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217. 存在重复元素 #88

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@Geekhyt

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@Geekhyt

原题链接

排序

排序后看相邻两位的数字

constcontainsDuplicate=function(nums){nums.sort((a,b)=>a-b)constn=nums.lengthfor(leti=0;i<n-1;i++){if(nums[i]===nums[i+1]){returntrue}}returnfalse}
  • 时间复杂度:O(nlogn)
  • 空间复杂度:O(logn)

哈希表

constcontainsDuplicate=function(nums){constset=newSet()for(constxofnums){if(set.has(x)){returntrue}set.add(x)}returnfalse}
  • 时间复杂度:O(n)
  • 空间复杂度:O(n)

一行代码

constcontainsDuplicate=function(nums){returnnewSet(nums).size!==nums.length}

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