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	`1`	`+/**`
	`2`	`+Given a date, return the corresponding day of the week for that date.`
	`3`	`+`
	`4`	`+The input is given as three integers representing the day, month and year respectively.`
	`5`	`+`
	`6`	`+Return the answer as one of the following values {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}.`
	`7`	`+`
	`8`	`+`
	`9`	`+`
	`10`	`+Example 1:`
	`11`	`+`
	`12`	`+Input: day = 31, month = 8, year = 2019`
	`13`	`+Output: "Saturday"`
	`14`	`+Example 2:`
	`15`	`+`
	`16`	`+Input: day = 18, month = 7, year = 1999`
	`17`	`+Output: "Sunday"`
	`18`	`+`
	`19`	`+*/`
	`20`	`+package main`
	`21`	`+`
	`22`	`+import (`
	`23`	`+"fmt"`
	`24`	`+"time"`
	`25`	`+)`
	`26`	`+`
	`27`	`+funcdayOfTheWeek(dayint,monthint,yearint)string {`
	`28`	`+t:=time.Date(year,time.Month(month),day,0,0,0,0,time.UTC)`
	`29`	`+returnt.Weekday().String()`
	`30`	`+}`
	`31`	`+`
	`32`	`+funcmain() {`
	`33`	`+str:=dayOfTheWeek(31,8,2019)`
	`34`	`+fmt.Println(str)`
	`35`	`+}`
	`36`	`+`
	`37`	`+/**`
	`38`	`+note:use golang intern function`
	`39`	`+*/`

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	`1`	`+/**`
	`2`	`+Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is unique.`
	`3`	`+`
	`4`	`+`
	`5`	`+`
	`6`	`+Example 1:`
	`7`	`+`
	`8`	`+Input: arr = [1,2,2,1,1,3]`
	`9`	`+Output: true`
	`10`	`+Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences.`
	`11`	`+Example 2:`
	`12`	`+`
	`13`	`+Input: arr = [1,2]`
	`14`	`+Output: false`
	`15`	`+`
	`16`	`+*/`
	`17`	`+package main`
	`18`	`+`
	`19`	`+funcuniqueOccurrences(arr []int)bool {`
	`20`	`+counts:=make(map[int]int)`
	`21`	`+for_,i:=rangearr {`
	`22`	`+counts[i]+=1`
	`23`	`+}`
	`24`	`+set:=make(map[int]bool)`
	`25`	`+for_,c:=rangecounts {`
	`26`	`+if_,ok:=set[c];ok {`
	`27`	`+returnfalse`
	`28`	`+}`
	`29`	`+set[c]=true`
	`30`	`+}`
	`31`	`+returntrue`
	`32`	`+}`

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	`1`	`+/**`
	`2`	`+Balanced strings are those who have equal quantity of 'L' and 'R' characters.`
	`3`	`+`
	`4`	`+Given a balanced string s split it in the maximum amount of balanced strings.`
	`5`	`+`
	`6`	`+Return the maximum amount of splitted balanced strings.`
	`7`	`+`
	`8`	`+`
	`9`	`+`
	`10`	`+Example 1:`
	`11`	`+`
	`12`	`+Input: s = "RLRRLLRLRL"`
	`13`	`+Output: 4`
	`14`	`+Explanation: s can be split into "RL", "RRLL", "RL", "RL", each substring contains same number of 'L' and 'R'.`
	`15`	`+Example 2:`
	`16`	`+`
	`17`	`+Input: s = "RLLLLRRRLR"`
	`18`	`+Output: 3`
	`19`	`+Explanation: s can be split into "RL", "LLLRRR", "LR", each substring contains same number of 'L' and 'R'.`
	`20`	`+`
	`21`	`+*/`
	`22`	`+package main`
	`23`	`+`
	`24`	`+funcbalancedStringSplit(sstring)int {`
	`25`	`+varsum,resint`
	`26`	`+for_,c:=ranges {`
	`27`	`+ifc=='R' {`
	`28`	`+sum+=1`
	`29`	`+}else {`
	`30`	`+sum-=1`
	`31`	`+}`
	`32`	`+ifsum==0 {`
	`33`	`+res+=1`
	`34`	`+}`
	`35`	`+}`
	`36`	`+returnres`
	`37`	`+}`

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