You can achieve this usingint() withbase argument.

You can know more aboutint(x,base) -here

• Split the string at'.' and store it in a listlst
• For every item inlst, convert the item (binary string) to decimal usingint(item, base=2) and then convert it into string type.
• Join the contents oflst using.

s = '00000000.00000000.00001111.11111111'lst = s.split('.')lst = [str(int(i,2)) for i in lst]print('.'.join(lst))

# Output0.0.15.255

First split the string on. then convert each to integer equivalent of the binary representation usingint builtin passingbase=2, then convert to string, finally join them all on.

>>> text = '00000000.00000000.00001111.11111111'>>> '.'.join(str(int(i, base=2)) for i in text.split('.'))# output'0.0.15.255'

You should split the data, convert and combine.

data = "00000000.00000000.00001111.11111111"data_int = ".".join([str(int(i, 2)) for i in data.split(".")])print(data_int)  # 0.0.15.255

Welcome! Once you have a string like this

s = '00000000.00000000.00101111.11111111'

you may get your integers in one single line:

int_list = list(map(lambda n_str: int(n_str, 2), s.split('.')))

• python
• string
• binary