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Valid Palindrome#2
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can you check it and merge it@NirmalSilwal ? |
Hi@ifenil, could you add another approach or more optimized solution. That would be better PR if you are considering hactoberfest. |
ifenil commentedOct 3, 2020 • edited
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@NirmalSilwal , |
javadev commentedMar 17, 2022
The alternative solution publicclassSolution {publicbooleanisPalindrome(Strings) {inti =0;intj =s.length() -1;booleanres =true;while (res) {// Iterates through string to find first char which is alphanumeric.// Done to ignore non-alphanumeric characters.// Starts from 0 to j-1.while (i <j &&isNotAlphaNumeric(s.charAt(i))) {i++; }// Similarly from j-1 to 0.while (i <j &&isNotAlphaNumeric(s.charAt(j))) {j--; }// Checks if i is greater than or equal to j.// The main loop only needs to loop n / 2 times hence this condition (where n is string// length).if (i >=j) {break; }// Assigning found indices to variables.// The upperToLower function is used to convert characters, if upper case, to lower// case.// If already lower case, it'll return as it is.charleft =upperToLower(s.charAt(i));charright =upperToLower(s.charAt(j));// If both variables are not same, result becomes false, and breaks out of the loop at// next iteration.if (left !=right) {res =false; }i++;j--; }returnres; }privatebooleanisNotAlphaNumeric(charc) {return (c <'a' ||c >'z') && (c <'A' ||c >'Z') && (c <'0' ||c >'9'); }privatebooleanisUpper(charc) {returnc >='A' &&c <='Z'; }privatecharupperToLower(charc) {if (isUpper(c)) {c = (char) (c +32); }returnc; }} |
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My solution to the problem. Missing some edge cases(which can be added later).
publicclassPalindrome {publicstaticvoidmain(String[]args) {Scannerinput =newScanner(System.in);System.out.print("Please enter the string: ");Stringstr =input.nextLine();input.close();inti =0;intj =str.length() -1;while (i <j) {if (str.charAt(i) ==str.charAt(j)) {i++;j--; }else {System.out.printf("The string %s is not a Palindrome.\n",str);return; } }System.out.printf("The string %s is a Palindrome.\n",str); }}
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Valid Palindeome From Leetcode August Challange ;
explanation of code line by line through comment;
easily understandable and simple code
it passed all the test cases;