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Commita234003

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TheKarlo95trekhleb
authored andcommitted
Add fibonnaci sequence closed form function (trekhleb#130)
* Add fibonnaci sequence closed form function* Revert package-lock.json
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importfibonacciClosedFormfrom'../fibonacciClosedForm';
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describe('fibonacciClosedForm',()=>{
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it('should calculate fibonacci correctly',()=>{
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expect(fibonacciClosedForm(1)).toBe(1);
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expect(fibonacciClosedForm(2)).toBe(1);
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expect(fibonacciClosedForm(3)).toBe(2);
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expect(fibonacciClosedForm(4)).toBe(3);
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expect(fibonacciClosedForm(5)).toBe(5);
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expect(fibonacciClosedForm(6)).toBe(8);
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expect(fibonacciClosedForm(7)).toBe(13);
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expect(fibonacciClosedForm(8)).toBe(21);
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expect(fibonacciClosedForm(20)).toBe(6765);
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expect(fibonacciClosedForm(30)).toBe(832040);
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expect(fibonacciClosedForm(50)).toBe(12586269025);
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expect(fibonacciClosedForm(70)).toBe(190392490709135);
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expect(fibonacciClosedForm(71)).toBe(308061521170129);
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expect(fibonacciClosedForm(72)).toBe(498454011879264);
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expect(fibonacciClosedForm(73)).toBe(806515533049393);
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expect(fibonacciClosedForm(74)).toBe(1304969544928657);
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expect(fibonacciClosedForm(75)).toBe(2111485077978050);
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});
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});
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/**
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* Calculate fibonacci number at specific position using closed form function.
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*
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*@param n n-th number of fibonacci sequence (must be number from 1(inclusive) to 75(inclusive))
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*@return {number}
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*/
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exportdefaultfunctionfibonacciClosedForm(n){
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constsqrt5=Math.sqrt(5);
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constphi=(1+sqrt5)/2;
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returnMath.floor((phi**n)/sqrt5+0.5);
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}

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