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Commite20d6c1

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add: Longest Substring Without Repeating Characters
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‎README.md

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@@ -8,6 +8,7 @@ This is the solution collection of my LeetCode problems, most of them are progra
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|---| -----| --------| ----------|
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|1|[Two Sum](https://leetcode.com/problems/two-sum/)|[JavaScript](./src/two-sum/res.js)|Easy|
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|2|[Add Two Numbers](https://leetcode.com/problems/add-two-numbers/)|[JavaScript](./src/add-two-numbers/res.js)|Medium|
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|3|[Longest Substring Without Repeating Characters](https://leetcode.com/problems/longest-substring-without-repeating-characters/)|[JavaScript](./src/longest-substring-without-repeating-characters/res.js)|Medium|
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|7|[Reverse Integer](https://leetcode.com/problems/reverse-integer/)|[JavaScript](./src/reverse-integer/res.js)|Easy|
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|13|[Roman to Integer](https://leetcode.com/problems/roman-to-integer/)|[JavaScript](./src/roman-to-integer/res.js)|Easy|
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|19|[Remove Nth Node From End of List](https://leetcode.com/problems/remove-nth-node-from-end-of-list/)|[JavaScript](./src/remove-nth-node-from-end-of-list/res.js)|Medium|
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/**
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* Given a string, find the length of the longest substring without repeating characters.
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*
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* Examples:
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*
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* Given "abcabcbb", the answer is "abc", which the length is 3.
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*
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* Given "bbbbb", the answer is "b", with the length of 1.
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*
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* Given "pwwkew", the answer is "wke", with the length of 3. Note that the answer must be a substring, "pwke" is a subsequence and not a substring.
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*
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* res.js
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*@authors Joe Jiang (hijiangtao@gmail.com)
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*@date 2017-02-27 20:52:27
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*@version $Id$
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*
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*@param {string} s
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*@return {number}
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*/
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letlengthOfLongestSubstring=function(s){
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letstrlen=s.length;
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// 字符串长度小于2
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if(strlen<2){
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returnstrlen;
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}
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letmaxString='',maxLen=1;
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for(leti=0;i<strlen;i++){
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letsubstr=[s[i]],continueJud=false;
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// 剩余字符串即使全部不重复也不可能长于现有最长的字符串
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if(strlen-i<=maxLen){
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break;
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}
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// 如果遇到连续相等的字符，则跳到本次连续出现的最后一个该字符上
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while(i+1<strlen&&s[i]===s[i+1]){
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i+=1;
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continueJud=true;
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}
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if(continueJud){
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continueJud=false;
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i-=1;
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continue;
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}
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// 从第二个字符开始遍历，直到字符串结尾或者出现重复字符的情况
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for(letj=i+1;j<strlen;j++){
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if(substr.indexOf(s[j])!==-1){
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if(substr.length>maxLen){
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maxLen=substr.length;
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// maxString = ''.join(substr);
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}
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break;
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}
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substr.push(s[j]);
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if(j===strlen-1){
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if(substr.length>maxLen){
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maxLen=substr.length;
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}
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}
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}
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}
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returnmaxLen;
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};

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