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Commit75dd8a2

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0704: Binary Search
1 parent40960d2 commit75dd8a2

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3 files changed

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3 files changed

+115
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‎0704-Binary_Search/main.js

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constnums=[-1,0,3,5,9,12];
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consttarget1=9;
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consttarget2=2;
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functionsearchUsingLCRC(nums,target){
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letmid,left=0,right=nums.length-1;
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while(left<=right){
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mid=left+((right-left)>>1);
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if(nums[mid]>target){
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right=mid-1;
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}
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elseif(nums[mid]<target){
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left=mid+1;
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}
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else{
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returnmid;
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}
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}
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return-1;
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}
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functionsearchUsingLCRO(nums,target){
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letmid,left=0,right=nums.length;
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while(left<right){
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mid=left+((right-left)>>1);
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if(nums[mid]>target){
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right=mid;
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}
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elseif(nums[mid]<target){
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left=mid+1;
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}
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else{
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returnmid;
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}
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}
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return-1;
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}
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console.time("searchUsingLCRC");
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searchUsingLCRC(nums,target1);
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console.timeEnd("searchUsingLCRC");
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console.time("searchUsingLCRO");
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searchUsingLCRO(nums,target1);
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console.timeEnd("searchUsingLCRO");
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console.log(searchUsingLCRC(nums,target1));
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console.log(searchUsingLCRO(nums,target1));

‎0704-Binary_Search/main.ts

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constnums=[-1,0,3,5,9,12]
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consttarget1=9
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consttarget2=2
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functionsearchUsingLCRC(nums:number[],target:number):number{
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letmid:number,
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left:number=0,
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right:number=nums.length-1
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while(left<=right){
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mid=left+((right-left)>>1)
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if(nums[mid]>target){
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right=mid-1
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}elseif(nums[mid]<target){
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left=mid+1
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}else{
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returnmid
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}
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}
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return-1
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}
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functionsearchUsingLCRO(nums:number[],target:number):number{
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letmid:number,
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left:number=0,
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right:number=nums.length
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while(left<right){
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mid=left+((right-left)>>1)
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if(nums[mid]>target){
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right=mid
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}elseif(nums[mid]<target){
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left=mid+1
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}else{
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returnmid
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}
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}
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return-1
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}
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console.time("searchUsingLCRC")
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searchUsingLCRC(nums,target1)
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console.timeEnd("searchUsingLCRC")
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console.time("searchUsingLCRO")
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searchUsingLCRO(nums,target1)
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console.timeEnd("searchUsingLCRO")
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console.log(searchUsingLCRC(nums,target1))
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console.log(searchUsingLCRO(nums,target1))

‎0704-Binary_Search/readme.md

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Given an array of integers`nums` which is sorted in ascending order, and an integer`target`, write a function to search`target` in`nums`. If`target` exists, then return its index. Otherwise, return`-1`.
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You must write an algorithm with`O(log n)` runtime complexity.
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Example 1:
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><spanstyle="color:white;">Input</span>: nums =[-1,0,3,5,9,12], target = 9<br>
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><spanstyle="color:white;">Output</span>: 4<br>
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><spanstyle="color:white;">Explanation</span>: 9 exists in nums and its index is 4
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Example 2:
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><spanstyle="color:white;">Input</span>: nums =[-1,0,3,5,9,12], target = 2<br>
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><spanstyle="color:white;">Output</span>: -1<br>
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><spanstyle="color:white;">Explanation</span>: 2 does not exist in nums so return -1
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Constraints:
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- 1 <= nums.length <= 10<sup>4</sup>
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- -10<sup>4</sup> < nums[i], target < 10<sup>4</sup>
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- All the integers in`nums` are unique.
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-`nums` is sorted in ascending order.

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