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0344: Reverse String (#1)

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Lines changed: 28 additions & 0 deletions

Original file line number	Diff line number	Diff line change
`@@ -0,0 +1,28 @@`
	`1`	`+letstrArray1=["h","e","l","l","o"];`
	`2`	`+letstrArray2=["H","a","n","n","a","h"];`
	`3`	`+functionreverseStringUsingDestructuring(s){`
	`4`	`+letleft=0;`
	`5`	`+letright=s.length-1;`
	`6`	`+while(left<right){`
	`7`	`+;`
	`8`	`+[s[left],s[right]]=[s[right],s[left]];`
	`9`	`+left++;`
	`10`	`+right--;`
	`11`	`+}`
	`12`	`+}`
	`13`	`+functionreverseStringUsingTempVariable(s){`
	`14`	`+letlength=s.length;`
	`15`	`+letleft=0,right=length-1;`
	`16`	`+lettempStr;`
	`17`	`+while(left<right){`
	`18`	`+tempStr=s[left];`
	`19`	`+s[left]=s[right];`
	`20`	`+s[right]=tempStr;`
	`21`	`+left++;`
	`22`	`+right--;`
	`23`	`+}`
	`24`	`+}`
	`25`	`+reverseStringUsingDestructuring(strArray1);`
	`26`	`+reverseStringUsingTempVariable(strArray2);`
	`27`	`+console.log(strArray1);`
	`28`	`+console.log(strArray2);`

Lines changed: 32 additions & 0 deletions

Original file line number	Diff line number	Diff line change
`@@ -0,0 +1,32 @@`
	`1`	`+letstrArray1=["h","e","l","l","o"]`
	`2`	`+letstrArray2=["H","a","n","n","a","h"]`
	`3`	`+`
	`4`	`+functionreverseStringUsingDestructuring(s:string[]):void{`
	`5`	`+letleft=0`
	`6`	`+letright=s.length-1`
	`7`	`+while(left<right){`
	`8`	`+;[s[left],s[right]]=[s[right],s[left]]`
	`9`	`+left++`
	`10`	`+right--`
	`11`	`+}`
	`12`	`+}`
	`13`	`+`
	`14`	`+functionreverseStringUsingTempVariable(s:string[]):void{`
	`15`	`+letlength:number=s.length`
	`16`	`+letleft:number=0,`
	`17`	`+right:number=length-1`
	`18`	`+lettempStr:string`
	`19`	`+while(left<right){`
	`20`	`+tempStr=s[left]`
	`21`	`+s[left]=s[right]`
	`22`	`+s[right]=tempStr`
	`23`	`+left++`
	`24`	`+right--`
	`25`	`+}`
	`26`	`+}`
	`27`	`+`
	`28`	`+reverseStringUsingDestructuring(strArray1)`
	`29`	`+reverseStringUsingTempVariable(strArray2)`
	`30`	`+`
	`31`	`+console.log(strArray1)`
	`32`	`+console.log(strArray2)`

Lines changed: 18 additions & 0 deletions

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`@@ -0,0 +1,18 @@`
	`1`	`+Write a function that reverses a string. The input string is given as an array of characters s.`
	`2`	`+`
	`3`	`+You must do this by modifying the input array[in-place](https://en.wikipedia.org/wiki/In-place_algorithm) with O(1) extra memory.`
	`4`	`+`
	`5`	`+Example 1:`
	`6`	`+`
	`7`	`+>Input: s =["h","e","l","l","o"]<br>`
	`8`	`+>Output:["o","l","l","e","h"]`
	`9`	`+`
	`10`	`+Example 2:`
	`11`	`+`
	`12`	`+>Input: s =["H","a","n","n","a","h"]<br>`
	`13`	`+>Output:["h","a","n","n","a","H"]`
	`14`	`+`
	`15`	`+Constraints:`
	`16`	`+`
	`17`	`+- 1 <= s.length <= 105`
	`18`	`+- s[i] is a[printable ascii character](https://en.wikipedia.org/wiki/ASCII#Printable_characters).`

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