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‎leetcode-algorithms/README.md

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| # | Title | Solutions | Time | Space | Difficulty | Tag | Notes
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|-----|----------------|---------------|---------------|---------------|-------------|--------------|-----
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|557|[Reverse Words in a String III](https://leetcode.com/problems/reverse-words-in-a-string-iii/)|[Solution](../../master/leetcode-algorithms/src/main/java/com/stevesun/solutions/ReverseWordsinaStringIII.java) | O(n) |O(n) | Easy | String
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|554|[Brick Wall](https://leetcode.com/problems/brick-wall/)|[Solution](../../master/leetcode-algorithms/src/main/java/com/stevesun/solutions/BrickWall.java) | O(n) (n is total number of bricks in the wall) |O(m) (m is width of the wall) | Medium | HashMap
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|548|[Split Array with Equal Sum](https://leetcode.com/problems/split-array-with-equal-sum/)|[Solution](../../master/leetcode-algorithms/src/main/java/com/stevesun/solutions/SplitArraywithEqualSum.java) | O(n^2) |O(1) | Medium | Array
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|547|[Friend Circles](https://leetcode.com/problems/friend-circles/)|[Solution](../../master/leetcode-algorithms/src/main/java/com/stevesun/solutions/FriendCircles.java) | O(n^2) |O(n) | Medium | Union Find
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|545|[Boundary of Binary Tree](https://leetcode.com/problems/boundary-of-binary-tree/)|[Solution](../../master/leetcode-algorithms/src/main/java/com/stevesun/solutions/BoundaryofBinaryTree.java) | O(n) |O(n) | Medium | Recursion
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packagecom.stevesun.solutions;
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importjava.util.HashMap;
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importjava.util.List;
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importjava.util.Map;
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/**
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* There is a brick wall in front of you. The wall is rectangular and has several rows of bricks. The bricks have the same height but different width. You want to draw a vertical line from the top to the bottom and cross the least bricks.
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The brick wall is represented by a list of rows. Each row is a list of integers representing the width of each brick in this row from left to right.
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If your line go through the edge of a brick, then the brick is not considered as crossed. You need to find out how to draw the line to cross the least bricks and return the number of crossed bricks.
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You cannot draw a line just along one of the two vertical edges of the wall, in which case the line will obviously cross no bricks.
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Example:
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Input:
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[[1,2,2,1],
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[3,1,2],
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[1,3,2],
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[2,4],
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[3,1,2],
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[1,3,1,1]]
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Output: 2
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Explanation:
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Note:
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The width sum of bricks in different rows are the same and won't exceed INT_MAX.
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The number of bricks in each row is in range [1,10,000]. The height of wall is in range [1,10,000]. Total number of bricks of the wall won't exceed 20,000.
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*/
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publicclassBrickWall {
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//credit to: https://leetcode.com/articles/brick-wall/
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/**we make use of a HashMap
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map which is used to store entries in the form:
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(sum,count). Here,
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sum refers to the cumulative sum of the bricks' widths encountered in the current row, and
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count refers to the number of times the corresponding sum is obtained. Thus,
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sum in a way, represents the positions of the bricks's boundaries relative to the leftmost boundary.
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This is done based on the following observation:
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We will never obtain the same value of sum twice while traversing over a particular row.
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Thus, if the sum value is repeated while traversing over the rows, it means some row's brick boundary coincides with some previous row's brick boundary.
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This fact is accounted for by incrementing the corresponding count value.
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But, for every row, we consider the sum only upto the second last brick, since the last boundary isn't a valid boundary for the solution.*/
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publicintleastBricks(List<List<Integer>>wall) {
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Map<Integer,Integer>map =newHashMap();
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for (List<Integer>row :wall) {
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intsum =0;
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for (inti =0;i <row.size()-1;i++) {//NOTE: i < row.size()-1
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sum +=row.get(i);
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if (map.containsKey(sum))map.put(sum,map.get(sum)+1);
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elsemap.put(sum,1);
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}
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}
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intresult =wall.size();
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for (intkey :map.keySet()) {
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result =Math.min(result,wall.size() -map.get(key));
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}
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returnresult;
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}
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}
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packagecom.stevesun;
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importcom.stevesun.solutions.BrickWall;
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importorg.junit.Before;
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importorg.junit.BeforeClass;
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importorg.junit.Test;
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importjava.util.ArrayList;
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importjava.util.Arrays;
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importjava.util.List;
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importstaticjunit.framework.Assert.assertEquals;
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publicclassBrickWallTest {
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privatestaticBrickWalltest;
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privatestaticintexpected;
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privatestaticintactual;
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privatestaticList<List<Integer>>wall;
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@BeforeClass
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publicstaticvoidsetup(){
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test =newBrickWall();
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}
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@Before
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publicvoidsetupForEachTest(){}
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@Test
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publicvoidtest1(){
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wall =newArrayList<>();
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wall.add(Arrays.asList(1,2,2,1));
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wall.add(Arrays.asList(3,1,2));
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wall.add(Arrays.asList(1,3,2));
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wall.add(Arrays.asList(2,4));
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wall.add(Arrays.asList(3,1,2));
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wall.add(Arrays.asList(1,3,1,1));
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expected =2;
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actual =test.leastBricks(wall);
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assertEquals(expected,actual);
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}
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}

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