You can use theint() function:

result = ''st = 'string'binSt = ' '.join(format(ord(x), '08b') for x in st)binSt_split = binSt.split()for split in binSt_split:    result = result + str(int(split,2) + ' 'print result

You can simply do

r = [int(numbs, 2) for numbs in binSt.split(' ')]

int(str, baseNumber) will read the stringstr and convert it toint usingbaseNumber

soint("0xFF", 16) = 255 andint("11", 2) = 3

Why not use abytearray?

>>> barr = bytearray('string')>>> barr[0]115

Bytearray does exactly what you want -- It interprets each character in the string as an integer in the range from0 ->255.

Using the solution for binary to int here:Convert base-2 binary number string to int

 binSt = ' '.join([str(int(format(ord(x), '08b'), 2)) for x in st])

And if you just want an array of ints

 int_array = [int(format(ord(x), '08b'), 2) for x in st]

Addressing SpoonMeiser comments. you can avoid intermediate conversions with ord(x)

 int_array = [ord(x) for x in st]

String to binary and then to decimal :

st = 'string'binSt = ' '.join(format(ord(x), '08b') for x in st)binSt##'01110011 01110100 01110010 01101001 01101110 01100111'bin=binSt.split()bin##['01110011', '01110100', '01110010', '01101001', '01101110', '01100111']print(map(lambda x: int(x,2), bin))##[115, 116, 114, 105, 110, 103]

## is used for outputs

• python