The current code of PyThread_acquire_lock_timed() (the implementation not using semaphore) doesn't compute correctly the timeout when pthread_cond_timedwait() is interrupted by a signal. We should recompute the timeout using a deadline.Something like select.select():if (tvp)    deadline = _PyTime_GetMonotonicClock() + timeout;do {    ... use tvp    if (errno != EINTR)        break;    /* select() was interrupted by a signal */    if (PyErr_CheckSignals())        goto finally;    if (tvp) {        timeout = deadline - _PyTime_GetMonotonicClock();        if (timeout < 0) {            n = 0;            break;        }        _PyTime_AsTimeval_noraise(timeout, &tv, _PyTime_ROUND_CEILING);        /* retry select() with the recomputed timeout */    }} while (1);

See also the oldbpo-12822: "NewGIL should use CLOCK_MONOTONIC if possible.".

See also thePEP 475 "Retry system calls failing with EINTR" andPEP 418 (time.monotonic).

interrupted_lock.py: test threading.Lock.acquire(timeout=1.0) with SIGALRM sent every 1 ms (so up to 1000 times in total). Example:haypo@selma$ ./python interrupted_lock.py acquire(timeout=1.0) took 1.0 seconds and got 1000 signalsOh, in fact, threading.Lock.acquire(timeout=1.0) already recomputes the timeout when interrupted.In Python stdlib, PyThread_acquire_lock_timed() is only called from one place with intr_flag=0: faulthandler watchdog thread, but this thread blocks all signals:    /* we don't want to receive any signal */    sigfillset(&set);    pthread_sigmask(SIG_SETMASK, &set, NULL);

Ah, I found another caller of PyThread_acquire_lock_timed() with a timeout > 0 and intr_flag=0: _enter_buffered_busy() ofModules/_io/bufferedio.c:        /* When finalizing, we don't want a deadlock to happen with daemon         * threads abruptly shut down while they owned the lock.         * Therefore, only wait for a grace period (1 s.).         * Note that non-daemon threads have already exited here, so this         * shouldn't affect carefully written threaded I/O code.         */        st = PyThread_acquire_lock_timed(self->lock, (PY_TIMEOUT_T)1e6, 0);

I wrotePR 4103 to fix the pthread+semaphore implementation of PyThread_acquire_lock_timed().ApplyPR 4103, apply attached test.patch, recompile Python, and run interrupted_lock.py to test the PR. Result:haypo@selma$ ./python interrupted_lock.py acquire(timeout=1.0) took 1.0 seconds and got 911 signals

To check if you are using pthread+semaphore, use:haypo@selma$ ./python -c 'import sys; print(sys.thread_info)'sys.thread_info(name='pthread', lock='semaphore', version='NPTL 2.25')Here you have pthread+semaphore. It's Fedora 26 running Linux kernel 4.13.

New changeset850a18e03e8f8309bc8c39adc6e7d51a4568cd9a by Victor Stinner in branch 'master':bpo-30768: Recompute timeout on interrupted lock (GH-4103)https://github.com/python/cpython/commit/850a18e03e8f8309bc8c39adc6e7d51a4568cd9a

I merged my PR. Thanks Antoine Pitrou for the review!This change only impacts the io.BufferedWriter and io.BufferedReader during Python finalization. It has no effect on theading.Lock.acquire(). It might impact faulthandler.dump_traceback_later(), but in practice, it shouldn't change anything since the internal faulthandler watchdog thread blocks all signals.If I understand correctly, if the system clock is stepped back by 1 hour during Python finalization, after PyThread_acquire_lock_timed() computed the deadline, but before sem_timedwait() completed, _enter_buffered_busy() can be blocked during 1 hour.Moving the system clock backward by 1 hour occurs once a year on the DST change. But the race condition is unlikely since the size of the time window is only 1 second. The DST change should occur at Python shutdown when an io.BufferedReader or io.BufferedWriter is used.Since the race condition seems very unlikely and was never reported by another user, I propose to not backward this change. Moreover, I'm not confident to modify locks in a stable release :-)

Oh, the pthread condvar+mutex implementation still has the bug, so I reopen the issue.