Medium

Implement the`myAtoi(string s)` function, which converts a string to a 32-bit signed integer.

Implement the`myAtoi(string s)` function, which converts a string to a 32-bit signed integer (similar to C/C++'s`atoi` function).

The algorithm for`myAtoi(string s)` is as follows:

1.**Whitespace**: Ignore any leading whitespace (`" "`).

2.**Signedness**: Determine the sign by checking if the next character is`'-'` or`'+'`, assuming positivity if neither present.

3.**Conversion**: Read the integer by skipping leading zeros until a non-digit character is encountered or the end of the string is reached. If no digits were read, then the result is 0.

4.**Rounding**: If the integer is out of the 32-bit signed integer range <code>[-2³¹, 2³¹ - 1]</code>, then round the integer to remain in the range. Specifically, integers less than <code>-2³¹</code> should be rounded to <code>-2³¹</code>, and integers greater than <code>2³¹ - 1</code> should be rounded to <code>2³¹ - 1</code>.

1. Read in and ignore any leading whitespace.

2. Check if the next character (if not already at the end of the string) is`'-'` or`'+'`. Read this character in if it is either. This determines if the final result is negative or positive respectively. Assume the result is positive if neither is present.

3. Read in next the characters until the next non-digit character or the end of the input is reached. The rest of the string is ignored.

4. Convert these digits into an integer (i.e.`"123" -> 123`,`"0032" -> 32`). If no digits were read, then the integer is`0`. Change the sign as necessary (from step 2).

5. If the integer is out of the 32-bit signed integer range <code>[-2³¹, 2³¹ - 1]</code>, then clamp the integer so that it remains in the range. Specifically, integers less than <code>-2³¹</code> should be clamped to <code>-2³¹</code>, and integers greater than <code>2³¹ - 1</code> should be clamped to <code>2³¹ - 1</code>.

6. Return the integer as the final result.

Return the integer as the final result.

**Note:**

* Only the space character`' '` is considered a whitespace character.

***Do not ignore** any characters other than the leading whitespace or the rest of the string after the digits.

**Example 1:**

**Input:** s = "42"

**Output:** 42

**Explanation:**

**Explanation:** The underlined characters are what is read in, the caret is the current reader position.

The parsed integer is 42. Since 42 is in the range[-2³¹, 2³¹ - 1], the final result is 42.

**Example 2:**

**Input:** s = " -042"

**Input:** s = " -42"

**Output:**\-42

**Output:** -42

**Explanation:**

Since -42 is in the range[-2³¹, 2³¹ - 1], the final result is -42.

**Example 3:**

**Input:** s = "1337c0d3"

**Input:** s = "4193 with words"

**Output:**1337

**Output:**4193

**Explanation:**

Since 4193 is in the range[-2³¹, 2³¹ - 1], the final result is 4193.

**Example 4:**

**Input:** s = "0-1"

**Input:** s = "words and 987"

**Output:** 0

**Explanation:**

Since 0 is in the range[-2³¹, 2³¹ - 1], the final result is 0.

**Example 5:**

**Input:** s = "words and 987"

**Input:** s = "-91283472332"

**Output:**0

**Output:**-2147483648

**Explanation:**

Reading stops at the first non-digit character 'w'.

Since -91283472332 is less than the lower bound of the range[-2³¹, 2³¹ - 1], the final result is clamped to -2³¹ = -2147483648.

**Constraints:**

*`s` consists of English letters (lower-case and upper-case), digits (`0-9`),`' '`,`'+'`,`'-'`, and`'.'`.

To solve the String to Integer (atoi) problem in Java using a`Solution` class, we'll follow these steps:

}

This implementation provides a solution to the String to Integer (atoi) problem in Java.

**Constraints:**

*`s` consists of English letters (lower-case and upper-case), digits (`0-9`),`' '`,`'+'`,`'-'`, and`'.'`.

This implementation provides a solution to the String to Integer (atoi) problem in Java.