(PHP 7, PHP 8)
intdiv —Integer division
Returns the integer quotient of the division ofnum1 bynum2.
num1Number to be divided.
num2 Number which divides thenum1.
The integer quotient of the division ofnum1 bynum2.
Ifnum2 is0, aDivisionByZeroError exception is thrown. If thenum1 isPHP_INT_MIN and thenum2 is-1, then anArithmeticError exception is thrown.
Example #1intdiv() example
<?php
var_dump(intdiv(3,2));
var_dump(intdiv(-3,2));
var_dump(intdiv(3, -2));
var_dump(intdiv(-3, -2));
var_dump(intdiv(PHP_INT_MAX,PHP_INT_MAX));
var_dump(intdiv(PHP_INT_MIN,PHP_INT_MIN));
?>The above example will output:
int(1)int(-1)int(-1)int(1)int(1)int(1)
Example #2intdiv() Example With Invalid Divisor
<?php
try {
intdiv(PHP_INT_MIN, -1);
} catch (Error $e) {
echoget_class($e),': ',$e->getMessage(),PHP_EOL;
}
try {
intdiv(1,0);
} catch (Error $e) {
echoget_class($e),': ',$e->getMessage(),PHP_EOL;
}
?>The above example will output:
ArithmeticError: Division of PHP_INT_MIN by -1 is not an integerDivisionByZeroError: Division by zero
This does indeed seem to be equal to intdiv:
<?php
functionintdiv_1($a,$b){
return ($a-$a%$b) /$b;
}
?>
However, this isn't:
<?php
functionintdiv_2($a,$b){
returnfloor($a/$b);
}
?>
Consider an example where either of the parameters is negative:
<?php
$param1= -10;
$param2=3;
print_r([
'modulus'=>intdiv_1($param1,$param2),
'floor'=>intdiv_2($param1,$param2),
]);
/**
* Array
* (
* [modulus] => -3
* [floor] => -4
* )
*/
?>Python style integer division, where the result is always rounded towards minus infinity.
1 // 2 is 0
(-1) // 2 is -1
1 // (-2) is -1
(-1) // (-2) is 0
<?php
functionintdiv_py(int $num1,int $num2):int{
if ($num1<0xor$num2<0){
$num1=abs($num1);
$num2=abs($num2);
$remainder=$num1%$num2;
return$remainder? -1-($num1-$remainder) /$num2: -$num1/$num2;
}
returnintdiv($num1,$num2);
}
var_dump(intdiv_py(1,2));// 0
var_dump(intdiv_py(-1,2));// -1
var_dump(intdiv_py(1, -2));// -1
var_dump(intdiv_py(-1, -2));// 0
?>