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std::sort_heapSection: 26.8.8.5[sort.heap]Status:C++20Submitter: François DumontOpened: 2014-10-07Last modified: 2021-02-25
Priority:3
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Discussion:
While creating complexity tests for the GNU libstdc++ implementationI stumbled across a surprising requirement for thestd::sort_heap algorithm.
Complexity: At most
N log(N)comparisons (whereN == last - first).
As stated on the libstdc++ mailing list by Marc Glissesort_heap can be implemented byN calls topop_heap. As max number of comparisons ofpop_heap is2 * log(N) thensort_heap max limit should be2 * log(1) + 2 * log(2) + .... + 2 * log(N) that is to say2 * log(N!). In terms oflog(N) we can also consider that this limit is also cap by2 *N * log(N) which is surely what the Standard wanted to set as a limit.
Complexity: At most
2N log(N)comparisons (whereN == last - first).
[2015-02 Cologne]
Marshall will research the maths and report back in Lenexa.
[2015-05-06 Lenexa]
STL: I dislike exact complexity requirements, they prevent one or two extra checks in debug mode. Would it be better to say O(N log(N)) not at most?
[2017-03-04, Kona]
Move to Tentatively Ready. STL may write a paper (with Thomas & Robert) offering guidance about Big-O notation vs. exact requirements.
Proposed resolution:
This wording is relative to N3936.
In 26.8.8.5[sort.heap] p3 the Standard states:
template<class RandomAccessIterator> void sort_heap(RandomAccessIterator first, RandomAccessIterator last);template<class RandomAccessIterator, class Compare> void sort_heap(RandomAccessIterator first, RandomAccessIterator last, Compare comp);[…]
-3-Complexity: At most2N log(N)comparisons (whereN == last - first).