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remove unused var in function selectionSort()#6
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selectionSort()Original code example has an unused var temp. We can drop that var.````jsfunction selectionSort() { var min; for (var outer = 0; outer <= this.dataStore.length-2; ++outer) { min = outer; for (var inner = outer + 1; inner <= this.dataStore.length-1; ++inner) { if (this.dataStore[inner] < this.dataStore[min]) { min = inner; } } swap(this.dataStore, outer, min); }} ````We can drop the var min by moving swap into the inner for loop.````jsfunction selectionSort() { for (var outer = 0; outer <= this.dataStore.length-2; ++outer) { for (var inner = outer + 1; inner <= this.dataStore.length-1; ++inner) { if (this.dataStore[inner] < this.dataStore[outer]) { swap(this.dataStore, inner, outer); } } }} ````Sign up for freeto join this conversation on GitHub. Already have an account?Sign in to comment
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selectionSort()
Original code example has an unused var temp. We can drop that var.
We can drop the var min by moving swap into the if clause in inner for loop. I think this is better because otherwise even if outer and min is the same value, swap is called. It's a bit confusing.