The code below will never print 3, and should not be an if/else. I think it's confusing to new learners to include code that does not do what it suggests. This code prints "number is smaller than 5" for everything < 5 and for anything >=5 it prints "number greater than or equal to 3, but smaller than 5" for any other value.

let number =3;if number <5{println!("`number` is smaller than 5");}elseif number >=3{println!("`number` is greater than or equal to 3, but smaller than 5");}else{println!("`number` is smaller than 3");}

This should be changed to an example that actually requires the use of if else and does what it is supposed to do.