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Commitb9b46bc

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author
applewjg
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path sum2
Change-Id: I53f9100815f68d914630525e4dd897f3b9715757
1 parentbd9d3f6 commitb9b46bc

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‎PathSum2.java

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/*
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Author: King, higuige@gmail.com
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Date: Oct 7, 2014
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Problem: Path Sum 2
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Difficulty: easy
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Source: https://oj.leetcode.com/problems/path-sum-ii/
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Notes:
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Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
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For example:
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Given the below binary tree and sum = 22,
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5
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/ \
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4 8
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/ / \
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11 13 4
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/ \ / \
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7 2 5 1
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return
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[
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[5,4,11,2],
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[5,8,4,5]
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]
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Solution: DFS.
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*/
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/**
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* Definition for binary tree
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* public class TreeNode {
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* int val;
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* TreeNode left;
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* TreeNode right;
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* TreeNode(int x) { val = x; }
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* }
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*/
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publicclassSolution {
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publicList<List<Integer>>pathSum(TreeNoderoot,intsum) {
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List<List<Integer>>res =newArrayList<List<Integer>>();
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ArrayList<Integer>path =newArrayList<Integer>();
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pathSumRe(root,sum,res,path);
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returnres;
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}
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publicvoidpathSumRe(TreeNoderoot,intsum,List<List<Integer>>res,ArrayList<Integer>path)
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{
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if (root ==null)return;
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path.add(root.val);
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if (root.left ==null &&root.right ==null &&root.val ==sum){
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ArrayList<Integer>tmp =newArrayList<Integer>(path);
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res.add(tmp);
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}
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pathSumRe(root.left,sum -root.val,res,path);
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pathSumRe(root.right,sum -root.val,res,path);
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path.remove(path.size()-1);
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}
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}
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