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Thermodynamic temperature, also known asabsolute temperature, is aphysical quantity that measurestemperature starting fromabsolute zero, the point at which particles have minimal thermal motion.
Thermodynamic temperature is typically expressed using theKelvin scale, on which the unit of measurement is thekelvin (unit symbol: K). This unit is the same interval as the degree Celsius, used on theCelsius scale but the scales are offset so that 0 K on the Kelvin scale corresponds to absolute zero. For comparison, a temperature of 295 K corresponds to 21.85 °C and 71.33 °F. Another absolute scale of temperature is theRankine scale, which is based on theFahrenheit degree interval.
Historically, thermodynamic temperature was defined byLord Kelvin in terms of a relation between the macroscopic quantitiesthermodynamic work andheat transfer as defined inthermodynamics, but the kelvin was redefined by international agreement in 2019 in terms of phenomena that are now understood as manifestations of the kinetic energy of free motion of particles such as atoms, molecules, and electrons.[citation needed]
Thermodynamic temperature can be defined in purely thermodynamic terms using theCarnot cycle. Thermodynamic temperature was rigorously defined historically long before particles such as atoms, molecules, and electrons were fully understood.
TheInternational System of Units (SI) specifies the absolute scale for measuring temperature, and the unit of measurekelvin (symbol: K) for specific values along the scale. A temperature interval of onedegree Celsius is the same as one kelvin. Since the2019 revision of the SI, the kelvin has been defined in relation to thephysical property underlying thermodynamic temperature: the kinetic energy of atomic free particle motion. The revision fixed theBoltzmann constant at exactly1.380649×10−23 J⋅K−1.[1]
The property that imbues material substances with a temperature can be readily understood by examining theideal gas law, which relates, through the Boltzmann constant, howheat energy causes precisely defined changes in thepressure and temperature of certain gases. This is becausemonatomic gases likehelium andargon behave kinetically like freely moving perfectly elastic and spherical billiard balls that move only in a specific subset of the possible motions that can occur in matter: that comprising the threetranslationaldegrees of freedom. The translational degrees of freedom are the familiar billiard ball-like movements along thex-,y-, andz-axes of 3D space (seeFig. 1, below). This is why the noble gases all have thesame heat capacity per atom and why that value is lowest of all the gases.
Molecules (two or more chemically bound atoms), however, haveinternal structure and therefore have additionalinternal degrees of freedom (seeFig. 3, below), which has the effect that molecules absorb more heat energy for any given rise in temperature than do the monatomic gases. Heat energy is born in all available degrees of freedom; this is in accordance with theequipartition theorem, so all available internal degrees of freedom have the same average energy as do their three external degrees of freedom. However, the property that gives all gases theirpressure, which is the net force per unit area on a container arising from gas particles recoiling off it, is a function of the kinetic energy borne in the freely moving atoms' and molecules' three translational degrees of freedom.[2]
Fixing the Boltzmann constant at a specific value had the effect of precisely establishing the magnitude of the kelvin in terms of the average kinetic behavior of the noble gases. Moreover, thestarting point of the thermodynamic temperature scale, absolute zero, was reaffirmed as the point at whichzero average kinetic energy remains in a sample; the only remaining particle motion being that comprising random vibrations due to zero-point energy.
Temperature scales are numerical. The numerical zero of a temperature scale is not bound to the absolute zero of temperature. Nevertheless, some temperature scales have their numerical zero coincident with the absolute zero of temperature. Examples are theKelvin temperature scale and theRankine temperature scale. Other temperature scales have their numerical zero far from the absolute zero of temperature. Examples are the Celsius scale and the Fahrenheit scale.
At the zero point of thermodynamic temperature,absolute zero, the particle constituents of matter have minimal motion and can become no colder.[3][4] Absolute zero, which is a temperature of zero kelvins (0 K), precisely corresponds to −273.15 °C and −459.67 °F. Matter at absolute zero has no remaining transferable average kinetic energy and the only remaining particle motion is due to an ever-pervasivequantum mechanical phenomenon called ZPE (zero-point energy).[5] Though the atoms in, for instance, a container of liquidhelium that wasprecisely at absolute zero would still jostle slightly due to zero-point energy, atheoretically perfect heat engine with such helium as one of itsworking fluids could never transfer any net kinetic energy (heat energy) to the other working fluid and nothermodynamic work could occur.
Temperature is generally expressed in absolute terms when scientifically examining temperature's interrelationships with certain other physical properties of matter such as itsvolume orpressure (seeGay-Lussac's law), or the wavelength of its emittedblack-body radiation. Absolute temperature is also useful when calculating chemical reaction rates (seeArrhenius equation). Furthermore, absolute temperature is typically used incryogenics and related phenomena likesuperconductivity, as per the following example usage:"Conveniently, tantalum's transition temperature (Tc) of 4.4924 kelvins is slightly above the 4.2221 K boiling point of helium."
Though there have been manyother temperature scales throughout history, there have been only two scales for measuring thermodynamic temperature which have absolute zero as their null point (0): The Kelvin scale and the Rankine scale.
Throughout the scientific world where modern measurements are nearly always made using the International System of Units, thermodynamic temperature is measured using the Kelvin scale. The Rankine scale is part ofEnglish engineering units and finds use in certain engineering fields, particularly in legacy reference works. The Rankine scale uses thedegree Rankine (symbol: °R) as its unit, which is the same magnitude as thedegree Fahrenheit (symbol: °F).
A unit increment of one kelvin is exactly 1.8 times one degree Rankine; thus, to convert a specific temperature on the Kelvin scale to the Rankine scale,x K = 1.8x °R, and to convert from a temperature on the Rankine scale to the Kelvin scale,x °R =x/1.8 K. Consequently, absolute zero is "0" for both scales, but the melting point of water ice (0 °C and 273.15 K) is 491.67 °R.
To convert temperatureintervals (a span or difference between two temperatures), the formulas from the preceding paragraph are applicable; for instance, an interval of 5 kelvins is precisely equal to an interval of 9 degrees Rankine.
For 65 years, between 1954 and the2019 revision of the SI, a temperature interval of one kelvin was defined as1/273.16 of the temperature difference between thetriple point of water and absolute zero. The 1954 resolution by theInternational Bureau of Weights and Measures (BIPM), plus later resolutions and publications, defined the triple point of water as precisely 273.16 K and acknowledged that it was "common practice" to accept that due to previous conventions (namely, that 0 °C had long been defined as the melting point of water and that the triple point of water had long been experimentally determined to be indistinguishably close to 0.01 °C), the difference between the Celsius scale and Kelvin scale is accepted as 273.15 K; which is to say, 0 °C corresponds to 273.15 K.[6] The net effect of this as well as later resolutions was twofold: 1) they defined absolute zero as precisely 0 K, and 2) they defined that the triple point of special isotopically controlled water calledVienna Standard Mean Ocean Water occurred at precisely 273.16 K and 0.01 °C. One effect of the aforementioned resolutions was that the melting point of water, whilevery close to 273.15 K and 0 °C, was not a defining value and was subject to refinement with more precise measurements.
The 1954 BIPM standard did a good job of establishing—within the uncertainties due toisotopic variations between water samples—temperatures around the freezing and triple points of water, but required thatintermediate values between the triple point and absolute zero, as well as extrapolated values from room temperature and beyond, to be experimentally determined via apparatus and procedures in individual labs. This shortcoming was addressed by theInternational Temperature Scale of 1990, or ITS‑90, which defined 13 additional points, from 13.8033 K, to 1,357.77 K. While definitional, ITS‑90 had—and still has—some challenges, partly because eight of its extrapolated values depend upon the melting or freezing points of metal samples, which must remain exceedingly pure lest their melting or freezing points be affected—usually depressed.
The 2019 revision of the SI was primarily for the purpose of decoupling much of the SI system's definitional underpinnings from thekilogram, which was the last physical artifact defining anSI base unit (a platinum/iridium cylinder stored under three nested bell jars in a safe located in France) and which had highly questionable stability. The solution required that four physical constants, including the Boltzmann constant, be definitionally fixed.
Assigning the Boltzmann constant a precisely defined value had no practical effect on modern thermometry except for the most exquisitely precise measurements. Before the revision, the triple point of water was exactly 273.16 K and 0.01 °C and the Boltzmann constant was experimentally determined to be1.38064903(51)×10−23 J/K, where the "(51)" denotes the uncertainty in the two least significant digits (the 03) and equals arelative standard uncertainty of 0.37 ppm.[7] Afterwards, by defining the Boltzmann constant as exactly1.380649×10−23 J/K, the 0.37 ppm uncertainty was transferred to the triple point of water, which became an experimentally determined value of273.1600±0.0001 K (0.0100±0.0001 °C). That the triple point of water ended up being exceedingly close to 273.16 K after the SI revision was no accident; the final value of the Boltzmann constant was determined, in part, through clever experiments withargon and helium that used the triple point of water for their key reference temperature.[8][9]
Notwithstanding the 2019 revision, water triple-point cells continue to serve in modern thermometry as exceedingly precise calibration references at 273.16 K and 0.01 °C. Moreover, the triple point of water remains one of the 14 calibration points comprising ITS‑90, which spans from the triple point of hydrogen (13.8033 K) to the freezing point of copper (1,357.77 K), which is a nearly hundredfold range of thermodynamic temperature.
The thermodynamic temperature of anybulk quantity of a substance (a statistically significant quantity of particles) is directly proportional to the mean average kinetic energy of a specific kind of particle motion known astranslational motion. These simple movements in the threex-,y-, andz-axes dimensions of space means the particles move in the three spatialdegrees of freedom. This particular form of kinetic energy is sometimes referred to askinetic temperature. Translational motion is but one form of heat energy and is what gives gases not only their temperature, but also their pressure and the vast majority of their volume. This relationship between the temperature, pressure, and volume of gases is established by theideal gas law's formulapV =nRT and is embodied in thegas laws.
Though the kinetic energy borne exclusively in the three translational degrees of freedom comprise the thermodynamic temperature of a substance, molecules, as can be seen inFig. 3, can have other degrees of freedom, all of which fall under three categories: bond length, bond angle, and rotational. All three additional categories are not necessarily available to all molecules, and even for molecules thatcan experience all three, some can be "frozen out" below a certain temperature. Nonetheless, all those degrees of freedom that are available to the molecules under a particular set of conditions contribute to thespecific heat capacity of a substance; which is to say, they increase the amount of heat (kinetic energy) required to raise a given amount of the substance by one kelvin or one degree Celsius.
The relationship of kinetic energy, mass, and velocity is given by the formulaEk = 1/2mv2.[10] Accordingly, particles with one unit of mass moving at one unit of velocity have precisely the same kinetic energy, and precisely the same temperature, as those with four times the mass but half the velocity.
TheBoltzmann constant relates the thermodynamic temperature of a gas to the mean kinetic energy of a particle's translational motion:where:
While the Boltzmann constant is useful for finding the mean kinetic energy in a sample of particles, it is important to note that even when a substance is isolated and inthermodynamic equilibrium (all parts are at a uniform temperature and no heat is going into or out of it), the translational motions of individual atoms and molecules occurs across a wide range of speeds (see animation inFig. 1 above). At any one instant, the proportion of particles moving at a given speed within this range is determined by probability as described by theMaxwell–Boltzmann distribution. The graph shown here inFig. 2 shows the speed distribution of 5500 K helium atoms. They have amost probable speed of 4.780 km/s (0.2092 s/km). However, a certain proportion of atoms at any given instant are moving faster while others are moving relatively slowly; some are momentarily at a virtual standstill (off thex-axis to the right). This graph usesinverse speed for itsx-axis so the shape of the curve can easily be compared to the curves inFig. 5 below. In both graphs, zero on thex-axis represents infinite temperature. Additionally, thex- andy-axes on both graphs are scaled proportionally.
Although very specialized laboratory equipment is required to directly detect translational motions, the resultant collisions by atoms or molecules with small particles suspended in afluid producesBrownian motion that can be seen with an ordinary microscope. The translational motions of elementary particles arevery fast[11] and temperatures close toabsolute zero are required to directly observe them. For instance, when scientists at theNIST achieved a record-setting low temperature of 700 nK (billionths of a kelvin) in 1994, they usedoptical lattice laser equipment toadiabatically coolcesium atoms. They then turned off the entrapment lasers and directly measured atom velocities of 7 mm per second in order to calculate their temperature.[12] Formulas for calculating the velocity and speed of translational motion are given in the following footnote.[13]
It is neither difficult to imagine atomic motions due to kinetic temperature, nor distinguish between such motions and those due to zero-point energy. Consider the following hypothetical thought experiment, as illustrated inFig. 2.5 at left, with an atom that is exceedingly close to absolute zero. Imagine peering through a common optical microscope set to 400 power, which is about the maximum practical magnification for optical microscopes. Such microscopes generally provide fields of view a bit over 0.4 mm in diameter. At the center of the field of view is a single levitated argon atom (argon comprises about 0.93% of air) that is illuminated and glowing against a dark backdrop. If this argon atom was at a beyond-record-settingone-trillionth of a kelvin above absolute zero,[14] and was moving perpendicular to the field of view towards the right, it would require 13.9 seconds to move from the center of the image to the 200 μm tick mark; this travel distance is about the same as the width of the period at the end of this sentence on modern computer monitors. As the argon atom slowly moved, the positional jitter due to zero-point energy would be much less than the 200 nm (0.0002 mm) resolution of an optical microscope. Importantly, the atom's translational velocity of 14.43 μm/s constitutes all its retained kinetic energy due to not being precisely at absolute zero. Were the atomprecisely at absolute zero, imperceptible jostling due to zero-point energy would cause it to very slightly wander, but the atom would perpetually be located, on average, at the same spot within the field of view. This is analogous to a boat that has had its motor turned off and is now bobbing slightly in relatively calm and windless ocean waters; even though the boat randomly drifts to and fro, it stays in the same spot in the long term and makes no headway through the water. Accordingly, an atom that was precisely at absolute zero would not be "motionless", and yet, a statistically significant collection of such atoms would have zero net kinetic energy available to transfer to any other collection of atoms. This is because regardless of the kinetic temperature of the second collection of atoms, they too experience the effects of zero-point energy. Such are the consequences ofstatistical mechanics and the nature of thermodynamics.
As mentioned above, there are other ways molecules can jiggle besides the three translational degrees of freedom that imbue substances with their kinetic temperature. As can be seen in the animation at right,molecules are complex objects; they are a population of atoms and thermal agitation can strain their internalchemical bonds in three different ways: via rotation, bond length, and bond angle movements; these are all types ofinternal degrees of freedom. This makes molecules distinct frommonatomic substances (consisting of individual atoms) like thenoble gaseshelium andargon, which have only the three translational degrees of freedom (thex-,y-, andz-axes). Kinetic energy is stored in molecules' internal degrees of freedom, which gives them aninternal temperature. Even though these motions are called "internal", the external portions of molecules still move—rather like the jiggling of a stationarywater balloon. This permits the two-way exchange of kinetic energy between internal motions and translational motions with each molecular collision. Accordingly, as internal energy is removed from molecules, both their kinetic temperature (the kinetic energy of translational motion) and their internal temperature simultaneously diminish in equal proportions. This phenomenon is described by theequipartition theorem, which states that for any bulk quantity of a substance in equilibrium, the kinetic energy of particle motion is evenly distributed among all the active degrees of freedom available to the particles. Since the internal temperature of molecules are usually equal to their kinetic temperature, the distinction is usually of interest only in the detailed study of non-local thermodynamic equilibrium (LTE) phenomena such ascombustion, thesublimation of solids, and thediffusion of hot gases in a partial vacuum.
The kinetic energy stored internally in molecules causes substances to contain more heat energy at any given temperature and to absorb additional internal energy for a given temperature increase. This is because any kinetic energy that is, at a given instant, bound in internal motions, is not contributing to the molecules' translational motions at that same instant.[15] This extra kinetic energy simply increases the amount of internal energy that substance absorbs for a given temperature rise. This property is known as a substance'sspecific heat capacity.
Different molecules absorb different amounts of internal energy for each incremental increase in temperature; that is, they have different specific heat capacities. High specific heat capacity arises, in part, because certain substances' molecules possess more internal degrees of freedom than others do. For instance, room-temperaturenitrogen, which is adiatomic molecule, hasfive active degrees of freedom: the three comprising translational motion plus two rotational degrees of freedom internally. Not surprisingly, in accordance with the equipartition theorem, nitrogen has five-thirds the specific heat capacity permole (a specific number of molecules) as do the monatomic gases.[16] Another example isgasoline (seetable showing its specific heat capacity). Gasoline can absorb a large amount of heat energy per mole with only a modest temperature change because each molecule comprises an average of 21 atoms and therefore has many internal degrees of freedom. Even larger, more complex molecules can have dozens of internal degrees of freedom.
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Heat conduction is the diffusion of thermal energy from hot parts of a system to cold parts. A system can be either a single bulk entity or a plurality of discrete bulk entities. The termbulk in this context means a statistically significant quantity of particles (which can be a microscopic amount). Whenever thermal energy diffuses within an isolated system, temperature differences within the system decrease (andentropy increases).
One particular heat conduction mechanism occurs when translational motion, the particle motion underlying temperature, transfersmomentum from particle to particle in collisions. In gases, these translational motions are of the nature shown above inFig. 1. As can be seen in that animation, not only does momentum (heat) diffuse throughout the volume of the gas through serial collisions, but entire molecules or atoms can move forward into new territory, bringing their kinetic energy with them. Consequently, temperature differences equalize throughout gases very quickly—especially for light atoms or molecules;convection speeds this process even more.[17]
Translational motion insolids, however, takes the form ofphonons (seeFig. 4 at right). Phonons are constrained, quantized wave packets that travel at the speed of sound of a given substance. The manner in which phonons interact within a solid determines a variety of its properties, including its thermal conductivity. In electrically insulating solids, phonon-based heat conduction isusually inefficient[18] and such solids are consideredthermal insulators (such as glass, plastic, rubber, ceramic, and rock). This is because in solids, atoms and molecules are locked into place relative to their neighbors and are not free to roam.
Metals however, are not restricted to only phonon-based heat conduction. Thermal energy conducts through metals extraordinarily quickly because instead of direct molecule-to-molecule collisions, the vast majority of thermal energy is mediated via very light, mobileconductionelectrons. This is why there is a near-perfect correlation between metals'thermal conductivity and theirelectrical conductivity.[19] Conduction electrons imbue metals with their extraordinary conductivity because they aredelocalized (i.e., not tied to a specific atom) and behave rather like a sort of quantum gas due to the effects ofzero-point energy (for more on ZPE, seeNote 1 below). Furthermore, electrons are relatively light with a rest mass only1⁄1836 that of aproton. AsIsaac Newton wrote with histhird law of motion,
Law #3: All forces occur in pairs, and these two forces are equal in magnitude and opposite in direction.
However, a bullet accelerates faster than a rifle given an equal force. Since kinetic energy increases as the square of velocity, nearly all the kinetic energy goes into the bullet, not the rifle, even though both experience the same force from the expanding propellant gases. In the same manner, because they are much less massive, thermal energy is readily borne by mobile conduction electrons. Additionally, because they are delocalized andvery fast, kinetic thermal energy conducts extremely quickly through metals with abundant conduction electrons.
Thermal radiation is a byproduct of the collisions arising from various vibrational motions of atoms. These collisions cause the electrons of the atoms to emit thermalphotons (known asblack-body radiation). Photons are emitted anytime an electric charge is accelerated (as happens when electron clouds of two atoms collide). Evenindividual molecules with internal temperatures greater than absolute zero also emit black-body radiation from their atoms. In any bulk quantity of a substance at equilibrium, black-body photons are emitted across a range ofwavelengths in a spectrum that has a bell curve-like shape called aPlanck curve (see graph inFig. 5 at right). The top of a Planck curve (the peak emittance wavelength) is located in a particular part of theelectromagnetic spectrum depending on the temperature of the black-body. Substances at extremecryogenic temperatures emit at long radio wavelengths whereas extremely hot temperatures produce shortgamma rays (see§ Table of thermodynamic temperatures).
Black-body radiation diffuses thermal energy throughout a substance as the photons are absorbed by neighboring atoms, transferring momentum in the process. Black-body photons also easily escape from a substance and can be absorbed by the ambient environment; kinetic energy is lost in the process.
As established by theStefan–Boltzmann law, the intensity of black-body radiation increases as the fourth power of absolute temperature. Thus, a black-body at 824 K (just short of glowing dull red) emits 60 times the radiantpower as it does at 296 K (room temperature). This is why one can so easily feel the radiant heat from hot objects at a distance. At higher temperatures, such as those found in anincandescent lamp, black-body radiation can be the principal mechanism by which thermal energy escapes a system.
The table below shows various points on the thermodynamic scale, in order of increasing temperature.
| Temperature | Peak emittance wavelength[20] of black-body photons | |
|---|---|---|
| Absolute zero (precisely by definition) | 0 K | ∞[5] |
| Coldest measured temperature[21] | 450pK | 6,400km |
| Onemillikelvin (precisely by definition) | 0.001 K | 2.897 77m (radio,FM band)[22] |
| cosmic microwave background radiation | 2.725 K | 1.063 mm (peak wavelength) |
| Water'striple point | 273.16 K | 10.6083μm (long wavelengthI.R.) |
| ISO 1 standard temperature for precisionmetrology (precisely 20 °C by definition) | 293.15 K | 9.88495 μm (long wavelengthI.R.) |
| Incandescent lamp[A] | 2500 K[B] | 1.16 μm (nearinfrared)[C] |
| Sun's visible surface[23][24][25][26] | 5772 K | 502 nm (green light) |
| Lightning bolt's channel | 28000 K | 100 nm (farultraviolet light) |
| Sun's core | 16MK | 0.18 nm (X-rays) |
| Thermonuclear explosion (peak temperature)[27] | 350 MK | 8.3 × 10−3 nm (gamma rays) |
| Sandia National Labs' Z machine[D][28] | 2GK | 1.4 × 10−3 nm (gamma rays) |
| Core of ahigh-mass star on its last day[29] | 3 GK | 1 × 10−3 nm (gamma rays) |
| Merging binaryneutron star system[30] | 350 GK | 8 × 10−6 nm (gamma rays) |
| Gamma-ray burst progenitors[31] | 1TK | 3 × 10−6 nm (gamma rays) |
| CERN's proton vs. nucleus collisions[32] | 10 TK | 3 × 10−7 nm (gamma rays) |
The kinetic energy of particle motion is just one contributor to the total thermal energy in a substance; another isphase transitions, which are thepotential energy of molecular bonds that can form in a substance as it cools (such as duringcondensing andfreezing). The thermal energy required for a phase transition is calledlatent heat. This phenomenon may more easily be grasped by considering it in the reverse direction: latent heat is the energy required tobreakchemical bonds (such as duringevaporation andmelting). Almost everyone is familiar with the effects of phase transitions; for instance,steam at 100 °C can cause severe burns much faster than the 100 °C air from ahair dryer. This occurs because a large amount of latent heat is liberated as steam condenses into liquid water on the skin.
Even though thermal energy is liberated or absorbed during phase transitions, purechemical elements,compounds, andeutecticalloys exhibit no temperature change whatsoever while they undergo them (seeFig. 7, below right). Consider one particular type of phase transition: melting. When a solid is melting,crystal latticechemical bonds are being broken apart; the substance is transitioning from what is known as amore ordered state to aless ordered state. InFig. 7, the melting of ice is shown within the lower left box heading from blue to green.
At one specific thermodynamic point, themelting point (which is 0 °C across a wide pressure range in the case of water), all the atoms or molecules are, on average, at the maximum energy threshold their chemical bonds can withstand without breaking away from the lattice. Chemical bonds are all-or-nothing forces: they either hold fast, or break; there is no in-between state. Consequently, when a substance is at its melting point, everyjoule of added thermal energy only breaks the bonds of a specific quantity of its atoms or molecules,[33] converting them into a liquid of precisely the same temperature; no kinetic energy is added to translational motion (which is what gives substances their temperature). The effect is rather likepopcorn: at a certain temperature, additional thermal energy cannot make the kernels any hotter until the transition (popping) is complete. If the process is reversed (as in the freezing of a liquid), thermal energy must be removed from a substance.
As stated above, the thermal energy required for a phase transition is calledlatent heat. In the specific cases of melting and freezing, it is calledenthalpy of fusion orheat of fusion. If the molecular bonds in a crystal lattice are strong, the heat of fusion can be relatively great, typically in the range of 6 to 30 kJ per mole for water and most of the metallic elements.[34] If the substance is one of the monatomic gases (which have little tendency to form molecular bonds) the heat of fusion is more modest, ranging from 0.021 to 2.3 kJ per mole.[35] Relatively speaking, phase transitions can be truly energetic events. To completely melt ice at 0 °C into water at 0 °C, one must add roughly 80 times the thermal energy as is required to increase the temperature of the same mass of liquid water by one degree Celsius. The metals' ratios are even greater, typically in the range of 400 to 1200 times.[36] The phase transition ofboiling is much more energetic than freezing. For instance, the energy required to completely boil or vaporize water (what is known asenthalpy of vaporization) is roughly 540 times that required for a one-degree increase.[37]
Water's sizable enthalpy of vaporization is why one's skin can be burned so quickly as steam condenses on it (heading from red to green inFig. 7 above); water vapors (gas phase) are liquefied on the skin with releasing a large amount of energy (enthalpy) to the environment including the skin, resulting in skin damage. In the opposite direction, this is why one's skin feels cool as liquid water on it evaporates (a process that occurs at a sub-ambientwet-bulb temperature that is dependent onrelative humidity); the water evaporation on the skin takes a large amount of energy from the environment including the skin, reducing the skin temperature. Water's highly energetic enthalpy of vaporization is also an important factor underlying whysolar pool covers (floating, insulated blankets that coverswimming pools when the pools are not in use) are so effective at reducing heating costs: they prevent evaporation. (In other words, taking energy from water when it is evaporated is limited.) For instance, the evaporation of just 20 mm of water from a 1.29 m-deep pool chills its water 8.4 °C (15.1 °F).
The total energy of all translational and internal particle motions, including that of conduction electrons, plus the potential energy of phase changes, pluszero-point energy[5] of a substance comprise theinternal energy of it.
As a substance cools, different forms of internal energy and their related effects simultaneously decrease in magnitude: the latent heat of available phase transitions is liberated as a substance changes from a less ordered state to a more ordered state; the translational motions of atoms and molecules diminish (their kinetic energy or temperature decreases); the internal motions of molecules diminish (their internal energy or temperature decreases); conduction electrons (if the substance is an electrical conductor) travelsomewhat slower;[38] and black-body radiation's peak emittance wavelength increases (the photons' energy decreases). When particles of a substance are as close as possible to complete rest and retain only ZPE (zero-point energy)-induced quantum mechanical motion, the substance is at the temperature of absolute zero (T = 0).
Whereas absolute zero is the point of zero thermodynamic temperature and is also the point at which the particle constituents of matter have minimal motion, absolute zero is not necessarily the point at which a substance contains zero internal energy; one must be very precise with what one means byinternal energy. Often, all the phase changes thatcan occur in a substance,will have occurred by the time it reaches absolute zero. However, this is not always the case. Notably,T = 0helium remains liquid at room pressure (Fig. 9 at right) and must be under a pressure of at least 25 bar (2.5 MPa) to crystallize. This is because helium's heat of fusion (the energy required to melt helium ice) is so low (only 21 joules per mole) that the motion-inducing effect of zero-point energy is sufficient to prevent it from freezing at lower pressures.
A further complication is that many solids change their crystal structure to more compact arrangements at extremely high pressures (up to millions of bars, or hundreds of gigapascals). These are known assolid–solid phase transitions wherein latent heat is liberated as a crystal lattice changes to a more thermodynamically favorable, compact one.
The above complexities make for rather cumbersome blanket statements regarding the internal energy inT = 0 substances. Regardless of pressure though, whatcan be said is that at absolute zero, all solids with a lowest-energy crystal lattice such those with aclosest-packed arrangement (seeFig. 8, above left) contain minimal internal energy, retaining only that due to the ever-present background of zero-point energy.[5][39] One can also say that for a given substance at constant pressure, absolute zero is the point of lowestenthalpy (a measure of work potential that takes internal energy, pressure, and volume into consideration).[40] Lastly, allT = 0 substances contain zero kinetic thermal energy.[5][13]
Thermodynamic temperature is useful not only for scientists, it can also be useful for lay-people in many disciplines involving gases. By expressing variables in absolute terms and applyingGay-Lussac's law of temperature/pressure proportionality, solutions to everyday problems are straightforward; for instance, calculating how a temperature change affects the pressure inside an automobile tire. If the tire has a cold gage[41] pressure of 200 kPa, then itsabsolute pressure is 300 kPa.[42][43] Room temperature ("cold" in tire terms) is 296 K. If the tire temperature is 20 °C hotter (20 kelvins), the solution is calculated as316 K/296 K = 6.8% greater thermodynamic temperatureand absolute pressure; that is, an absolute pressure of 320 kPa, which is a gage pressure of 220 kPa.
The thermodynamic temperature is closely linked to theideal gas law and its consequences. It can be linked also to the second law of thermodynamics. The thermodynamic temperature can be shown to have special properties, and in particular can be seen to be uniquely defined (up to some constant multiplicative factor) by considering theefficiency of idealizedheat engines. Thus theratioT2/T1 of two temperaturesT1 andT2 is the same in all absolute scales.
Strictly speaking, the temperature of a system is well-defined only if it is atthermal equilibrium. From a microscopic viewpoint, a material is at thermal equilibrium if the quantity of heat between its individual particles cancel out. There are many possible scales of temperature, derived from a variety of observations of physical phenomena.
Loosely stated, temperature differences dictate the direction of heat between two systems such that their combined energy is maximally distributed among their lowest possible states. We call this distribution "entropy". To better understand the relationship between temperature and entropy, consider the relationship between heat,work and temperature illustrated in theCarnot heat engine. The engine converts heat into work by directing a temperature gradient between a higher temperature heat source,TH, and a lower temperature heat sink,TC, through a gas filled piston. The work done per cycle is equal in magnitude to net heat taken up, which is sum of the heatqH taken up by the engine from the high-temperature source, plus the wasteheat given off by the engine,qC < 0.[44] Theefficiency of the engine is the work divided by the heat put into the system orwhere is the work done per cycle. Thus the efficiency depends only on|qC| / |qH|.
Carnot's theorem states that all reversible engines operating between the same heat reservoirs are equally efficient. Thus, any reversible heat engine operating between temperaturesT1 andT2 must have the same efficiency, that is to say, the efficiency is the function of only temperatures
In addition, a reversible heat engine operating between a pair of thermal reservoirs at temperaturesT1 andT3 must have the same efficiency as one consisting of two cycles, one betweenT1 and another (intermediate) temperatureT2, and the second betweenT2 andT3. If this were not the case, then energy (in the form ofq) will be wasted or gained, resulting in different overall efficiencies every time a cycle is split into component cycles; clearly a cycle can be composed of any number of smaller cycles as an engine design choice, and any reversible engine between the same reservoir atT1 andT3 must be equally efficient regardless of the engine design.
If we choose engines such that work done by the one cycle engine and the two cycle engine are same, then the efficiency of each heat engine is written as below.
Here, the engine 1 is the one cycle engine, and the engines 2 and 3 make the two cycle engine where there is the intermediate reservoir atT2. We also have used the fact that the heat passes through the intermediate thermal reservoir at without losing its energy. (I.e., is not lost during its passage through the reservoir at.) This fact can be proved by the following.
In order to have the consistency in the last equation, the heat flown from the engine 2 to the intermediate reservoir must be equal to the heat flown out from the reservoir to the engine 3.
With this understanding ofq1,q2 andq3, mathematically,
But since the first function isnot a function ofT2, the product of the final two functionsmust result in the removal ofT2 as a variable. The only way is therefore to define the functionf as follows:andso that
I.e. the ratio of heat exchanged is a function of the respective temperatures at which they occur. We can choose any monotonic function for our;[45] it is a matter of convenience and convention that we choose. Choosing thenone fixed reference temperature (i.e. triple point of water), we establish the thermodynamic temperature scale.
Such a definition coincides with that of the ideal gas derivation; also it is thisdefinition of the thermodynamic temperature that enables us to represent the Carnot efficiency in terms ofTH andTC, and hence derive that the (complete) Carnot cycle is isentropic:
Substituting this back into our first formula for efficiency yields a relationship in terms of temperature:
Note that forTC = 0 the efficiency is 100% and that efficiency becomes greater than 100% forTC < 0, which is unrealistic. Subtracting 1 from the right hand side of the Equation (4) and the middle portion gives and thus[46][44]
The generalization of this equation is theClausius theorem, which proposes the existence of astate function (i.e., a function which depends only on the state of the system, not on how it reached that state) defined (up to an additive constant) bywhere the subscriptrev indicates heat transfer in a reversible process. The function is theentropy of the system, mentioned previously, and the change of around any cycle is zero (as is necessary for any state function). The Equation 5 can be rearranged to get an alternative definition for temperature in terms of entropy and heat (to avoid a logic loop, we should first defineentropy through statistical mechanics):
For a constant-volume system (so no mechanical work) in which the entropy is a function of itsinternal energy, and the thermodynamic temperature is therefore given byso that the reciprocal of the thermodynamic temperature is the rate of change of entropy with respect to the internal energy at the constant volume.
Guillaume Amontons (1663–1705) published two papers in 1702 and 1703 that may be used to credit him as being the first researcher to deduce the existence of a fundamental (thermodynamic) temperature scale featuring an absolute zero. He made the discovery while endeavoring to improve upon the air thermometers in use at the time. His J-tube thermometers comprised a mercury column that was supported by a fixed mass of air entrapped within the sensing portion of the thermometer. In thermodynamic terms, his thermometers relied upon the volume / temperature relationship of gas under constant pressure. His measurements of the boiling point of water and the melting point of ice showed that regardless of the mass of air trapped inside his thermometers or the weight of mercury the air was supporting, the reduction in air volume at the ice point was always the same ratio. This observation led him to posit that a sufficient reduction in temperature would reduce the air volume to zero. In fact, his calculations projected that absolute zero was equivalent to −240 °C—only 33.15 degrees short of the true value of −273.15 °C. Amonton's discovery of a one-to-one relationship between absolute temperature and absolute pressure was rediscovered a century later and popularized within the scientific community byJoseph Louis Gay-Lussac. Today, this principle of thermodynamics is commonly known asGay-Lussac's law but is also known asAmonton's law.
In 1742,Anders Celsius (1701–1744) created a "backwards" version of the modern Celsius temperature scale. In Celsius's original scale, zero represented the boiling point of water and 100 represented the melting point of ice. In his paperObservations of two persistent degrees on a thermometer, he recounted his experiments showing that ice's melting point was effectively unaffected by pressure. He also determined with remarkable precision how water's boiling point varied as a function of atmospheric pressure. He proposed that zero on his temperature scale (water's boiling point) would be calibrated at the mean barometric pressure at mean sea level.
Coincident with the death of Anders Celsius in 1744, the botanistCarl Linnaeus (1707–1778) effectively reversed[47][48][full citation needed] Celsius's scale upon receipt of his first thermometer featuring a scale where zero represented the melting point of ice and 100 represented water's boiling point. The custom-madeLinnaeus-thermometer, for use in his greenhouses, was made by Daniel Ekström, Sweden's leading maker of scientific instruments at the time. For the next 204 years, the scientific and thermometry communities worldwide referred to this scale as thecentigrade scale. Temperatures on the centigrade scale were often reported simply asdegrees or, when greater specificity was desired,degrees centigrade. The symbol for temperature values on this scale was °C (in several formats over the years). Because the termcentigrade was also the French-language name for a unit of angular measurement (one-hundredth of a right angle) and had a similar connotation in other languages, the term "centesimal degree" was used when very precise, unambiguous language was required by international standards bodies such as theInternational Bureau of Weights and Measures (BIPM). The 9th CGPM (General Conference on Weights and Measures and the CIPM (International Committee for Weights and Measures formally adopted[49]degree Celsius (symbol: °C) in 1948.
In his bookPyrometrie (1777)[50] completed four months before his death,Johann Heinrich Lambert (1728–1777), sometimes incorrectly referred to as Joseph Lambert, proposed an absolute temperature scale based on the pressure/temperature relationship of a fixed volume of gas. This is distinct from the volume/temperature relationship of gas under constant pressure that Guillaume Amontons discovered 75 years earlier. Lambert stated that absolute zero was the point where a simple straight-line extrapolation reached zero gas pressure and was equal to −270 °C.
Notwithstanding the work of Guillaume Amontons 85 years earlier,Jacques Alexandre César Charles (1746–1823) is often credited with discovering (circa 1787), but not publishing, that the volume of a gas under constant pressure is proportional to its absolute temperature. The formula he created wasV1/T1 =V2/T2.
Joseph Louis Gay-Lussac (1778–1850) published work in 1802 (acknowledging the unpublished lab notes of Jacques Charles fifteen years earlier) describing how the volume of gas under constant pressure changes linearly with its absolute (thermodynamic) temperature. This behavior is calledCharles's law and is one of thegas laws. His are the first known formulas to use the number 273 for the expansion coefficient of gas relative to the melting point of ice (indicating that absolute zero was equivalent to −273 °C).
William Thomson (1824–1907), also known as Lord Kelvin, wrote in his 1848 paper "On an Absolute Thermometric Scale"[51] of the need for a scale wherebyinfinite cold (absolute zero) was the scale's zero point, and which used the degree Celsius for its unit increment. Like Gay-Lussac, Thomson calculated that absolute zero was equivalent to −273 °C on the air thermometers of the time. This absolute scale is known today as the Kelvin thermodynamic temperature scale. Thomson's value of −273 was derived from 0.00366, which was the accepted expansion coefficient of gas per degree Celsius relative to the ice point. The inverse of −0.00366 expressed to five significant digits is −273.22 °C which is remarkably close to the true value of −273.15 °C.
In the paper he proposed to define temperature using idealized heat engines. In detail, he proposed that, given three heat reservoirs at temperatures, if two reversible heat engines (Carnot engine), one working between and another between, can produce the same amount of mechanical work by letting the same amount of heat pass through, then define.
Note that like Carnot, Kelvin worked under the assumption that heat is conserved ("the conversion of heat (or caloric) into mechanical effect is probably impossible"), and if heat goes into the heat engine, then heat must come out.[52]
Kelvin, realizing after Joule's experiments that heat is not a conserved quantity but is convertible with mechanical work, modified his scale in the 1851 workAn Account of Carnot's Theory of the Motive Power of Heat. In this work, he defined as follows:[53]
Given two heat reservoirs, and a reversible heat engine working between them, such that if during an engine cycle, heat moves into the engine, and heat comes out of the engine, then.
The above definition fixes the ratios between absolute temperatures, but it does not fix a scale for absolute temperature. For the scale, Thomson proposed to use the Celsius degree, that is, the interval between the freezing and the boiling point of water.
In 1859Macquorn Rankine (1820–1872) proposed a thermodynamic temperature scale similar to William Thomson's but which used the degreeFahrenheit for its unit increment, that is, the interval between the freezing and the boiling point of water. This absolute scale is known today as theRankine thermodynamic temperature scale.
Ludwig Boltzmann (1844–1906) made major contributions to thermodynamics between 1877 and 1884 through an understanding of the role that particle kinetics and black body radiation played. His name is now attached to several of the formulas used today in thermodynamics.
Gas thermometry experiments carefully calibrated to the melting point of ice and boiling point of water showed in the 1930s that absolute zero was equivalent to −273.15 °C.
Resolution 3[54] of the 9thGeneral Conference on Weights and Measures (CGPM) in 1948 fixed the triple point of water at precisely 0.01 °C. At this time, the triple point still had no formal definition for its equivalent kelvin value, which the resolution declared "will be fixed at a later date". The implication is that if the value of absolute zero measured in the 1930s was truly −273.15 °C, then the triple point of water (0.01 °C) was equivalent to 273.16 K. Additionally, both the International Committee for Weights and Measures (CIPM) and the CGPM formally adopted[55] the nameCelsius for thedegree Celsius and theCelsius temperature scale.[58]
Resolution 3[59] of the 10th CGPM in 1954 gave the Kelvin scale its modern definition by choosing the triple point of water as its upper defining point (with no change to absolute zero being the null point) and assigning it a temperature of precisely 273.16 kelvins (what was actually written 273.16degrees Kelvin at the time). This, in combination with Resolution 3 of the 9th CGPM, had the effect of defining absolute zero as being precisely zero kelvins and −273.15 °C.
Resolution 3[60] of the 13th CGPM in 1967/1968 renamed the unit increment of thermodynamic temperaturekelvin, symbol K, replacingdegree absolute, symbol °K. Further, feeling it useful to more explicitly define the magnitude of the unit increment, the 13th CGPM also decided in Resolution 4[61] that "The kelvin, unit of thermodynamic temperature, is the fraction 1/273.16 of the thermodynamic temperature of the triple point of water".
The CIPM affirmed in 2005[62] that for the purposes of delineating the temperature of the triple point of water, the definition of the Kelvin thermodynamic temperature scale would refer to water having an isotopic composition defined as being precisely equal to the nominal specification ofVienna Standard Mean Ocean Water.
In November 2018, the 26th General Conference on Weights and Measures (CGPM) changed the definition of the Kelvin by fixing the Boltzmann constant to1.380649×10−23 when expressed in the unit J/K.This change (and other changes in the definition of SI units) was made effective on the 144th anniversary of the Metre Convention, 20 May 2019.
Although absolute zero (T = 0) is not a state of zero molecular motion, itis the point of zero temperature and, in accordance with the Boltzmann constant, is also the point of zero particle kinetic energy and zero kinetic velocity.To understand how atoms can have zero kinetic velocity and simultaneously be vibrating due to ZPE, consider the following thought experiment: twoT = 0 helium atoms in zero gravity are carefully positioned and observed to have an average separation of620 pm between them (a gap of ten atomic diameters). It is an "average" separation because ZPE causes them to jostle about their fixed positions. Then one atom is given a kinetic kick of precisely 83 yoctokelvins (1 yK =1×10−24 K). This is done in a way that directs this atom's velocity vector at the other atom. With 83 yK of kinetic energy between them, the 620 pm gap through their commonbarycenter would close at a rate of 719 pm/s and they would collide after 0.862 second. This is the same speed as shown in theFig. 1animation above. Before being given the kinetic kick, bothT = 0 atoms had zero kinetic energy and zero kinetic velocity because they could persist indefinitely in that state and relative orientation even though both were being jostled by ZPE. AtT = 0, nokinetic energy is available for transfer to other systems.
Note too that absolute zero serves as the baseline atop whichthermodynamics and itsequations are founded because they deal with the exchange of thermal energy between "systems" (a plurality of particles and fields modeled as an average). Accordingly, one may examine ZPE-induced particle motionwithin a system that is at absolute zero but there can never be a net outflow of thermal energy from such a system. Also, the peak emittance wavelength of black-body radiation shifts to infinity at absolute zero; indeed, a peak no longer exists and black-body photons can no longer escape. Because of ZPE, however,virtual photons are still emitted atT = 0. Such photons are called "virtual" because they can't be intercepted and observed. Furthermore, thiszero-point radiation has a uniquezero-point spectrum. However, even though aT = 0 system emits zero-point radiation, no net heat flowQ out of such a system can occur because if the surrounding environment is at a temperature greater thanT = 0, heat will flow inward, and if the surrounding environment is at 'T = 0, there will be an equal flux of ZP radiation both inward and outward. A similarQequilibrium exists atT = 0 with the ZPE-inducedspontaneous emission of photons (which is more properly called astimulated emission in this context). The graph at upper right illustrates the relationship of absolute zero to zero-point energy. The graph also helps in the understanding of how zero-point energy got its name: it is the vibrational energy matter retains at thezero-kelvin point.Derivation of the classical electromagnetic zero-point radiation spectrum via a classical thermodynamic operation involving van der Waals forces, Daniel C. Cole, Physical Review A,42 (1990) 1847.
While the details of this process are currently unknown, it must involve a fireball of relativistic particles heated to something in the region of a trillion kelvin.
eq.(64)
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