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Commitdc54cc8

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Update all yesterday (Mar 26)'s solution changes.
1 parentc26f2c0 commitdc54cc8

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‎en/1-1000/1-two-sum.md‎

Lines changed: 1 addition & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -2,7 +2,7 @@ Original link: [leetcoder.net - LeetCoder: Fucking Good LeetCode Solutions](http
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#1. Two Sum - LeetCoder: Fucking Good LeetCode Solutions
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5-
LeetCode link:[1. Two Sum](https://leetcode.com/problems/two-sum),Difficulty:**Easy**.
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LeetCode link:[1. Two Sum](https://leetcode.com/problems/two-sum),difficulty:**Easy**.
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##LeetCode description of "1. Two Sum"
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‎en/1-1000/15-3sum.md‎

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@@ -2,7 +2,7 @@ Original link: [leetcoder.net - LeetCoder: Fucking Good LeetCode Solutions](http
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#15. 3Sum - LeetCoder: Fucking Good LeetCode Solutions
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5-
LeetCode link:[15. 3Sum](https://leetcode.com/problems/3sum),Difficulty:**Medium**.
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LeetCode link:[15. 3Sum](https://leetcode.com/problems/3sum),difficulty:**Medium**.
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##LeetCode description of "15. 3Sum"
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@@ -140,6 +140,308 @@ class Solution:
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return list(results)
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```
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## Ruby
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```ruby
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# @param {Integer[]} nums
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# @return {Integer[][]}
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def three_sum(nums)
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nums.sort!
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results = Set.new
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nums_2 = []
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nums.each_with_index do |num, i|
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next if i >= 3 && num == nums[i - 1] && num == nums[i - 2] && num == nums[i - 3]
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nums_2.append(num)
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end
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nums = nums_2
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# Iterate through each number as potential first element
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(0...nums.length - 2).each do |i|
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break if nums[i] > 0
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left = i + 1
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right = nums.length - 1
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# Two-pointer approach for remaining elements
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while left < right
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current_sum = nums[i] + nums[left] + nums[right]
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if current_sum == 0
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# Add sorted triplet to avoid duplicates
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results.add([nums[i], nums[left], nums[right]])
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left += 1
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right -= 1
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elsif current_sum < 0
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left += 1 # Need larger sum
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else
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right -= 1 # Need smaller sum
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end
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end
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end
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results.to_a
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end
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```
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## Go
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```go
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func threeSum(nums []int) [][]int {
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sort.Ints(nums)
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nums2 := make([]int, 0)
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for i, num := range nums {
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if i >= 3 && num == nums[i-1] && nums[i-1] == nums[i-2] && nums[i-2] == nums[i-3] {
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continue
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}
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nums2 = append(nums2, num)
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}
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nums = nums2
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results := make([][]int, 0)
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seen := make(map[string]bool)
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for i := 0; i < len(nums)-2; i++ {
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// if nums[i] > 0 {
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// break
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// }
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left := i + 1
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right := len(nums) - 1
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for left < right {
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sum := nums[left] + nums[right]
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if sum == -nums[i] {
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triplet := []int{nums[i], nums[left], nums[right]}
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key := fmt.Sprintf("%d,%d,%d", triplet[0], triplet[1], triplet[2])
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if !seen[key] {
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results = append(results, triplet)
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seen[key] = true
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}
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left++
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} else if sum > -nums[i] {
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right--
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} else {
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left++
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}
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}
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}
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return results
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}
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```
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##C++
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```cpp
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class Solution {
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public:
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vector<vector<int>> threeSum(vector<int>& nums) {
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sort(nums.begin(), nums.end());
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// Uncomment to speed up
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// vector<int> nums2;
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// for (int i = 0; i < nums.size(); i++) {
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// if (i >= 3 && nums[i] == nums[i-1] && nums[i-1] == nums[i-2] &&
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// nums[i-2] == nums[i-3]) {
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// continue;
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// }
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// nums2.push_back(nums[i]);
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// }
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// nums = nums2;
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vector<vector<int>> results;
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set<vector<int>> seen;
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for (int i = 0; i < nums.size() - 2; i++) {
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// Uncomment to speed up
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// if (nums[i] > 0) {
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// break;
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// }
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int left = i + 1;
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int right = nums.size() - 1;
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while (left < right) {
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int sum = nums[left] + nums[right];
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if (sum == -nums[i]) {
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vector<int> triplet = {nums[i], nums[left], nums[right]};
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if (seen.find(triplet) == seen.end()) {
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results.push_back(triplet);
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seen.insert(triplet);
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}
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left++;
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} else if (sum > -nums[i]) {
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right--;
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} else {
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left++;
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}
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}
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}
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return results;
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}
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};
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```
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## JavaScript
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```javascript
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/**
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* @param {number[]} nums
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* @return {number[][]}
296+
*/
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var threeSum = function(nums) {
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nums.sort((a, b) => a - b);
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// Uncomment to speed up
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// let nums2 = [];
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// for (let i = 0; i < nums.length; i++) {
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// if (i >= 3 && nums[i] === nums[i-1] && nums[i-1] === nums[i-2] && nums[i-2] === nums[i-3]) {
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// continue;
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// }
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// nums2.push(nums[i]);
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// }
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// nums = nums2;
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const results = [];
311+
const seen = new Set();
312+
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for (let i = 0; i < nums.length - 2; i++) {
314+
// Uncomment to speed up
315+
// if (nums[i] > 0) {
316+
// break;
317+
// }
318+
let left = i + 1;
319+
let right = nums.length - 1;
320+
321+
while (left < right) {
322+
const sum = nums[left] + nums[right];
323+
324+
if (sum === -nums[i]) {
325+
const triplet = [nums[i], nums[left], nums[right]];
326+
const key = triplet.join(',');
327+
if (!seen.has(key)) {
328+
results.push(triplet);
329+
seen.add(key);
330+
}
331+
left++;
332+
} else if (sum > -nums[i]) {
333+
right--;
334+
} else {
335+
left++;
336+
}
337+
}
338+
}
339+
340+
return results;
341+
};
342+
```
343+
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##C#
345+
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```csharp
347+
public class Solution {
348+
public IList<IList<int>> ThreeSum(int[] nums) {
349+
Array.Sort(nums);
350+
351+
// Uncomment to speed up
352+
// var nums2 = new List<int>();
353+
// for (int i = 0; i < nums.Length; i++) {
354+
// if (i >= 3 && nums[i] == nums[i-1] && nums[i-1] == nums[i-2] && nums[i-2] == nums[i-3]) {
355+
// continue;
356+
// }
357+
// nums2.Add(nums[i]);
358+
// }
359+
// nums = nums2.ToArray();
360+
361+
var results = new List<IList<int>>();
362+
var seen = new HashSet<string>();
363+
364+
for (int i = 0; i < nums.Length - 2; i++) {
365+
// Uncomment to speed up
366+
// if (nums[i] > 0) {
367+
// break;
368+
// }
369+
int left = i + 1;
370+
int right = nums.Length - 1;
371+
372+
while (left < right) {
373+
int sum = nums[left] + nums[right];
374+
if (sum == -nums[i]) {
375+
var triplet = new List<int> { nums[i], nums[left], nums[right] };
376+
string key = string.Join(",", triplet);
377+
if (!seen.Contains(key)) {
378+
results.Add(triplet);
379+
seen.Add(key);
380+
}
381+
left++;
382+
} else if (sum > -nums[i]) {
383+
right--;
384+
} else {
385+
left++;
386+
}
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}
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}
389+
390+
return results;
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}
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}
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```
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## Java
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```java
398+
class Solution {
399+
public List<List<Integer>> threeSum(int[] nums) {
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Arrays.sort(nums);
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// Uncomment to speed up
403+
// List<Integer> nums2 = new ArrayList<>();
404+
// for (int i = 0; i < nums.length; i++) {
405+
// if (i >= 3 && nums[i] == nums[i-1] && nums[i-1] == nums[i-2] && nums[i-2] == nums[i-3]) {
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// continue;
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// }
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// nums2.add(nums[i]);
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// }
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// nums = nums2.stream().mapToInt(i -> i).toArray();
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List<List<Integer>> results = new ArrayList<>();
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var seen = new HashSet<>();
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for (int i = 0; i < nums.length - 2; i++) {
416+
// Uncomment to speed up
417+
// if (nums[i] > 0) {
418+
// break;
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// }
420+
int left = i + 1;
421+
int right = nums.length - 1;
422+
423+
while (left < right) {
424+
int sum = nums[left] + nums[right];
425+
if (sum == -nums[i]) {
426+
List<Integer> triplet = Arrays.asList(nums[i], nums[left], nums[right]);
427+
if (!seen.contains(triplet)) {
428+
results.add(triplet);
429+
seen.add(triplet);
430+
}
431+
left++;
432+
} else if (sum > -nums[i]) {
433+
right--;
434+
} else {
435+
left++;
436+
}
437+
}
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}
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440+
return results;
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}
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}
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```
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143445
## Other languages
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145447
```java

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