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Commitd435414

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Create 1249-minimum-remove-to-make-valid-parentheses.cpp
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/*
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* [1249] Minimum Remove to Make Valid Parentheses *
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Given a string s of '(' , ')' and lowercase English characters.
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Your task is to remove the minimum number of parentheses ( '(' or ')', in any positions ) so that the resulting parentheses string is valid and return any valid string.
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Formally, a parentheses string is valid if and only if:
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It is the empty string, contains only lowercase characters, or
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It can be written as AB (A concatenated with B), where A and B are valid strings, or
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It can be written as (A), where A is a valid string.
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Example 1:
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Input: s = "lee(t(c)o)de)"
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Output: "lee(t(c)o)de"
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Explanation: "lee(t(co)de)" , "lee(t(c)ode)" would also be accepted.
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Time: O(n)
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Space: O(n)
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Runtime: 14 ms, faster than 98.14% of C++ online submissions for Minimum Remove to Make Valid Parentheses.
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Memory Usage: 14.2 MB, less than 10.57% of C++ online submissions for Minimum Remove to Make Valid Parentheses.
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*/
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classSolution {
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public:
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stringminRemoveToMakeValid(string s) {
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stack<pair<char,int>> st;
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for(int i=0;i<s.size();i++){
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if(s[i]=='('){
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st.push(make_pair(s[i],i));
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}elseif(s[i]==')'){
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if(!st.empty()and st.top().first=='('){
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st.pop();
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}else{
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st.push(make_pair(')',i));
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}
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}
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}
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while(!st.empty()){
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s.erase(s.begin()+st.top().second);
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st.pop();
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}
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return s;
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}
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};

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