Is my implementation of quicksort efficient, in-place, pythonic ?
def quicksort(array, lo, hi): if hi - lo < 2: return key = random.randrange(lo, hi) array[key], array[lo] = array[lo], array[key] y = 1 + lo for x in xrange(lo + 1, hi): if array[x] <= array[lo]: array[x], array[y] = array[y], array[x] y += 1 array[lo], array[y - 1] = array[y - 1], array[lo] quicksort(array, lo, y - 1) quicksort(array, y, hi)a = map(int, raw_input().split())quicksort(a, 0, len(a))2 Answers2
Consider your partition method
for x in xrange(lo + 1, hi): if array[x] <= array[lo]: array[x], array[y] = array[y], array[x] y += 1Abstracted out it looks something like this.
def partition(array, lo, hi, pivot): y = lo for x in xrange(lo, hi): if array[x] <= pivot: array[x], array[y] = array[y], array[x] y += 1 return y# egpivot = partition(array, lo + 1, hi, array[lo])array[lo], array[pivot] = array[pivot], array[lo]That struck me as an odd partition method. It's not the one I learned yet it is simpler and seems to work. When searching for an example I came acrossthis question on cs.exchange. You should read the very detailed answer and consider using the Hoare partition as it always slightly more efficient.
Also you should consider implementing a separate swap method. The idiom you use is perfectly fine it just gets verbose and you use it often enough
def swap_indexes(array, a, b): array[a], array[b] = array[b], array[a]- \$\begingroup\$yes, it does a lot of swaps, especially when encountered a max element.\$\endgroup\$eightnoteight– eightnoteight2014-09-25 12:11:06 +00:00CommentedSep 25, 2014 at 12:11
Looks good in general. Few comments.
Missing
import random.Random pivot selection is just one of many possible strategies. It may or may not be a good strategy depending on the nature of data. Only the client knows what a suitable strategy will be; let him chose.
No Raw Loops mantra: Every loop possible represents an algorithm, often very important itself. In this case the algorithm is
partition. It is worthy to be factored out in a function of its own.
- \$\begingroup\$No Raw Loops mantra +1.... and about the second comment, if it is random data, does it make any difference if i took 3 random pivots and finalized the median of pivots as final pivot?\$\endgroup\$eightnoteight– eightnoteight2014-09-25 12:15:57 +00:00CommentedSep 25, 2014 at 12:15
- \$\begingroup\$Forpurely random data it makes no difference.\$\endgroup\$vnp– vnp2014-09-25 16:44:24 +00:00CommentedSep 25, 2014 at 16:44
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