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Commit4f4f837

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add: Spiral Matrix
1 parent05d5d3a commit4f4f837

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‎README.md

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@@ -22,6 +22,7 @@ This is the solutions collection of my LeetCode submissions, most of them are pr
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|33|[Search in Rotated Sorted Array](https://leetcode.com/problems/search-in-rotated-sorted-array/)|[JavaScript](./src/search-in-rotated-sorted-array/res.js)|Medium|
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|34|[Search for a Range](https://leetcode.com/problems/search-for-a-range/)|[JavaScript](./src/search-for-a-range/res.js)|Medium|
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|48|[Rotate Image](https://leetcode.com/problems/rotate-image/)|[JavaScript](./src/rotate-image/res.js)|Medium|
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|54|[Spiral Matrix](https://leetcode.com/problems/spiral-matrix/)|[JavaScript](./src/spiral-matrix/res.js)|Medium|
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|66|[Plus One](https://leetcode.com/problems/plus-one/)|[JavaScript](./src/plus-one/res.js)|Easy|
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|69|[Sqrt(x)](https://leetcode.com/problems/sqrtx/)|[JavaScript](./src/sqrtx/res.js)|Easy|
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|73|[Set Matrix Zeroes](https://leetcode.com/problems/set-matrix-zeroes/)|[JavaScript](./src/set-matrix-zeroes/res.js)|Medium|

‎src/spiral-matrix/res.js

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/**
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* Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
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*
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* For example,
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*
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* Given the following matrix:
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* [
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* [ 1, 2, 3 ],
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* [ 4, 5, 6 ],
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* [ 7, 8, 9 ]
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* ]
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*
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* You should return [1,2,3,6,9,8,7,4,5].
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*
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* res.js
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*@authors Joe Jiang (hijiangtao@gmail.com)
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*@date 2017-03-03 21:42:58
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*@version $Id$
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*
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*@param {number[][]} matrix
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*@return {number[]}
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*/
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letspiralOrder=function(matrix){
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if(matrix.length===0){
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returnmatrix;
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}
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letrowBegin=0,
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rowEnd=matrix.length-1,
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colBegin=0,
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colEnd=matrix[0].length-1,
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res=[];
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while(rowBegin<=rowEnd||colBegin<=colEnd){
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// left->right
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for(leti=colBegin;i<=colEnd;i++){
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res.push(matrix[rowBegin][i]);
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}
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if(rowBegin===rowEnd){
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break;
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}
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// right->bottom
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rowBegin++;
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for(leti=rowBegin;i<=rowEnd;i++){
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res.push(matrix[i][colEnd]);
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}
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if(colBegin===colEnd){
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break;
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}
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// bottom->left
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colEnd--;
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for(leti=colEnd;i>=colBegin;i--){
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res.push(matrix[rowEnd][i]);
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}
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if(rowBegin===rowEnd){
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break;
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}
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// left bottom->top
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rowEnd--;
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for(leti=rowEnd;i>=rowBegin;i--){
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res.push(matrix[i][colBegin]);
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}
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if(colBegin===colEnd){
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break;
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}
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colBegin++;
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}
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returnres;
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};

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