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LengthofLastWord

Change-Id: I3db3c8b5e2ffbfcb06f1c74d9ff6020362b93041

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	`1`	`+/*`
	`2`	`+ Author: King, wangjingui@outlook.com`
	`3`	`+ Date: Dec 25, 2014`
	`4`	`+ Problem: Length of Last Word`
	`5`	`+ Difficulty: Easy`
	`6`	`+ Source: https://oj.leetcode.com/problems/length-of-last-word/`
	`7`	`+ Notes:`
	`8`	`+ Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.`
	`9`	`+ If the last word does not exist, return 0.`
	`10`	`+ Note: A word is defined as a character sequence consists of non-space characters only.`
	`11`	`+ For example,`
	`12`	`+ Given s = "Hello World",`
	`13`	`+ return 5.`
	`14`	`+`
	`15`	`+ Solution: ...`
	`16`	`+ */`
	`17`	`+publicclassSolution {`
	`18`	`+publicintlengthOfLastWord(Strings) {`
	`19`	`+intres =0,i =s.length() -1;`
	`20`	`+while (i >=0 &&s.charAt(i) ==' ') --i;`
	`21`	`+while (i >=0 &&s.charAt(i) !=' ') {`
	`22`	`+ --i; ++res;`
	`23`	`+ }`
	`24`	`+returnres;`
	`25`	`+ }`
	`26`	`+}`

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