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Triacontagon

From Wikipedia, the free encyclopedia
Polygon with 30 edges
Regular triacontagon
A regular triacontagon
TypeRegular polygon
Edges andvertices30
Schläfli symbol{30}, t{15}
Coxeter–Dynkin diagrams
Symmetry groupDihedral (D30), order 2×30
Internal angle (degrees)168°
PropertiesConvex,cyclic,equilateral,isogonal,isotoxal
Dual polygonSelf

Ingeometry, atriacontagon or 30-gon is a thirty-sidedpolygon. The sum of any triacontagon's interior angles is5040 degrees.

Regular triacontagon

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Theregular triacontagon is aconstructible polygon, by an edge-bisection of a regularpentadecagon, and can also be constructed as atruncatedpentadecagon, t{15}. Atruncated triacontagon, t{30}, is ahexacontagon, {60}.

One interior angle in aregular triacontagon is 168 degrees, meaning that one exterior angle would be 12°. The triacontagon is the largest regular polygon whose interior angle is the sum of theinterior angles of smallerpolygons: 168° is the sum of the interior angles of theequilateral triangle (60°) and theregular pentagon (108°).

Thearea of a regular triacontagon is (witht = edge length)[1]

A=152t2cotπ30=154t2(15+33+225+115){\displaystyle A={\frac {15}{2}}t^{2}\cot {\frac {\pi }{30}}={\frac {15}{4}}t^{2}\left({\sqrt {15}}+3{\sqrt {3}}+{\sqrt {2}}{\sqrt {25+11{\sqrt {5}}}}\right)}

Theinradius of a regular triacontagon is

r=12tcotπ30=14t(15+33+225+115){\displaystyle r={\frac {1}{2}}t\cot {\frac {\pi }{30}}={\frac {1}{4}}t\left({\sqrt {15}}+3{\sqrt {3}}+{\sqrt {2}}{\sqrt {25+11{\sqrt {5}}}}\right)}

Thecircumradius of a regular triacontagon is

R=12tcscπ30=12t(2+5+15+65){\displaystyle R={\frac {1}{2}}t\csc {\frac {\pi }{30}}={\frac {1}{2}}t\left(2+{\sqrt {5}}+{\sqrt {15+6{\sqrt {5}}}}\right)}

Construction

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Regular triacontagon with given circumcircle. D is the midpoint of AM, DC = DF, and CF, which is the side length of the regularpentagon, is E25E1. Since 1/30 = 1/5 - 1/6, the difference between the arcs subtended by the sides of a regular pentagon and hexagon (E25E1 and E25A) is that of the regular triacontagon, AE1.

As 30 = 2 × 3 × 5 , a regular triacontagon isconstructible using acompass and straightedge.[2]

Symmetry

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The symmetries of a regular triacontagon as shown with colors on edges and vertices. Lines of reflections are blue through vertices, and purple through edges. Gyrations are given as numbers in the center. Vertices are colored by their symmetry positions. Subgroup symmetries are connected by colored lines, index 2, 3, and 5.

Theregular triacontagon has Dih30dihedral symmetry, order 60, represented by 30 lines of reflection. Dih30 has 7 dihedral subgroups: Dih15, (Dih10, Dih5), (Dih6, Dih3), and (Dih2, Dih1). It also has eight morecyclic symmetries as subgroups: (Z30, Z15), (Z10, Z5), (Z6, Z3), and (Z2, Z1), with Zn representing π/n radian rotational symmetry.

John Conway labels these lower symmetries with a letter and order of the symmetry follows the letter.[3] He givesd (diagonal) with mirror lines through vertices,p with mirror lines through edges (perpendicular),i with mirror lines through both vertices and edges, andg for rotational symmetry.a1 labels no symmetry.

These lower symmetries allows degrees of freedoms in defining irregular triacontagons. Only theg30 subgroup has no degrees of freedom but can be seen asdirected edges.

Dissection

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30-gon with 420 rhombs

Coxeter states that everyzonogon (a 2m-gon whose opposite sides are parallel and of equal length) can be dissected intom(m-1)/2 parallelograms.[4]In particular this is true for regular polygons with evenly many sides, in which case the parallelograms are all rhombi. For theregular triacontagon,m=15, it can be divided into 105: 7 sets of 15 rhombs. This decomposition is based on aPetrie polygon projection of a15-cube.

Examples

Triacontagram

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A triacontagram is a 30-sidedstar polygon (though the word is extremely rare). There are 3 regular forms given bySchläfli symbols {30/7}, {30/11}, and {30/13}, and 11 compound star figures with the samevertex configuration.

Compounds and stars
FormCompoundsStar polygonCompound
Picture
{30/2}=2{15}

{30/3}=3{10}

{30/4}=2{15/2}

{30/5}=5{6}

{30/6}=6{5}

{30/7}

{30/8}=2{15/4}
Interior angle156°144°132°120°108°96°84°
FormCompoundsStar polygonCompoundStar polygonCompounds
Picture
{30/9}=3{10/3}

{30/10}=10{3}

{30/11}

{30/12}=6{5/2}

{30/13}

{30/14}=2{15/7}

{30/15}=15{2}
Interior angle72°60°48°36°24°12°

There are alsoisogonal triacontagrams constructed as deeper truncations of the regularpentadecagon {15} and pentadecagram {15/7}, and inverted pentadecagrams {15/11}, and {15/13}. Other truncations form double coverings: t{15/14}={30/14}=2{15/7}, t{15/8}={30/8}=2{15/4}, t{15/4}={30/4}=2{15/4}, and t{15/2}={30/2}=2{15}.[5]

Compounds and stars
QuasiregularIsogonalQuasiregular
Double coverings

t{15} = {30}

t{15/14}=2{15/7}

t{15/7}={30/7}

t{15/8}=2{15/4}

t{15/11}={30/11}

t{15/4}=2{15/2}

t{15/13}={30/13}

t{15/2}=2{15}

Petrie polygons

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The regular triacontagon is thePetrie polygon for three 8-dimensional polytopes with E8 symmetry, shown inorthogonal projections in the E8Coxeter plane. It is also the Petrie polygon for two 4-dimensional polytopes, shown in the H4Coxeter plane.

E8H4

421

241

142

120-cell

600-cell

The regular triacontagram {30/7} is also the Petrie polygon for thegreat grand stellated 120-cell andgrand 600-cell.

References

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  1. ^Weisstein, Eric W."Triacontagon".MathWorld.
  2. ^Constructible Polygon
  3. ^The Symmetries of Things, Chapter 20
  4. ^Coxeter, Mathematical recreations and Essays, Thirteenth edition, p.141
  5. ^The Lighter Side of Mathematics: Proceedings of the Eugène Strens Memorial Conference on Recreational Mathematics and its History, (1994),Metamorphoses of polygons,Branko Grünbaum
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