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Commit8688eac

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author
applewjg
committed
ValidSudoku
Change-Id: Ib833015581798bf95f546e0370340732a0e0cb12
1 parentea5ff4f commit8688eac

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‎ValidSudoku.java

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/*
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Author: King, wangjingui@outlook.com
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Date: Dec 20, 2014
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Problem: Valid Sudoku
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Difficulty: Easy
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Source: https://oj.leetcode.com/problems/valid-sudoku/
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Notes:
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Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules (http://sudoku.com.au/TheRules.aspx).
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The Sudoku board could be partially filled, where empty cells are filled with the character '.'.
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Solution: 1. Traverse the Sudoku only once.
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2. Bit manipulation. Use only one bit to represent a number. Space: sizeof(int) * (1+9+9).
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*/
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publicclassSolution {
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publicbooleanisValidSudoku(char[][]board) {
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boolean[]used =newboolean[9];
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for(inti=0;i<9;i++){
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Arrays.fill(used,false);
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for(intj =0;j<9;j++){
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if(check(board[i][j],used)==false)returnfalse;
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}
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Arrays.fill(used,false);
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for(intj =0;j<9;j++){
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if(check(board[j][i],used)==false)returnfalse;
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}
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}
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for(intr =0;r<3;r++){
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for(intc =0;c<3;c++){
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Arrays.fill(used,false);
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for(inti =r*3;i<r*3+3;i++){
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for(intj =c*3;j<c*3+3;j++){
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if(check(board[i][j],used)==false)returnfalse;
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}
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}
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}
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}
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returntrue;
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}
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booleancheck(charch,boolean[]used){
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if(ch=='.')returntrue;
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if(used[ch-'1'])returnfalse;
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used[ch-'1']=true;
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returntrue;
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}
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}

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