveprint([num for num in l1 for no in l2 if num==no])30 40 [30, 40]1 = [10,20,30,40]l2 = [30,40,50,60]#comprehensiveoutput = [num for num in l1 if num not in l2]output = output + [num for num in l2 if num not in l1]print(output)#for loopfor num in l1: if num not in l2: print(num,end=' ')for num in l2: if num not in l1: print(num,end=' ')[10, 20, 50, 60]10 20 50 60Write a program for the given output in comprehensive approach:
l1 = [1,2,3]
l2 = [5,6,7]
Output:[(1, 5), (1, 6), (1, 7), (2, 5), (2, 6), (2, 7), (3, 5), (3, 6), (3, 7)]
l1 = [1,2,3]l2 = [5,6,7]l = [(i,j) for i in l1 for j in l2 if i!=j]print(l)[(1, 5), (1, 6), (1, 7), (2, 5), (2, 6), (2, 7), (3, 5), (3, 6), (3, 7)]Write a program for the given output:
s = "a1b2c3"
output: abc123
Method:1
s= "a1b2c3"alpha_list = []num_list = []for letter in s: if letter.isalpha(): alpha_list.append(letter) else: num_list.append(letter)print("".join(alpha_list+num_list))Method:2
s = "a1b2c3"letter=''.join([i for i in s if i.isalpha()])no=''.join([i for i in s if i.isdigit()])print(letter+no)abc123Write a program for the given output:
s = "a4k3b2"
output: aeknbd
s = "a4k3b2"i = 0 while i<len(s): first = s[i] second = int(s[i+1]) print(first, chr(ord(first)+second),sep='',end='') i+=2aeknbdTask:
1) Write a program to get the output 'abbbbklllbcc'
s = "a4k3b2"i = 0while i < len(s): first = s[i] second =int(s[i + 1]) print(first,chr(ord(first)+1)*second,sep='',end='') i+=2abbbbklllbcc2) Write a program to get the output 'aaaaakkkkbbb'
s = "a4k3b2"i = 0while i < len(s): first = s[i] second =int(s[i + 1]) print(first,chr(ord(first))*second,sep='',end='') i+=2aaaaakkkkbbb3.Join the given matrix into single list using comprehensive for and normal for loop.
Method:1(Using for loop)
matrix = [[10,20,30], [40,50,60], [70,80,90]]output=[]for i in matrix: for j in i: output.append(j)print(output)Method:2(Using comprehensive for loop)
matrix = [[10, 20, 30], [40, 50, 60], [70, 80, 90]]output = [j for i in matrix for j in i]print(output)[10, 20, 30, 40, 50, 60, 70, 80, 90]4.l = ['ABC','DEF', 'GHI', 'JKL']
Get OUTPUT: ['ABC', 'def','GHI', 'jkl']
l = ['ABC', 'DEF', 'GHI', 'JKL']output = [] for i, alpha in enumerate(l): if i % 2 != 0: output.append(alpha.casefold()) else: output.append(alpha)print(output)['ABC', 'def', 'GHI', 'jkl']5.Find the row wise total for the given matrix:
matrix = [[10,20,30], [40,50,60], [70,80,90]]for inner in matrix: total = 0 for index,num in enumerate(inner): total+=num print(total,end=' ')60 150 240Top comments(0)
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