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Commitb96c1bd

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Create 448-Find-All-Numbers-Disappeared-in-an-Array.java
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// Since the array has values form 0 to n we can use in-place sorting that's O(N) time and constant space.
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classSolution {
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publicList<Integer>findDisappearedNumbers(int[]nums) {
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List<Integer>list =newArrayList<>();
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for (inti =0;i<nums.length;i++) {
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intcorrect =nums[i]-1;
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if (nums[i]!=nums[correct] &&nums[correct]!=nums[i]) {
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inttemp =nums[i];
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nums[i] =nums[correct];
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nums[correct] =temp;
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i--;
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}
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}
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for (inti =0;i<nums.length;i++) {
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if (nums[i]-1!=i)
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list.add(i+1);
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}
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returnlist;
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}
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}

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