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Kepler orbit

From Wikipedia, the free encyclopedia
Celestial orbit whose trajectory is a conic section in the orbital plane

For broader coverage of this topic, seeOrbit.
An elliptic Kepler orbit with an eccentricity of 0.7, a parabolic Kepler orbit and a hyperbolic Kepler orbit with an eccentricity of 1.3. The distance to the focal point is a function of the polar angle relative to the horizontal line as given by the equation (13)

Incelestial mechanics, aKepler orbit (orKeplerian orbit, named after the German astronomerJohannes Kepler) is the motion of one body relative to another, as anellipse,parabola, orhyperbola, which forms a two-dimensionalorbital plane in three-dimensional space. A Kepler orbit can also form astraight line. It considers only the point-like gravitational attraction of two bodies, neglectingperturbations due to gravitational interactions with other objects,atmospheric drag,solar radiation pressure, a non-spherical central body, and so on. It is thus said to be a solution of a special case of thetwo-body problem, known as theKepler problem. As a theory inclassical mechanics, it also does not take into account the effects ofgeneral relativity. Keplerian orbits can beparametrized into sixorbital elements in various ways.

In most applications, there is a large central body, the center of mass of which is assumed to be the center of mass of the entire system. By decomposition, the orbits of two objects of similar mass can be described as Kepler orbits around their common center of mass, theirbarycenter.

Introduction

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From ancient times until the 16th and 17th centuries, the motions of the planets were believed to follow perfectly circulargeocentric paths as taught by the ancient Greek philosophersAristotle andPtolemy. Variations in the motions of the planets were explained by smaller circular paths overlaid on the larger path (seeepicycle). As measurements of the planets became increasingly accurate, revisions to the theory were proposed. In 1543,Nicolaus Copernicus published aheliocentric model of theSolar System, although he still believed that the planets traveled in perfectly circular paths centered on the Sun.[1]

Development of the laws

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In 1601,Johannes Kepler acquired the extensive, meticulous observations of the planets made byTycho Brahe. Kepler would spend the next five years trying to fit the observations of the planetMars to various curves. In 1609, Kepler published the first two of his threelaws of planetary motion. The first law states:

Theorbit of every planet is anellipse with the sun at afocus.

More generally, the path of an object undergoing Keplerian motion may also follow aparabola or ahyperbola, which, along with ellipses, belong to a group of curves known asconic sections. Mathematically, the distance between a central body and an orbiting body can be expressed as:

r(θ)=a(1e2)1+ecos(θ){\displaystyle r(\theta )={\frac {a(1-e^{2})}{1+e\cos(\theta )}}}

where:

Alternately, the equation can be expressed as:

r(θ)=p1+ecos(θ){\displaystyle r(\theta )={\frac {p}{1+e\cos(\theta )}}}

Wherep{\displaystyle p} is called thesemi-latus rectum of the curve. This form of the equation is particularly useful when dealing with parabolic trajectories, for which the semi-major axis is infinite.

Despite developing these laws from observations, Kepler was never able to develop a theory to explain these motions.[2] Isaac Newton produced the first such theory based around the concept ofgravity.Albert Einstein'sgeneral relativity is the current description of gravitation in modern physics. Thetwo-body problem in general relativity has no closed-form solutions.

Isaac Newton

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Between 1665 and 1666,Isaac Newton developed several concepts related to motion, gravitation and differential calculus. However, these concepts were not published until 1687 in thePrincipia, in which he outlined hislaws of motion and hislaw of universal gravitation. His second of his three laws of motion states:

Theacceleration of a body is parallel and directly proportional to the netforce acting on the body, is in the direction of the net force, and is inversely proportional to themass of the body:

F=ma=md2rdt2{\displaystyle \mathbf {F} =m\mathbf {a} =m{\frac {d^{2}\mathbf {r} }{dt^{2}}}}

Where:

Strictly speaking, this form of the equation only applies to an object of constant mass, which holds true based on the simplifying assumptions made below.

The mechanisms of Newton's law of universal gravitation; a point massm1 attracts another point massm2 by a forceF2 which is proportional to the product of the two masses and inversely proportional to the square of the distance (r) between them. Regardless of masses or distance, the magnitudes of |F1| and |F2| will always be equal.G is thegravitational constant.

Newton's law of gravitation states:

Everypoint mass attracts every other point mass by aforce pointing along the line intersecting both points. The force isproportional to the product of the two masses and inversely proportional to the square of the distance between the point masses:

F=Gm1m2r2{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}}

where:

From the laws of motion and the law of universal gravitation, Newton was able to derive Kepler's laws, which are specific to orbital motion in astronomy. Since Kepler's laws were well-supported by observation data, this consistency provided strong support of the validity of Newton's generalized theory, and unified celestial and ordinary mechanics. These laws of motion formed the basis of moderncelestial mechanics untilAlbert Einstein introduced the concepts ofspecial andgeneral relativity in the early 20th century. For most applications, Keplerian motion approximates the motions of planets and satellites to relatively high degrees of accuracy and is used extensively inastronomy andastrodynamics.

Simplified two body problem

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See also:Orbit § Newtonian analysis of orbital motion

To solve for the motion of an object in atwo body system, two simplifying assumptions can be made:

  1. The bodies are spherically symmetric and can be treated as point masses.
  2. There are no external or internal forces acting upon the bodies other than their mutual gravitation.

The shapes of large celestial bodies are close to spheres. By symmetry, the net gravitational force attracting a mass point towards a homogeneous sphere must be directed towards its centre. Theshell theorem (also proven by Isaac Newton) states that the magnitude of this force is the same as if all mass was concentrated in the middle of the sphere, even if the density of the sphere varies with depth (as it does for most celestial bodies). From this immediately follows that the attraction between two homogeneous spheres is as if both had its mass concentrated to its center.

Smaller objects, likeasteroids orspacecraft often have a shape strongly deviating from a sphere. But the gravitational forces produced by these irregularities are generally small compared to the gravity of the central body. The difference between an irregular shape and a perfect sphere also diminishes with distances, and most orbital distances are very large when compared with the diameter of a small orbiting body. Thus for some applications, shape irregularity can be neglected without significant impact on accuracy. This effect is quite noticeable for artificial Earth satellites, especially those in low orbits.

Planets rotate at varying rates and thus may take a slightly oblate shape because of the centrifugal force. With such an oblate shape, the gravitational attraction will deviate somewhat from that of a homogeneous sphere. At larger distances the effect of this oblateness becomes negligible. Planetary motions in the Solar System can be computed with sufficient precision if they are treated as point masses.

Two point mass objects with massesm1{\displaystyle m_{1}} andm2{\displaystyle m_{2}} and position vectorsr1{\displaystyle \mathbf {r} _{1}} andr2{\displaystyle \mathbf {r} _{2}} relative to someinertial reference frame experience gravitational forces:

m1r¨1=Gm1m2r2r^{\displaystyle m_{1}{\ddot {\mathbf {r} }}_{1}={\frac {-Gm_{1}m_{2}}{r^{2}}}\mathbf {\hat {r}} }m2r¨2=Gm1m2r2r^{\displaystyle m_{2}{\ddot {\mathbf {r} }}_{2}={\frac {Gm_{1}m_{2}}{r^{2}}}\mathbf {\hat {r}} }

wherer{\displaystyle \mathbf {r} } is the relative position vector of mass 1 with respect to mass 2, expressed as:

r=r1r2{\displaystyle \mathbf {r} =\mathbf {r} _{1}-\mathbf {r} _{2}}

andr^{\displaystyle \mathbf {\hat {r}} } is theunit vector in that direction andr{\displaystyle r} is thelength of that vector.

Dividing by their respective masses and subtracting the second equation from the first yields the equation of motion for the acceleration of the first object with respect to the second:

r¨=αr2r^{\displaystyle {\ddot {\mathbf {r} }}=-{\frac {\alpha }{r^{2}}}\mathbf {\hat {r}} }1

whereα{\displaystyle \alpha } is the gravitational parameter and is equal to

α=G(m1+m2){\displaystyle \alpha =G(m_{1}+m_{2})}

In many applications, a third simplifying assumption can be made:

  1. When compared to the central body, the mass of the orbiting body is insignificant. Mathematically,m1 >>m2, soα =G (m1 +m2) ≈Gm1. Suchstandard gravitational parameters, often denoted asμ=GM{\displaystyle \mu =G\,M}, are widely available for Sun, major planets and Moon, which have much larger massesM{\displaystyle M} than their orbiting satellites.

This assumption is not necessary to solve the simplified two body problem, but it simplifies calculations, particularly with Earth-orbiting satellites and planets orbiting the Sun. EvenJupiter's mass is less than the Sun's by a factor of 1047,[3] which would constitute an error of 0.096% in the value of α. Notable exceptions include the Earth-Moon system (mass ratio of 81.3), the Pluto-Charon system (mass ratio of 8.9) and binary star systems.

Under these assumptions the differential equation for the two body case can be completely solved mathematically and the resulting orbit which follows Kepler's laws of planetary motion is called a "Kepler orbit". The orbits of all planets are to high accuracy Kepler orbits around the Sun. The small deviations are due to the much weaker gravitational attractions between the planets, and in the case ofMercury, due togeneral relativity. The orbits of the artificial satellites around the Earth are, with a fair approximation, Kepler orbits with small perturbations due to the gravitational attraction of the Sun, the Moon and the oblateness of the Earth. In high accuracy applications for which the equation of motion must be integrated numerically with all gravitational and non-gravitational forces (such assolar radiation pressure andatmospheric drag) being taken into account, the Kepler orbit concepts are of paramount importance and heavily used.

Keplerian elements

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Keplerianorbital elements.
Main article:Keplerian elements

Any Keplerian trajectory can be defined by six parameters. The motion of an object moving in three-dimensional space is characterized by a position vector and a velocity vector. Each vector has three components, so the total number of values needed to define a trajectory through space is six. An orbit is generally defined by six elements (known asKeplerian elements) that can be computed from position and velocity, three of which have already been discussed. These elements are convenient in that of the six, five are unchanging for an unperturbed orbit (a stark contrast to two constantly changing vectors). The future location of an object within its orbit can be predicted and its new position and velocity can be easily obtained from the orbital elements.

Two define the size and shape of the trajectory:

Three define the orientation of theorbital plane:

And finally:

Becausei{\displaystyle i},Ω{\displaystyle \Omega } andω{\displaystyle \omega } are simply angular measurements defining the orientation of the trajectory in the reference frame, they are not strictly necessary when discussing the motion of the object within the orbital plane. They have been mentioned here for completeness, but are not required for the proofs below.

Mathematical solution of the differential equation (1) above

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For movement under any central force, i.e. a force parallel tor, thespecific relative angular momentumH=r×r˙{\displaystyle \mathbf {H} =\mathbf {r} \times {\dot {\mathbf {r} }}} stays constant:H˙=ddt(r×r˙)=r˙×r˙+r×r¨=0+0=0{\displaystyle {\dot {\mathbf {H} }}={\frac {d}{dt}}\left(\mathbf {r} \times {\dot {\mathbf {r} }}\right)={\dot {\mathbf {r} }}\times {\dot {\mathbf {r} }}+\mathbf {r} \times {\ddot {\mathbf {r} }}=\mathbf {0} +\mathbf {0} =\mathbf {0} }

Since the cross product of the position vector and its velocity stays constant, they must lie in the same plane, orthogonal toH{\displaystyle \mathbf {H} }. This implies the vector function is aplane curve.

Because the equation has symmetry around its origin, it is easier to solve in polar coordinates. However, it is important to note that equation (1) refers to linear acceleration(r¨),{\displaystyle \left({\ddot {\mathbf {r} }}\right),} as opposed to angular(θ¨){\displaystyle \left({\ddot {\theta }}\right)} or radial(r¨){\displaystyle \left({\ddot {r}}\right)} acceleration. Therefore, one must be cautious when transforming the equation.Introducing a cartesian coordinate system(x^,y^){\displaystyle ({\hat {\mathbf {x} }},{\hat {\mathbf {y} }})} andpolar unit vectors(r^,q^){\displaystyle ({\hat {\mathbf {r} }},{\hat {\mathbf {q} }})} in the plane orthogonal toH{\displaystyle \mathbf {H} }:

r^=cosθx^+sinθy^q^=sinθx^+cosθy^{\displaystyle {\begin{aligned}{\hat {\mathbf {r} }}&=\cos {\theta }{\hat {\mathbf {x} }}+\sin {\theta }{\hat {\mathbf {y} }}\\{\hat {\mathbf {q} }}&=-\sin {\theta }{\hat {\mathbf {x} }}+\cos {\theta }{\hat {\mathbf {y} }}\end{aligned}}}

We can now rewrite the vector functionr{\displaystyle \mathbf {r} } and its derivatives as:

r=r(cosθx^+sinθy^)=rr^r˙=r˙r^+rθ˙q^r¨=(r¨rθ˙2)r^+(rθ¨+2r˙θ˙)q^{\displaystyle {\begin{aligned}\mathbf {r} &=r\left(\cos \theta {\hat {\mathbf {x} }}+\sin \theta {\hat {\mathbf {y} }}\right)=r{\hat {\mathbf {r} }}\\{\dot {\mathbf {r} }}&={\dot {r}}{\hat {\mathbf {r} }}+r{\dot {\theta }}{\hat {\mathbf {q} }}\\{\ddot {\mathbf {r} }}&=\left({\ddot {r}}-r{\dot {\theta }}^{2}\right){\hat {\mathbf {r} }}+\left(r{\ddot {\theta }}+2{\dot {r}}{\dot {\theta }}\right){\hat {\mathbf {q} }}\end{aligned}}}

(see "Vector calculus"). Substituting these into (1), we find:(r¨rθ˙2)r^+(rθ¨+2r˙θ˙)q^=(αr2)r^+(0)q^{\displaystyle \left({\ddot {r}}-r{\dot {\theta }}^{2}\right){\hat {\mathbf {r} }}+\left(r{\ddot {\theta }}+2{\dot {r}}{\dot {\theta }}\right){\hat {\mathbf {q} }}=\left(-{\frac {\alpha }{r^{2}}}\right){\hat {\mathbf {r} }}+(0){\hat {\mathbf {q} }}}

This gives the ordinary differential equation in the two variablesr{\displaystyle r} andθ{\displaystyle \theta }:

r¨rθ˙2=αr2{\displaystyle {\ddot {r}}-r{\dot {\theta }}^{2}=-{\frac {\alpha }{r^{2}}}}2

In order to solve this equation, all time derivatives must be eliminated. This brings:H=|r×r˙|=|(rcos(θ)rsin(θ)0)×(r˙cos(θ)rsin(θ)θ˙r˙sin(θ)+rcos(θ)θ˙0)|=|(00r2θ˙)|=r2θ˙{\displaystyle H=|\mathbf {r} \times {\dot {\mathbf {r} }}|=\left|{\begin{pmatrix}r\cos(\theta )\\r\sin(\theta )\\0\end{pmatrix}}\times {\begin{pmatrix}{\dot {r}}\cos(\theta )-r\sin(\theta ){\dot {\theta }}\\{\dot {r}}\sin(\theta )+r\cos(\theta ){\dot {\theta }}\\0\end{pmatrix}}\right|=\left|{\begin{pmatrix}0\\0\\r^{2}{\dot {\theta }}\end{pmatrix}}\right|=r^{2}{\dot {\theta }}}

θ˙=Hr2{\displaystyle {\dot {\theta }}={\frac {H}{r^{2}}}}3

Taking the time derivative of (3) gets

θ¨=2Hr˙r3{\displaystyle {\ddot {\theta }}=-{\frac {2\cdot H\cdot {\dot {r}}}{r^{3}}}}4

Equations (3) and (4) allow us to eliminate the time derivatives ofθ{\displaystyle \theta }. In order to eliminate the time derivatives ofr{\displaystyle r}, the chain rule is used to find appropriate substitutions:

r˙=drdθθ˙{\displaystyle {\dot {r}}={\frac {dr}{d\theta }}\cdot {\dot {\theta }}}5
r¨=d2rdθ2θ˙2+drdθθ¨{\displaystyle {\ddot {r}}={\frac {d^{2}r}{d\theta ^{2}}}\cdot {\dot {\theta }}^{2}+{\frac {dr}{d\theta }}\cdot {\ddot {\theta }}}6

Using these four substitutions, all time derivatives in (2) can be eliminated, yielding anordinary differential equation forr{\displaystyle r} as function ofθ.{\displaystyle \theta .}r¨rθ˙2=αr2{\displaystyle {\ddot {r}}-r{\dot {\theta }}^{2}=-{\frac {\alpha }{r^{2}}}}d2rdθ2θ˙2+drdθθ¨rθ˙2=αr2{\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}\cdot {\dot {\theta }}^{2}+{\frac {dr}{d\theta }}\cdot {\ddot {\theta }}-r{\dot {\theta }}^{2}=-{\frac {\alpha }{r^{2}}}}d2rdθ2(Hr2)2+drdθ(2Hr˙r3)r(Hr2)2=αr2{\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}\cdot \left({\frac {H}{r^{2}}}\right)^{2}+{\frac {dr}{d\theta }}\cdot \left(-{\frac {2\cdot H\cdot {\dot {r}}}{r^{3}}}\right)-r\left({\frac {H}{r^{2}}}\right)^{2}=-{\frac {\alpha }{r^{2}}}}

H2r4(d2rdθ22(drdθ)2rr)=αr2{\displaystyle {\frac {H^{2}}{r^{4}}}\cdot \left({\frac {d^{2}r}{d\theta ^{2}}}-2\cdot {\frac {\left({\frac {dr}{d\theta }}\right)^{2}}{r}}-r\right)=-{\frac {\alpha }{r^{2}}}}7

The differential equation (7) can be solved analytically by the variable substitution

r=1s{\displaystyle r={\frac {1}{s}}}8

Using the chain rule for differentiation gets:

drdθ=1s2dsdθ{\displaystyle {\frac {dr}{d\theta }}=-{\frac {1}{s^{2}}}\cdot {\frac {ds}{d\theta }}}9
d2rdθ2=2s3(dsdθ)21s2d2sdθ2{\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}={\frac {2}{s^{3}}}\cdot \left({\frac {ds}{d\theta }}\right)^{2}-{\frac {1}{s^{2}}}\cdot {\frac {d^{2}s}{d\theta ^{2}}}}10

Using the expressions (10) and (9) ford2rdθ2{\displaystyle {\frac {d^{2}r}{d\theta ^{2}}}} anddrdθ{\displaystyle {\frac {dr}{d\theta }}} gets

H2(d2sdθ2+s)=α{\displaystyle H^{2}\cdot \left({\frac {d^{2}s}{d\theta ^{2}}}+s\right)=\alpha }11

with the general solution

s=αH2(1+ecos(θθ0)){\displaystyle s={\frac {\alpha }{H^{2}}}\cdot \left(1+e\cdot \cos(\theta -\theta _{0})\right)}12

wheree andθ0{\displaystyle \theta _{0}} are constants of integration depending on the initial values fors anddsdθ.{\displaystyle {\tfrac {ds}{d\theta }}.}

Instead of using the constant of integrationθ0{\displaystyle \theta _{0}} explicitly one introduces the convention that the unit vectorsx^,y^{\displaystyle {\hat {x}},{\hat {y}}} defining the coordinate system in the orbital plane are selected such thatθ0{\displaystyle \theta _{0}} takes the value zero ande is positive. This then means thatθ{\displaystyle \theta } is zero at the point wheres{\displaystyle s} is maximal and thereforer=1s{\displaystyle r={\tfrac {1}{s}}} is minimal. Defining the parameterp asH2α{\displaystyle {\tfrac {H^{2}}{\alpha }}} one has that

r=1s=p1+ecosθ{\displaystyle r={\frac {1}{s}}={\frac {p}{1+e\cdot \cos \theta }}}

Alternate derivation

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Another way to solve this equation without the use of polar differential equations is as follows:

Define a unit vectoru{\displaystyle \mathbf {u} },u=rr{\displaystyle \mathbf {u} ={\frac {\mathbf {r} }{r}}}, such thatr=ru{\displaystyle \mathbf {r} =r\mathbf {u} } andr¨=αr2u{\displaystyle {\ddot {\mathbf {r} }}=-{\tfrac {\alpha }{r^{2}}}\mathbf {u} }. It follows thatH=r×r˙=ru×ddt(ru)=ru×(ru˙+r˙u)=r2(u×u˙)+rr˙(u×u)=r2u×u˙{\displaystyle \mathbf {H} =\mathbf {r} \times {\dot {\mathbf {r} }}=r\mathbf {u} \times {\frac {d}{dt}}(r\mathbf {u} )=r\mathbf {u} \times (r{\dot {\mathbf {u} }}+{\dot {r}}\mathbf {u} )=r^{2}(\mathbf {u} \times {\dot {\mathbf {u} }})+r{\dot {r}}(\mathbf {u} \times \mathbf {u} )=r^{2}\mathbf {u} \times {\dot {\mathbf {u} }}}

Now considerr¨×H=αr2u×(r2u×u˙)=αu×(u×u˙)=α[(uu˙)u(uu)u˙]{\displaystyle {\ddot {\mathbf {r} }}\times \mathbf {H} =-{\frac {\alpha }{r^{2}}}\mathbf {u} \times (r^{2}\mathbf {u} \times {\dot {\mathbf {u} }})=-\alpha \mathbf {u} \times (\mathbf {u} \times {\dot {\mathbf {u} }})=-\alpha [(\mathbf {u} \cdot {\dot {\mathbf {u} }})\mathbf {u} -(\mathbf {u} \cdot \mathbf {u} ){\dot {\mathbf {u} }}]}

(seeVector triple product). Notice thatuu=|u|2=1{\displaystyle \mathbf {u} \cdot \mathbf {u} =|\mathbf {u} |^{2}=1}uu˙=12(uu˙+u˙u)=12ddt(uu)=0{\displaystyle \mathbf {u} \cdot {\dot {\mathbf {u} }}={\frac {1}{2}}(\mathbf {u} \cdot {\dot {\mathbf {u} }}+{\dot {\mathbf {u} }}\cdot \mathbf {u} )={\frac {1}{2}}{\frac {d}{dt}}(\mathbf {u} \cdot \mathbf {u} )=0}

Substituting these values into the previous equation gives:r¨×H=αu˙{\displaystyle {\ddot {\mathbf {r} }}\times \mathbf {H} =\alpha {\dot {\mathbf {u} }}}

Integrating both sides:r˙×H=αu+c{\displaystyle {\dot {\mathbf {r} }}\times \mathbf {H} =\alpha \mathbf {u} +\mathbf {c} }

wherec is a constant vector. Dotting this withr yields an interesting result:r(r˙×H)=r(αu+c)=αru+rc=αr(uu)+rccos(θ)=r(α+ccos(θ)){\displaystyle \mathbf {r} \cdot ({\dot {\mathbf {r} }}\times \mathbf {H} )=\mathbf {r} \cdot (\alpha \mathbf {u} +\mathbf {c} )=\alpha \mathbf {r} \cdot \mathbf {u} +\mathbf {r} \cdot \mathbf {c} =\alpha r(\mathbf {u} \cdot \mathbf {u} )+rc\cos(\theta )=r(\alpha +c\cos(\theta ))}whereθ{\displaystyle \theta } is the angle betweenr{\displaystyle \mathbf {r} } andc{\displaystyle \mathbf {c} }. Solving forr :r=r(r˙×H)α+ccos(θ)=(r×r˙)Hα+ccos(θ)=|H|2α+ccos(θ)=|H|2/α1+(c/α)cos(θ).{\displaystyle r={\frac {\mathbf {r} \cdot ({\dot {\mathbf {r} }}\times \mathbf {H} )}{\alpha +c\cos(\theta )}}={\frac {(\mathbf {r} \times {\dot {\mathbf {r} }})\cdot \mathbf {H} }{\alpha +c\cos(\theta )}}={\frac {|\mathbf {H} |^{2}}{\alpha +c\cos(\theta )}}={\frac {|\mathbf {H} |^{2}/\alpha }{1+(c/\alpha )\cos(\theta )}}.}

Notice that(r,θ){\displaystyle (r,\theta )} are effectively the polar coordinates of the vector function. Making the substitutionsp=|H|2α{\displaystyle p={\tfrac {|\mathbf {H} |^{2}}{\alpha }}} ande=cα{\displaystyle e={\tfrac {c}{\alpha }}}, we again arrive at the equation

r=p1+ecosθ{\displaystyle r={\frac {p}{1+e\cdot \cos \theta }}}13

This is the equation in polar coordinates for aconic section with origin in a focal point. The argumentθ{\displaystyle \theta } is called "true anomaly".

Eccentricity Vector

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Notice also that, sinceθ{\displaystyle \theta } is the angle between the position vectorr{\displaystyle \mathbf {r} } and the integration constantc{\displaystyle \mathbf {c} }, the vectorc{\displaystyle \mathbf {c} } must be pointing in the direction of theperiapsis of the orbit. We can then define theeccentricity vector associated with the orbit as:ecα=r˙×Hαu=v×Hαrr=v×(r×v)αrr{\displaystyle \mathbf {e} \triangleq {\frac {\mathbf {c} }{\alpha }}={\frac {{\dot {\mathbf {r} }}\times \mathbf {H} }{\alpha }}-\mathbf {u} ={\frac {\mathbf {v} \times \mathbf {H} }{\alpha }}-{\frac {\mathbf {r} }{r}}={\frac {\mathbf {v} \times (\mathbf {r} \times \mathbf {v} )}{\alpha }}-{\frac {\mathbf {r} }{r}}}

whereH=r×r˙=r×v{\displaystyle \mathbf {H} =\mathbf {r} \times {\dot {\mathbf {r} }}=\mathbf {r} \times \mathbf {v} } is the constant angular momentum vector of the orbit, andv{\displaystyle \mathbf {v} } is the velocity vector associated with the position vectorr{\displaystyle \mathbf {r} }.

Obviously, theeccentricity vector, having the same direction as the integration constantc{\displaystyle \mathbf {c} }, also points to the direction of theperiapsis of the orbit, and it has the magnitude of orbital eccentricity. This makes it very useful inorbit determination (OD) for theorbital elements of an orbit when astate vector [r,r˙{\displaystyle \mathbf {r} ,\mathbf {\dot {r}} }] or [r,v{\displaystyle \mathbf {r} ,\mathbf {v} }] is known.

Properties of trajectory equation

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Fore=0{\displaystyle e=0} this is a circle with radiusp.

For0<e<1,{\displaystyle 0<e<1,} this is anellipse with

a=p1e2{\displaystyle a={\frac {p}{1-e^{2}}}}14
b=p1e2=a1e2{\displaystyle b={\frac {p}{\sqrt {1-e^{2}}}}=a\cdot {\sqrt {1-e^{2}}}}15

Fore=1{\displaystyle e=1} this is aparabola with focal lengthp2{\displaystyle {\tfrac {p}{2}}}

Fore>1{\displaystyle e>1} this is ahyperbola with

a=pe21{\displaystyle a={\frac {p}{e^{2}-1}}}16
b=pe21=ae21{\displaystyle b={\frac {p}{\sqrt {e^{2}-1}}}=a\cdot {\sqrt {e^{2}-1}}}17

The following image illustrates a circle (grey), an ellipse (red), a parabola (green) and a hyperbola (blue)

A diagram of the various forms of theKepler Orbit and their eccentricities. Blue is a hyperbolic trajectory (e > 1). Green is a parabolic trajectory (e = 1). Red is an elliptical orbit (0 <e < 1). Grey is a circular orbit (e = 0).

The point on the horizontal line going out to the right from the focal point is the point withθ=0{\displaystyle \theta =0} for which the distance to the focus takes the minimal valuep1+e,{\displaystyle {\tfrac {p}{1+e}},} the pericentre. For the ellipse there is also an apocentre for which the distance to the focus takes the maximal valuep1e.{\displaystyle {\tfrac {p}{1-e}}.} For the hyperbola the range forθ{\displaystyle \theta } iscos1(1e)<θ<cos1(1e){\displaystyle -\cos ^{-1}\left(-{\frac {1}{e}}\right)<\theta <\cos ^{-1}\left(-{\frac {1}{e}}\right)}and for a parabola the range isπ<θ<π{\displaystyle -\pi <\theta <\pi }

Using the chain rule for differentiation (5), the equation (2) and the definition ofp asH2α{\displaystyle {\frac {H^{2}}{\alpha }}} one gets that the radial velocity component is

Vr=r˙=Hpesinθ=αpesinθ{\displaystyle V_{r}={\dot {r}}={\frac {H}{p}}e\sin \theta ={\sqrt {\frac {\alpha }{p}}}e\sin \theta }18

and that the tangential component (velocity component perpendicular toVr{\displaystyle V_{r}}) is

Vt=rθ˙=Hr=αp(1+ecosθ){\displaystyle V_{t}=r\cdot {\dot {\theta }}={\frac {H}{r}}={\sqrt {\frac {\alpha }{p}}}\cdot (1+e\cdot \cos \theta )}19

The connection between the polar argumentθ{\displaystyle \theta } and timet is slightly different for elliptic and hyperbolic orbits.

For an elliptic orbit one switches to the "eccentric anomaly"E for which

x=a(cosEe){\displaystyle x=a\cdot (\cos E-e)}20
y=bsinE{\displaystyle y=b\cdot \sin E}21

and consequently

x˙=asinEE˙{\displaystyle {\dot {x}}=-a\cdot \sin E\cdot {\dot {E}}}22
y˙=bcosEE˙{\displaystyle {\dot {y}}=b\cdot \cos E\cdot {\dot {E}}}23

and the angular momentumH is

H=xy˙yx˙=ab(1ecosE)E˙{\displaystyle H=x\cdot {\dot {y}}-y\cdot {\dot {x}}=a\cdot b\cdot (1-e\cdot \cos E)\cdot {\dot {E}}}24

Integrating with respect to timet gives

Ht=ab(EesinE){\displaystyle H\cdot t=a\cdot b\cdot (E-e\cdot \sin E)}25

under the assumption that timet=0{\displaystyle t=0} is selected such that the integration constant is zero.

As by definition ofp one has

H=αp{\displaystyle H={\sqrt {\alpha \cdot p}}}26

this can be written

t=aaα(EesinE){\displaystyle t=a\cdot {\sqrt {\frac {a}{\alpha }}}(E-e\cdot \sin E)}27

For a hyperbolic orbit one uses thehyperbolic functions for the parameterisation

x=a(ecoshE){\displaystyle x=a\cdot (e-\cosh E)}28
y=bsinhE{\displaystyle y=b\cdot \sinh E}29

for which one has

x˙=asinhEE˙{\displaystyle {\dot {x}}=-a\cdot \sinh E\cdot {\dot {E}}}30
y˙=bcoshEE˙{\displaystyle {\dot {y}}=b\cdot \cosh E\cdot {\dot {E}}}31

and the angular momentumH is

H=xy˙yx˙=ab(ecoshE1)E˙{\displaystyle H=x\cdot {\dot {y}}-y\cdot {\dot {x}}=a\cdot b\cdot (e\cdot \cosh E-1)\cdot {\dot {E}}}32

Integrating with respect to timet gets

Ht=ab(esinhEE){\displaystyle H\cdot t=a\cdot b\cdot (e\cdot \sinh E-E)}33

i.e.

t=aaα(esinhEE){\displaystyle t=a\cdot {\sqrt {\frac {a}{\alpha }}}(e\cdot \sinh E-E)}34

To find what time t that corresponds to a certain true anomalyθ{\displaystyle \theta } one computes corresponding parameterE connected to time with relation (27) for an elliptic and with relation (34) for a hyperbolic orbit.

Note that the relations (27) and (34) define a mapping between the ranges[<t<][<E<]{\displaystyle \left[-\infty <t<\infty \right]\longleftrightarrow \left[-\infty <E<\infty \right]}

Some additional formulae

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For anelliptic orbit one gets from (20) and (21) that

r=a(1ecosE){\displaystyle r=a\cdot (1-e\cos E)}35

and therefore that

cosθ=xr=cosEe1ecosE{\displaystyle \cos \theta ={\frac {x}{r}}={\frac {\cos E-e}{1-e\cos E}}}36

From (36) then follows thattan2θ2=1cosθ1+cosθ=1cosEe1ecosE1+cosEe1ecosE=1ecosEcosE+e1ecosE+cosEe=1+e1e1cosE1+cosE=1+e1etan2E2{\displaystyle \tan ^{2}{\frac {\theta }{2}}={\frac {1-\cos \theta }{1+\cos \theta }}={\frac {1-{\frac {\cos E-e}{1-e\cos E}}}{1+{\frac {\cos E-e}{1-e\cos E}}}}={\frac {1-e\cos E-\cos E+e}{1-e\cos E+\cos E-e}}={\frac {1+e}{1-e}}\cdot {\frac {1-\cos E}{1+\cos E}}={\frac {1+e}{1-e}}\cdot \tan ^{2}{\frac {E}{2}}}

From the geometrical construction defining theeccentric anomaly it is clear that the vectors(cosE,sinE){\displaystyle (\cos E,\sin E)} and(cosθ,sinθ){\displaystyle (\cos \theta ,\sin \theta )} are on the same side of thex-axis. From this then follows that the vectors(cosE2,sinE2){\displaystyle \left(\cos {\tfrac {E}{2}},\sin {\tfrac {E}{2}}\right)} and(cosθ2,sinθ2){\displaystyle \left(\cos {\tfrac {\theta }{2}},\sin {\tfrac {\theta }{2}}\right)} are in the same quadrant. One therefore has that

tanθ2=1+e1etanE2{\displaystyle \tan {\frac {\theta }{2}}={\sqrt {\frac {1+e}{1-e}}}\cdot \tan {\frac {E}{2}}}37

and that

θ=2arg(1ecosE2,1+esinE2)+n2π{\displaystyle \theta =2\cdot \arg \left({\sqrt {1-e}}\cdot \cos {\frac {E}{2}},{\sqrt {1+e}}\cdot \sin {\frac {E}{2}}\right)+n\cdot 2\pi }38
E=2arg(1+ecosθ2,1esinθ2)+n2π{\displaystyle E=2\cdot \arg \left({\sqrt {1+e}}\cdot \cos {\frac {\theta }{2}},{\sqrt {1-e}}\cdot \sin {\frac {\theta }{2}}\right)+n\cdot 2\pi }39

where "arg(x,y){\displaystyle \arg(x,y)}" is the polar argument of the vector(x,y){\displaystyle (x,y)} andn is selected such that|Eθ|<π{\displaystyle |E-\theta |<\pi }

For the numerical computation ofarg(x,y){\displaystyle \arg(x,y)} the standard functionATAN2(y,x) (or indouble precision DATAN2(y,x)) available in for example the programming languageFORTRAN can be used.

Note that this is a mapping between the ranges[<θ<][<E<]{\displaystyle \left[-\infty <\theta <\infty \right]\longleftrightarrow \left[-\infty <E<\infty \right]}

For ahyperbolic orbit one gets from (28) and (29) that

r=a(ecoshE1){\displaystyle r=a\cdot (e\cdot \cosh E-1)}40

and therefore that

cosθ=xr=ecoshEecoshE1{\displaystyle \cos \theta ={\frac {x}{r}}={\frac {e-\cosh E}{e\cdot \cosh E-1}}}41

Astan2θ2=1cosθ1+cosθ=1ecoshEecoshE11+ecoshEecoshE1=ecoshEe+coshEecoshE+ecoshE=e+1e1coshE1coshE+1=e+1e1tanh2E2{\displaystyle \tan ^{2}{\frac {\theta }{2}}={\frac {1-\cos \theta }{1+\cos \theta }}={\frac {1-{\frac {e-\cosh E}{e\cdot \cosh E-1}}}{1+{\frac {e-\cosh E}{e\cdot \cosh E-1}}}}={\frac {e\cdot \cosh E-e+\cosh E}{e\cdot \cosh E+e-\cosh E}}={\frac {e+1}{e-1}}\cdot {\frac {\cosh E-1}{\cosh E+1}}={\frac {e+1}{e-1}}\cdot \tanh ^{2}{\frac {E}{2}}}and astanθ2{\displaystyle \tan {\frac {\theta }{2}}} andtanhE2{\displaystyle \tanh {\frac {E}{2}}} have the same sign it follows that

tanθ2=e+1e1tanhE2{\displaystyle \tan {\frac {\theta }{2}}={\sqrt {\frac {e+1}{e-1}}}\cdot \tanh {\frac {E}{2}}}42

This relation is convenient for passing between "true anomaly" and the parameterE, the latter being connected to time through relation (34). Note that this is a mapping between the ranges[cos1(1e)<θ<cos1(1e)][<E<]{\displaystyle \left[-\cos ^{-1}\left(-{\frac {1}{e}}\right)<\theta <\cos ^{-1}\left(-{\frac {1}{e}}\right)\right]\longleftrightarrow \left[-\infty <E<\infty \right]}and thatE2{\displaystyle {\tfrac {E}{2}}} can be computed using the relationtanh1x=12ln(1+x1x){\displaystyle \tanh ^{-1}x={\frac {1}{2}}\ln \left({\frac {1+x}{1-x}}\right)}

From relation (27) follows that the orbital periodP for an elliptic orbit is

P=2πaaα{\displaystyle P=2\pi a\cdot {\sqrt {\frac {a}{\alpha }}}}43

As the potential energy corresponding to the force field of relation (1) isαr{\displaystyle -{\frac {\alpha }{r}}}it follows from (13), (14), (18) and (19) that the sum of the kinetic and the potential energyVr2+Vt22αr{\displaystyle {\frac {{V_{r}}^{2}+{V_{t}}^{2}}{2}}-{\frac {\alpha }{r}}}for an elliptic orbit is

α2a{\displaystyle -{\frac {\alpha }{2a}}}44

and from (13), (16), (18) and (19) that the sum of the kinetic and the potential energy for a hyperbolic orbit is

α2a{\displaystyle {\frac {\alpha }{2a}}}45

Relative the inertial coordinate systemx^,y^{\displaystyle {\hat {x}},{\hat {y}}}in the orbital plane withx^{\displaystyle {\hat {x}}} towards pericentre one gets from (18) and (19) that the velocity components are

Vx=VrcosθVtsinθ=αpsinθ{\displaystyle V_{x}=V_{r}\cos \theta -V_{t}\sin \theta =-{\sqrt {\frac {\alpha }{p}}}\cdot \sin \theta }46
Vy=Vrsinθ+Vtcosθ=αp(e+cosθ){\displaystyle V_{y}=V_{r}\sin \theta +V_{t}\cos \theta ={\sqrt {\frac {\alpha }{p}}}\cdot (e+\cos \theta )}47

The equation of the center relates mean anomaly to true anomaly for elliptical orbits, for small numerical eccentricity.

Further information:Equation of the center § Analytical expansions

Determination of the Kepler orbit that corresponds to a given initial state

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This is the "initial value problem" for the differential equation (1) which is a first order equation for the 6-dimensional "state vector"(r,v){\displaystyle (\mathbf {r} ,\mathbf {v} )} when written as

v˙=αr^r2{\displaystyle {\dot {\mathbf {v} }}=-\alpha \cdot {\frac {\hat {\mathbf {r} }}{r^{2}}}}48
r˙=v{\displaystyle {\dot {\mathbf {r} }}=\mathbf {v} }49

For any values for the initial "state vector"(r0,v0){\displaystyle (\mathbf {r} _{0},\mathbf {v} _{0})} the Kepler orbit correspondingto the solution of this initial value problem can be found with the following algorithm:

Define the orthogonal unit vectors(r^,t^){\displaystyle ({\hat {\mathbf {r} }},{\hat {\mathbf {t} }})} through

r0=rr^{\displaystyle \mathbf {r} _{0}=r{\hat {\mathbf {r} }}}50
v0=Vrr^+Vtt^{\displaystyle \mathbf {v} _{0}=V_{r}{\hat {\mathbf {r} }}+V_{t}{\hat {\mathbf {t} }}}51

withr>0{\displaystyle r>0} andVt>0{\displaystyle V_{t}>0}

From (13), (18) and (19) follows that by setting

p=(rVt)2α{\displaystyle p={\frac {{(r\cdot V_{t})}^{2}}{\alpha }}}52

and by defininge0{\displaystyle e\geq 0} andθ{\displaystyle \theta } such that

ecosθ=VtV01{\displaystyle e\cos \theta ={\frac {V_{t}}{V_{0}}}-1}53
esinθ=VrV0{\displaystyle e\sin \theta ={\frac {V_{r}}{V_{0}}}}54

where

V0=αp{\displaystyle V_{0}={\sqrt {\frac {\alpha }{p}}}}55

one gets a Kepler orbit that for true anomalyθ{\displaystyle \theta } has the samer,Vr{\displaystyle V_{r}} andVt{\displaystyle V_{t}} values as those defined by (50) and (51).

If this Kepler orbit then also has the same(r^,t^){\displaystyle ({\hat {\mathbf {r} }},{\hat {\mathbf {t} }})} vectors for this true anomalyθ{\displaystyle \theta } as the ones defined by (50) and (51) the state vector(r,v){\displaystyle (\mathbf {r} ,\mathbf {v} )} of the Kepler orbit takes the desired values(r0,v0){\displaystyle (\mathbf {r} _{0},\mathbf {v} _{0})} for true anomalyθ{\displaystyle \theta }.

The standard inertially fixed coordinate system(x^,y^){\displaystyle ({\hat {\mathbf {x} }},{\hat {\mathbf {y} }})} in the orbital plane (withx^{\displaystyle {\hat {\mathbf {x} }}} directed from the centre of the homogeneous sphere to the pericentre) defining the orientation of the conical section (ellipse, parabola or hyperbola) can then be determined with the relation

x^=cosθr^sinθt^{\displaystyle {\hat {\mathbf {x} }}=\cos \theta {\hat {\mathbf {r} }}-\sin \theta {\hat {\mathbf {t} }}}56
y^=sinθr^+cosθt^{\displaystyle {\hat {\mathbf {y} }}=\sin \theta {\hat {\mathbf {r} }}+\cos \theta {\hat {\mathbf {t} }}}57

Note that the relations (53) and (54) has a singularity whenVr=0{\displaystyle V_{r}=0} andVt=V0=αp=α(rVt)2α{\displaystyle V_{t}=V_{0}={\sqrt {\frac {\alpha }{p}}}={\sqrt {\frac {\alpha }{\frac {{(r\cdot V_{t})}^{2}}{\alpha }}}}}i.e.

Vt=αr{\displaystyle V_{t}={\sqrt {\frac {\alpha }{r}}}}58

which is the case that it is a circular orbit that is fitting the initial state(r0,v0){\displaystyle (\mathbf {r} _{0},\mathbf {v} _{0})}

The osculating Kepler orbit

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Main article:Osculating orbit

For any state vector(r,v){\displaystyle (\mathbf {r} ,\mathbf {v} )} the Kepler orbit corresponding to this state can be computed with the algorithm defined above.First the parametersp,e,θ{\displaystyle p,e,\theta } are determined fromr,Vr,Vt{\displaystyle r,V_{r},V_{t}} and then the orthogonal unit vectors in the orbital planex^,y^{\displaystyle {\hat {x}},{\hat {y}}} using the relations (56) and (57).

If now the equation of motion is

r¨=F(r,r˙,t){\displaystyle {\ddot {\mathbf {r} }}=\mathbf {F} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}59

whereF(r,r˙,t){\displaystyle \mathbf {F} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}is a function other thanαrr2{\displaystyle -\alpha {\frac {\mathbf {r} }{r^{2}}}}the resulting parametersp{\displaystyle p},e{\displaystyle e},θ{\displaystyle \theta },x^{\displaystyle {\hat {\mathbf {x} }}},y^{\displaystyle {\hat {\mathbf {y} }}} defined byr,r˙{\displaystyle \mathbf {r} ,{\dot {\mathbf {r} }}} will all vary with time as opposed to the case of a Kepler orbit for which only the parameterθ{\displaystyle \theta } will vary.

The Kepler orbit computed in this way having the same "state vector" as the solution to the "equation of motion" (59) at timet is said to be "osculating" at this time.

This concept is for example useful in caseF(r,r˙,t)=αr^r2+f(r,r˙,t){\displaystyle \mathbf {F} (\mathbf {r} ,{\dot {\mathbf {r} }},t)=-\alpha {\frac {\hat {\mathbf {r} }}{r^{2}}}+\mathbf {f} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}wheref(r,r˙,t){\displaystyle \mathbf {f} (\mathbf {r} ,{\dot {\mathbf {r} }},t)}

is a small "perturbing force" due to for example a faint gravitational pull from other celestial bodies. The parameters of the osculating Kepler orbit will then only slowly change and the osculating Kepler orbit is a good approximation to the real orbit for a considerable time period before and after the time of osculation.

This concept can also be useful for a rocket during powered flight as it then tells which Kepler orbit the rocket would continue in case the thrust is switched off.

For a "close to circular" orbit the concept "eccentricity vector" defined ase=ex^{\displaystyle \mathbf {e} =e{\hat {\mathbf {x} }}} is useful. From (53), (54) and (56) follows that

e=(VtV0)r^Vrt^V0{\displaystyle \mathbf {e} ={\frac {(V_{t}-V_{0}){\hat {\mathbf {r} }}-V_{r}{\hat {\mathbf {t} }}}{V_{0}}}}60

i.e.e{\displaystyle \mathbf {e} } is a smooth differentiable function of the state vector(r,v){\displaystyle (\mathbf {r} ,\mathbf {v} )} also if this state corresponds to a circular orbit.

See also

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Citations

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  1. ^Copernicus. pp 513–514
  2. ^Bate, Mueller, White. pp 177–181
  3. ^"NASA website". Archived fromthe original on 16 February 2011. Retrieved12 August 2012.

References

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  • El'Yasberg "Theory of flight of artificial earth satellites", Israel program for Scientific Translations (1967)
  • Bate, Roger; Mueller, Donald; White, Jerry (1971).Fundamentals of Astrodynamics. Dover Publications, Inc., New York.ISBN 0-486-60061-0.
  • Copernicus, Nicolaus (1952), "Book I, Chapter 4, The Movement of the Celestial Bodies Is Regular, Circular, and Everlasting-Or Else Compounded of Circular Movements",On the Revolutions of the Heavenly Spheres, Great Books of the Western World, vol. 16, translated by Charles Glenn Wallis, Chicago: William Benton, pp. 497–838

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