I have to input 5 words and organize.In order to organize words, I have to get them into Array of String to compare.I succeed to getchar[buffer] intoString in_str but somehowin_str doesn't get intostr[5].isString str[i]=in_str; Wrong?? How can I putin_str to Array ofString str??
void setup() { Serial.begin(9600); }void loop() { int state = 1, len = 0 ,i=0, k=1; char buffer[128]; String str[5]; while (true) { if (state == 1) { Serial.print("Enter the "); Serial.print(k); Serial.print("th Word --> "); state = 2; } while (Serial.available()) { char data = Serial.read(); if (data == '\n') { buffer[len] = '\0'; String in_str = buffer; String str[i]=in_str; Serial.println(in_str); i=i+1; k=k+1; len = 0; if(i>4){state = 3; } else {state = 1;} break; } buffer[len++] = data; } if(state==3){ Serial.println("After Sorting"); for (int i = 0; i < 4; i++) { for (int j = i + 1; j < 5; j++) { int compare = str[i].compareTo(str[j]); if (compare > 0) { String temp = str[i]; str[i] = str[j]; str[j] = temp; } } } for (int i = 0; i < 5; i++) { Serial.println(String(i) + " : " + str[i]); } break; } }}
1 Answer1
When you writeString str[i]=in_str; that is wrong. You only write the type when you are declaring the variable, once.
When assigning, you need only write the variable name, not the type:str[i]=in_str;
- I thought like hours to solve this problem but this was a simple mistake.. thanks for your helpTaeHyeong Kim– TaeHyeong Kim2018-03-29 14:41:52 +00:00CommentedMar 29, 2018 at 14:41
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