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Commitd53c2b7

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Added python solution for 323-Number-of-Connected-Components-in-an-Undirected-Graph
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classUnionFind:
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def__init__(self):
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self.f= {}
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deffindParent(self,x):
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y=self.f.get(x,x)
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ifx!=y:
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y=self.f[x]=self.findParent(y)
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returny
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defunion(self,x,y):
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self.f[self.findParent(x)]=self.findParent(y)
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classSolution:
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defcountComponents(self,n:int,edges:List[List[int]])->int:
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dsu=UnionFind()
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fora,binedges:
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dsu.union(a,b)
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returnlen(set(dsu.findParent(x)forxinrange(n)))

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