Movatterモバイル変換


[0]ホーム

URL:


Skip to content

Navigation Menu

Sign in
Appearance settings

Search code, repositories, users, issues, pull requests...

Provide feedback

We read every piece of feedback, and take your input very seriously.

Saved searches

Use saved searches to filter your results more quickly

Sign up
Appearance settings

Commit582496e

Browse files
committed
[Function add]
1. Add leetcode solutions using C++;
1 parentec7eead commit582496e

4 files changed

+227
-1
lines changed

‎leetcode/22. Generate Parentheses.md

Lines changed: 20 additions & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -127,4 +127,24 @@ class Solution {
127127
}
128128
}
129129
}
130+
```
131+
132+
###C++ Version
133+
* Method 1: traceback with restriction
134+
```objectivec
135+
class Solution {
136+
private:
137+
void dfs(int left, int right, string s){
138+
if(left == 0 && right == 0) res_.emplace_back(s);
139+
if(left > 0) dfs(left - 1, right, s + "(");
140+
if(right > left) dfs(left, right - 1, s + ")");
141+
}
142+
vector<string> res_;
143+
public:
144+
vector<string> generateParenthesis(int n) {
145+
if(!n) return res_;
146+
dfs(n, n, "");
147+
return res_;
148+
}
149+
};
130150
```

‎leetcode/301. Remove Invalid Parentheses.md

Lines changed: 50 additions & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -128,5 +128,55 @@ class Solution {
128128
}
129129
```
130130

131+
###C++ Version
132+
* Method 1: dfs
133+
```objectivec
134+
class Solution {
135+
private:
136+
pair<int, int> checkParentheses(string s){
137+
const int n = s.length();
138+
int l = 0, r = 0;
139+
for(int i = 0; i < n; ++i){
140+
if(isalpha(s[i])) continue;
141+
else if(s[i] == '(') l++;
142+
else{
143+
if(l <= 0) r++;
144+
else l--;
145+
}
146+
}
147+
pair<int, int> p(l, r);
148+
return p;
149+
}
150+
vector<string> res_;
151+
bool valid(string s){
152+
int l = 0, r = 0;
153+
for(const char& c : s){
154+
if(c == '(') l++;
155+
else if(c == ')'){
156+
if(++r > l) return false;
157+
}
158+
}
159+
return l == r;
160+
}
161+
void dfs(int l, int r, string s, int index){
162+
if(l == 0 && r == 0 && valid(s)) res_.emplace_back(s);
163+
for(int i = index; i < s.length(); ++i){
164+
if(isalpha(s[i]) || (i > 0 && s[i] == s[i - 1])) continue;
165+
if(r > 0 && s[i] == ')'){
166+
dfs(l, r - 1, s.substr(0, i) + s.substr(i + 1), i);
167+
}else if(l > 0 && s[i] == '('){
168+
dfs(l - 1, r, s.substr(0, i) + s.substr(i + 1), i);
169+
}
170+
}
171+
}
172+
public:
173+
vector<string> removeInvalidParentheses(string s) {
174+
pair<int, int> p = checkParentheses(s);
175+
dfs(p.first, p.second, s, 0);
176+
return res_;
177+
}
178+
};
179+
```
180+
131181
###Reference
132182
1.[花花酱 LeetCode 301. Remove Invalid Parentheses - 刷题找工作 EP139](https://www.youtube.com/watch?v=2k_rS_u6EBk)

‎leetcode/943. Find the Shortest Superstring.md

Lines changed: 110 additions & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -87,7 +87,116 @@ Note:
8787
}
8888
```
8989

90-
*Method2:DPNeed to fill when doing the dp questions.
90+
###C++Version
91+
*Method1: brutal force
92+
```objectivec
93+
classSolution {
94+
public:
95+
stringshortestSuperstring(vector<string>&A) {
96+
constint n=A.size();
97+
g_= vector<vector<int>>(n, vector<int>(n));
98+
for(int f=0; f< n;++f){
99+
int flen=A[f].length();
100+
for(int s=0; s< n;++s){
101+
if(s== f)continue;
102+
int slen=A[s].length();
103+
g_[f][s]= slen;
104+
for(int i=1; i<= min(flen, slen);++i){
105+
if(A[f].substr(flen- i)==A[s].substr(0, i))
106+
g_[f][s]= slen- i;
107+
}
108+
}
109+
}
110+
vector<int> path(n);
111+
best_len_=INT_MAX;
112+
dfs(A,0,0,0, path);
113+
string res=A[path_[0]];
114+
for(int i=1; i< n;++i){
115+
int cur_len=A[path_[i]].length();
116+
res+=A[path_[i]].substr(cur_len- g_[path_[i-1]][path_[i]]);
117+
}
118+
return res;
119+
}
120+
private:
121+
vector<vector<int>> g_;
122+
vector<int> path_;
123+
int best_len_;
124+
125+
voiddfs(constvector<string>&A,intd,intcur_len,intused,vector<int>&path){
126+
if(cur_len>= best_len_)return;
127+
if(d==A.size()){
128+
best_len_= cur_len;
129+
path_= path;
130+
return;
131+
}
132+
for(int i=0; i<A.size();++i){
133+
if(used& (1<< i))continue;
134+
path[d]= i;
135+
dfs(A,
136+
d+1,
137+
d==0?A[i].length(): cur_len+ g_[path[d-1]][i],
138+
used| (1<< i),
139+
path);
140+
}
141+
}
142+
};
143+
```
144+
145+
*Method2:DP
146+
1. dp[s][j]: s is a visited set in binary form, j is the output of current state.
147+
2.Transition function: dp[s][j]= min(dp[s- (1<< j)][i]+ g[i][j])
148+
3. initialization: dp[1<< i][i]=A[i].length(), current string's length.
149+
4. final result: min(dp[2^n - 1][*]) with traceback.
150+
```objectivec
151+
class Solution {
152+
public:
153+
string shortestSuperstring(vector<string>& A) {
154+
const int n = A.size();
155+
vector<vector<int>> g(n, vector<int>(n));
156+
for(int f = 0; f < n; ++f){
157+
int flen = A[f].length();
158+
for(int s = 0; s < n; ++s){
159+
if(s == f) continue;
160+
int slen = A[s].length();
161+
g[f][s] = slen;
162+
for(int i = 1; i <= min(flen, slen); ++i){
163+
if(A[f].substr(flen - i) == A[s].substr(0, i))
164+
g[f][s] = slen - i;
165+
}
166+
}
167+
}
168+
vector<vector<int>> dp(1 << n, vector<int>(n, INT_MAX >> 1));
169+
vector<vector<int>> parent(1 << n, vector<int>(n, -1));
170+
for(int i = 0; i < n; ++i) dp[1 << i][i] = A[i].length();
171+
for(int s = 1; s < (1 << n); ++s){ // 访问的集合
172+
for(int j = 0; j < n; ++j){ // 最后的出口结点
173+
if(!(s & (1 << j))) continue;
174+
int ps = s & ~(1 << j);
175+
for(int i = 0; i < n; ++i){
176+
if(!(ps & (1 << i))) continue;
177+
if(dp[ps][i] + g[i][j] < dp[s][j]){
178+
dp[s][j] = dp[ps][i] + g[i][j];
179+
parent[s][j] = i;
180+
}
181+
}
182+
}
183+
}
184+
185+
auto it = min_element(begin(dp.back()), end(dp.back()));
186+
int j = it - begin(dp.back());
187+
int s = (1 << n) - 1;
188+
string res;
189+
while(s){
190+
int i = parent[s][j];
191+
if(i < 0) res = A[j] + res;
192+
else res = A[j].substr(A[j].length() - g[i][j]) + res;
193+
s &= ~(1 << j);
194+
j = i;
195+
}
196+
return res;
197+
}
198+
};
199+
```
91200
92201
### Reference
93202
1. [花花酱 LeetCode 943. Find the Shortest Superstring - 刷题找工作 EP231](https://www.youtube.com/watch?v=u_Wc4jwrp3Q)

‎leetcode/996. Number of Squareful Arrays.md

Lines changed: 47 additions & 0 deletions
Original file line numberDiff line numberDiff line change
@@ -174,6 +174,53 @@ Note:
174174
}
175175
```
176176

177+
###C++ version
178+
* Method 1: dp
179+
```objectivec
180+
class Solution {
181+
private:
182+
bool square(int x){
183+
int r = sqrt(x);
184+
return x == r * r;
185+
}
186+
vector<vector<int>> dp_; //dp[cur][state]
187+
188+
int dfs(vector<int>& A, int cur, int to_visit){
189+
if(dp_[cur][to_visit]) return dp_[cur][to_visit];
190+
else if(!to_visit) return 1;
191+
int copy = to_visit;
192+
int pre = -1, index = 0;
193+
while(copy){
194+
if((copy & 1) && square(A[cur] + A[index])){
195+
if(pre == A[index]){
196+
index ++;
197+
copy >>= 1;
198+
continue;
199+
}
200+
pre = A[index];
201+
dp_[cur][to_visit] += dfs(A, index, to_visit ^ (1 << index));
202+
}
203+
index++;
204+
copy >>= 1;
205+
}
206+
return dp_[cur][to_visit];
207+
}
208+
public:
209+
int numSquarefulPerms(vector<int>& A) {
210+
const int n = A.size();
211+
dp_ = vector<vector<int>>(n, vector<int>(1 << n, 0));
212+
sort(A.begin(), A.end());
213+
int res = 0;
214+
int fullstate = (1 << n) - 1;
215+
for(int i = 0; i < n; ++i){
216+
if(i > 0 && A[i] == A[i - 1]) continue;
217+
res += dfs(A, i, fullstate ^ (1 << i));
218+
}
219+
return res;
220+
}
221+
};
222+
```
223+
177224
###Reference
178225
1.[花花酱 LeetCode 996. Number of Squareful Arrays](https://zxi.mytechroad.com/blog/searching/leetcode-996-number-of-squareful-arrays/)
179226

0 commit comments

Comments
 (0)

[8]ページ先頭

©2009-2025 Movatter.jp