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path root_directory()const; | (since C++17) | |
Returns the root directory of the generic-format path. If the path (in generic format) does not include root directory, returnspath().
Contents |
(none)
The root directory of the path.
May throw implementation-defined exceptions.
#include <filesystem>#include <iostream>namespace fs= std::filesystem; int main(){ fs::path p= fs::current_path(); std::cout<<"The current path "<< p<<" decomposes into:\n"<<"root name "<< p.root_name()<<'\n'<<"root directory "<< p.root_directory()<<'\n'<<"relative path "<< p.relative_path()<<'\n';}
Possible output:
The current path "C:\Users\abcdef\Local Settings\temp" decomposes into:root name "C:"root directory "\"relative path "Users\abcdef\Local Settings\temp"
| returns the root-name of the path, if present (public member function)[edit] | |
| returns the root path of the path, if present (public member function)[edit] |