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Commitb73ddec

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Add Pascal's Triangle based solution for Unique Paths problem.
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‎README.md

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*`B`[Tower of Hanoi](src/algorithms/uncategorized/hanoi-tower)
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*`B`[Square Matrix Rotation](src/algorithms/uncategorized/square-matrix-rotation) - in-place algorithm
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*`B`[Jump Game](src/algorithms/uncategorized/jump-game) - backtracking, dynamic programming (top-down + bottom-up) and greedy examples
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*`B`[Unique Paths](src/algorithms/uncategorized/unique-paths) - backtracking anddynamic programming examples
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*`B`[Unique Paths](src/algorithms/uncategorized/unique-paths) - backtracking,dynamic programming and Pascal's Triangle based examples
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*`A`[N-Queens Problem](src/algorithms/uncategorized/n-queens)
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*`A`[Knight's Tour](src/algorithms/uncategorized/knight-tour)
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‎src/algorithms/uncategorized/unique-paths/README.md

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**Auxiliary Space Complexity**:`O(m * n)` - since we need to have DP matrix.
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###Pascal's Triangle Based
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This question is actually another form of Pascal Triangle.
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The corner of this rectangle is at`m + n - 2` line, and
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at`min(m, n) - 1` position of the Pascal's Triangle.
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##References
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-[LeetCode](https://leetcode.com/problems/unique-paths/description/)
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importuniquePathsfrom'../uniquePaths';
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describe('uniquePaths',()=>{
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it('should find the number of unique paths on board',()=>{
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expect(uniquePaths(3,2)).toBe(3);
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expect(uniquePaths(7,3)).toBe(28);
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expect(uniquePaths(3,7)).toBe(28);
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expect(uniquePaths(10,10)).toBe(48620);
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expect(uniquePaths(100,1)).toBe(1);
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expect(uniquePaths(1,100)).toBe(1);
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});
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});
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importpascalTrianglefrom'../../math/pascal-triangle/pascalTriangle';
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/**
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*@param {number} width
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*@param {number} height
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*@return {number}
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*/
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exportdefaultfunctionuniquePaths(width,height){
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constpascalLine=width+height-2;
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constpascalLinePosition=Math.min(width,height)-1;
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returnpascalTriangle(pascalLine)[pascalLinePosition];
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}

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