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Absolute continuity

From Wikipedia, the free encyclopedia
Form of continuity for functions

Incalculus andreal analysis,absolute continuity is asmoothness property offunctions that is stronger thancontinuity anduniform continuity. The notion of absolute continuity allows one to obtain generalizations of the relationship between the two central operations ofcalculusdifferentiation andintegration. This relationship is commonly characterized (by thefundamental theorem of calculus) in the framework ofRiemann integration, but with absolute continuity it may be formulated in terms ofLebesgue integration. For real-valued functions on thereal line, two interrelated notions appear:absolute continuity of functions andabsolute continuity of measures. These two notions are generalized in different directions. The usual derivative of a function is related to theRadon–Nikodym derivative, ordensity, of a measure. We have the following chains of inclusions for functionsover acompact subset of the real line:

absolutely continuousuniformly continuous={\displaystyle =}continuous

and, for a compact interval,

continuously differentiableLipschitz continuousabsolutely continuousbounded variationdifferentiablealmost everywhere.

Absolute continuity of functions

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A continuous function fails to be absolutely continuous if it fails to beuniformly continuous, which can happen if the domain of the function is not compact – examples are tan(x) over[0,π/2),x2 over the entire real line, and sin(1/x) over (0, 1]. But a continuous functionf can fail to be absolutely continuous even on a compact interval. It may not be "differentiable almost everywhere" (like theWeierstrass function, which is not differentiable anywhere). Or it may bedifferentiable almost everywhere and its derivativef  may beLebesgue integrable, but the integral off  differs from the increment off (how muchf changes over an interval). This happens for example with theCantor function.

Definition

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LetI{\displaystyle I} be aninterval in thereal lineR{\displaystyle \mathbb {R} }. A functionf:IR{\displaystyle f\colon I\to \mathbb {R} } isabsolutely continuous onI{\displaystyle I} if for every positive numberε{\displaystyle \varepsilon }, there is a positive numberδ{\displaystyle \delta } such that whenever a finite sequence ofpairwise disjoint sub-intervals(xk,yk){\displaystyle (x_{k},y_{k})} ofI{\displaystyle I} withxk<yk{\displaystyle x_{k}<y_{k}} satisfies[1]

k=1N(ykxk)<δ{\displaystyle \sum _{k=1}^{N}(y_{k}-x_{k})<\delta }

then

k=1N|f(yk)f(xk)|<ε.{\displaystyle \sum _{k=1}^{N}|f(y_{k})-f(x_{k})|<\varepsilon .}

The collection of all absolutely continuous functions onI{\displaystyle I} is denotedAC(I){\displaystyle \operatorname {AC} (I)}.

Equivalent definitions

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The following conditions on a real-valued functionf on a compact interval [a,b] are equivalent:[2]

  1. f is absolutely continuous;
  2. f has a derivativef almost everywhere, the derivative is Lebesgue integrable, andf(x)=f(a)+axf(t)dt{\displaystyle f(x)=f(a)+\int _{a}^{x}f'(t)\,dt} for allx on [a,b];
  3. there exists a Lebesgue integrable functiong on [a,b] such thatf(x)=f(a)+axg(t)dt{\displaystyle f(x)=f(a)+\int _{a}^{x}g(t)\,dt} for allx in [a,b].

If these equivalent conditions are satisfied, then necessarily any functiong as in condition 3. satisfiesg =f  almost everywhere.

Equivalence between (1) and (3) is known as thefundamental theorem of Lebesgue integral calculus, due toLebesgue.[3]

For an equivalent definition in terms of measures see the sectionRelation between the two notions of absolute continuity.

Properties

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  • The sum and difference of two absolutely continuous functions are also absolutely continuous. If the two functions are defined on a bounded closed interval, then their product is also absolutely continuous.[4]
  • If an absolutely continuous functionf is defined on a bounded closed interval and is nowhere zero then1/f is absolutely continuous.[5]
  • Every absolutely continuous function (over a compact interval) isuniformly continuous and, therefore,continuous. Every (globally)Lipschitz-continuousfunction is absolutely continuous.[6]
  • Iff: [a,b] →R is absolutely continuous, then it is ofbounded variation on [a,b].[7]
  • Iff: [a,b] →R is absolutely continuous, then it can be written as the difference of two monotonic nondecreasing absolutely continuous functions on [a,b].
  • Iff: [a,b] →R is absolutely continuous, then it has theLuzinN property (that is, for anyN[a,b]{\displaystyle N\subseteq [a,b]} such thatλ(N)=0{\displaystyle \lambda (N)=0}, it holds thatλ(f(N))=0{\displaystyle \lambda (f(N))=0}, whereλ{\displaystyle \lambda } stands for theLebesgue measure onR).
  • f:IR is absolutely continuous if and only if it is continuous, is of bounded variation and has the LuzinN property. This statement is also known as the Banach-Zareckiǐ theorem.[8]
  • Iff:IR is absolutely continuous andg:RR is globallyLipschitz-continuous, then the compositiong{\displaystyle \circ } f is absolutely continuous. Conversely, for every functiong that is not globally Lipschitz continuous there exists an absolutely continuous functionf such thatg{\displaystyle \circ } f is not absolutely continuous.[9]

Examples

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The following functions are uniformly continuous butnot absolutely continuous:

The following functions are absolutely continuous but not α-Hölder continuous:

  • The functionf(x) = xβ on [0, c], for any0 <β <α < 1

The following functions are absolutely continuous andα-Hölder continuous but notLipschitz continuous:

  • The functionf(x) = x on [0, c], forα ≤ 1/2.

Generalizations

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Let (X,d) be ametric space and letI be aninterval in thereal lineR. A functionf:IX isabsolutely continuous onI if for every positive numberε{\displaystyle \varepsilon }, there is a positive numberδ{\displaystyle \delta } such that whenever a finite sequence ofpairwise disjoint sub-intervals [xk,yk] ofI satisfies:

k|ykxk|<δ{\displaystyle \sum _{k}\left|y_{k}-x_{k}\right|<\delta }

then:

kd(f(yk),f(xk))<ε.{\displaystyle \sum _{k}d\left(f(y_{k}),f(x_{k})\right)<\varepsilon .}

The collection of all absolutely continuous functions fromI intoX is denoted AC(I;X).

A further generalization is the space ACp(I;X) of curvesf:IX such that:[10]

d(f(s),f(t))stm(τ)dτ for all [s,t]I{\displaystyle d\left(f(s),f(t)\right)\leq \int _{s}^{t}m(\tau )\,d\tau {\text{ for all }}[s,t]\subseteq I}

for somem in theLp spaceLp(I).

Properties of these generalizations

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Absolute continuity of measures

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Definition

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Ameasureμ{\displaystyle \mu } onBorel subsets of the real line is absolutely continuous with respect to theLebesgue measureλ{\displaystyle \lambda } if for everyλ{\displaystyle \lambda }-measurable setA,{\displaystyle A,}λ(A)=0{\displaystyle \lambda (A)=0} impliesμ(A)=0{\displaystyle \mu (A)=0}. Equivalently,μ(A)>0{\displaystyle \mu (A)>0} impliesλ(A)>0{\displaystyle \lambda (A)>0}. This condition is written asμλ.{\displaystyle \mu \ll \lambda .} We sayμ{\displaystyle \mu } isdominated byλ.{\displaystyle \lambda .}

In most applications, if a measure on the real line is simply said to be absolutely continuous — without specifying with respect to which other measure it is absolutely continuous — then absolute continuity with respect to the Lebesgue measure is meant.

The same principle holds for measures on Borel subsets ofRn,n2.{\displaystyle \mathbb {R} ^{n},n\geq 2.}

Equivalent definitions

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The following conditions on a finite measureμ{\displaystyle \mu } on Borel subsets of the real line are equivalent:[12]

  1. μ{\displaystyle \mu } is absolutely continuous;
  2. For every positive numberε{\displaystyle \varepsilon } there is a positive numberδ>0{\displaystyle \delta >0} such thatμ(A)<ε{\displaystyle \mu (A)<\varepsilon } for all Borel setsA{\displaystyle A} of Lebesgue measure less thanδ;{\displaystyle \delta ;}
  3. There exists a Lebesgue integrable functiong{\displaystyle g} on the real line such that:μ(A)=Agdλ{\displaystyle \mu (A)=\int _{A}g\,d\lambda } for all Borel subsetsA{\displaystyle A} of the real line.

For an equivalent definition in terms of functions see the sectionRelation between the two notions of absolute continuity.

Any other function satisfying (3) is equal tog{\displaystyle g} almost everywhere. Such a function is calledRadon–Nikodym derivative, or density, of the absolutely continuous measureμ.{\displaystyle \mu .}

Equivalence between (1), (2) and (3) holds also inRn{\displaystyle \mathbb {R} ^{n}} for alln=1,2,3,.{\displaystyle n=1,2,3,\ldots .}

Thus, the absolutely continuous measures onRn{\displaystyle \mathbb {R} ^{n}} are precisely those that have densities; as a special case, the absolutely continuous probability measures are precisely the ones that haveprobability density functions.

Generalizations

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Ifμ{\displaystyle \mu } andν{\displaystyle \nu } are twomeasures on the samemeasurable space(X,A),{\displaystyle (X,{\mathcal {A}}),}μ{\displaystyle \mu } is said to beabsolutely continuous with respect toν{\displaystyle \nu } ifμ(A)=0{\displaystyle \mu (A)=0} for every setA{\displaystyle A} for whichν(A)=0.{\displaystyle \nu (A)=0.}[13] This is written as "μν{\displaystyle \mu \ll \nu }". That is:μν if and only if  for all AA,(ν(A)=0  implies  μ(A)=0).{\displaystyle \mu \ll \nu \qquad {\text{ if and only if }}\qquad {\text{ for all }}A\in {\mathcal {A}},\quad (\nu (A)=0\ {\text{ implies }}\ \mu (A)=0).}

Whenμν,{\displaystyle \mu \ll \nu ,} thenν{\displaystyle \nu } is said to bedominatingμ.{\displaystyle \mu .}

Absolute continuity of measures isreflexive andtransitive, but is notantisymmetric, so it is apreorder rather than apartial order. Instead, ifμν{\displaystyle \mu \ll \nu } andνμ,{\displaystyle \nu \ll \mu ,} the measuresμ{\displaystyle \mu } andν{\displaystyle \nu } are said to beequivalent. Thus absolute continuity induces a partial ordering of suchequivalence classes.

Ifμ{\displaystyle \mu } is asigned orcomplex measure, it is said thatμ{\displaystyle \mu } is absolutely continuous with respect toν{\displaystyle \nu } if its variation|μ|{\displaystyle |\mu |} satisfies|μ|ν;{\displaystyle |\mu |\ll \nu ;} equivalently, if every setA{\displaystyle A} for whichν(A)=0{\displaystyle \nu (A)=0} isμ{\displaystyle \mu }-null.

TheRadon–Nikodym theorem[14] states that ifμ{\displaystyle \mu } is absolutely continuous with respect toν,{\displaystyle \nu ,} and both measures areσ-finite, thenμ{\displaystyle \mu } has a density, or "Radon-Nikodym derivative", with respect toν,{\displaystyle \nu ,} which means that there exists aν{\displaystyle \nu }-measurable functionf{\displaystyle f} taking values in[0,+),{\displaystyle [0,+\infty ),} denoted byf=dμ/dν,{\displaystyle f=d\mu /d\nu ,} such that for anyν{\displaystyle \nu }-measurable setA{\displaystyle A} we have:μ(A)=Afdν.{\displaystyle \mu (A)=\int _{A}f\,d\nu .}

Singular measures

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ViaLebesgue's decomposition theorem,[15] every σ-finite measure can be decomposed into the sum of an absolutely continuous measure and a singular measure with respect to another σ-finite measure. Seesingular measure for examples of measures that are not absolutely continuous.

Relation between the two notions of absolute continuity

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A finite measureμ onBorel subsets of the real line is absolutely continuous with respect toLebesgue measure if and only if the point function:

F(x)=μ((,x]){\displaystyle F(x)=\mu ((-\infty ,x])}

is an absolutely continuous real function. More generally, a function is locally (meaning on every bounded interval) absolutely continuous if and only if itsdistributional derivative is a measure that is absolutely continuous with respect to the Lebesgue measure.

If absolute continuity holds then the Radon–Nikodym derivative ofμ is equal almost everywhere to the derivative ofF.[16]

More generally, the measureμ is assumed to be locally finite (rather than finite) andF(x) is defined asμ((0,x]) forx > 0, 0 forx = 0, and −μ((x,0]) forx < 0. In this caseμ is theLebesgue–Stieltjes measure generated byF.[17] The relation between the two notions of absolute continuity still holds.[18]

Notes

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  1. ^Royden 1988, Sect. 5.4, page 108;Nielsen 1997, Definition 15.6 on page 251;Athreya & Lahiri 2006, Definitions 4.4.1, 4.4.2 on pages 128,129. The intervalI{\displaystyle I} is assumed to be bounded and closed in the former two books but not the latter book.
  2. ^Nielsen 1997, Theorem 20.8 on page 354; alsoRoyden 1988, Sect. 5.4, page 110 andAthreya & Lahiri 2006, Theorems 4.4.1, 4.4.2 on pages 129,130.
  3. ^Athreya & Lahiri 2006, before Theorem 4.4.1 on page 129.
  4. ^Royden 1988, Problem 5.14(a,b) on page 111.
  5. ^Royden 1988, Problem 5.14(c) on page 111.
  6. ^Royden 1988, Problem 5.20(a) on page 112.
  7. ^Royden 1988, Lemma 5.11 on page 108.
  8. ^Bruckner, Bruckner & Thomson 1997, Theorem 7.11.
  9. ^Fichtenholz 1923.
  10. ^Ambrosio, Gigli & Savaré 2005, Definition 1.1.1 on page 23
  11. ^Ambrosio, Gigli & Savaré 2005, Theorem 1.1.2 on page 24
  12. ^Equivalence between (1) and (2) is a special case ofNielsen 1997, Proposition 15.5 on page 251 (fails for σ-finite measures); equivalence between (1) and (3) is a special case of theRadon–Nikodym theorem, seeNielsen 1997, Theorem 15.4 on page 251 orAthreya & Lahiri 2006, Item (ii) of Theorem 4.1.1 on page 115 (still holds for σ-finite measures).
  13. ^Nielsen 1997, Definition 15.3 on page 250;Royden 1988, Sect. 11.6, page 276;Athreya & Lahiri 2006, Definition 4.1.1 on page 113.
  14. ^Royden 1988, Theorem 11.23 on page 276;Nielsen 1997, Theorem 15.4 on page 251;Athreya & Lahiri 2006, Item (ii) of Theorem 4.1.1 on page 115.
  15. ^Royden 1988, Proposition 11.24 on page 278;Nielsen 1997, Theorem 15.14 on page 262;Athreya & Lahiri 2006, Item (i) of Theorem 4.1.1 on page 115.
  16. ^Royden 1988, Problem 12.17(b) on page 303.
  17. ^Athreya & Lahiri 2006, Sect. 1.3.2, page 26.
  18. ^Nielsen 1997, Proposition 15.7 on page 252;Athreya & Lahiri 2006, Theorem 4.4.3 on page 131;Royden 1988, Problem 12.17(a) on page 303.

References

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External links

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