This is my given array

const arr=[1,2,6,4,5]

• You need traverse through array from the index 1

• In each loop check the current element (arr[i]) with previous element

• if current element is greater than previous element then continue with loop else break the loop over there

In the first loop

current element is greater than previous element so you can continue with the loop

In the second loop

current element is greater than previous element so you can continue with the loop

In the third loop

current element is lesser than previous element so break the loop

Solution to check array is sorted or not in javascript

let checkSort = truefor(let i=1;i<arr.length;i++){  if(arr[i] < arr[i-1]]){    checkSort=false;    break;  }}if(checkSort){  console.log("Array is Sorted")}else{  console.log("Array is not sorted)}