![]() | This![]() It is of interest to the followingWikiProjects: | ||||||||||||||||||||||||
|
Temperature eV/kB 1.1604505(20)×10^5 K is definitely wrong by a factor of 10! As one learns early on in the physics course at university KB * room temperature ≈ 1/40 eV!— Precedingunsigned comment added byNayano2 (talk •contribs)19:48, 11 November 2016 (UTC)[reply]
Decay width is used several times on this page but never explained.
Arlesterc21:42, 10 February 2007 (UTC)[reply]
A single particle has no temperature, because temperature is a property of a body consisting of many particles. The average kinetic energy of particles of a gas is approximately. Where is the number of degrees of freedom of the gas particles and is the Boltzmann constant. For an ideal gas is 3. So the relation between average kinetic energy of the particles and the temperature of the gas is. In the case of an ideal gas the constant of proportionality is. See alsoMaxwell-Boltzmann distribution equation (17). --Hardy15:20, 6 November 2005 (UTC)[reply]
Can someone more knowledgable than I implement the above correction (see last line of "Electronvolts and kinetic energy"). Thanks.Anthony Chivetta06:12, 13 February 2006 (UTC)[reply]
Hey,I'm getting ready for the SAT physics test, and I seem to be getting some strange info. about the eV. In my book, it says 1eV=1.6x10(-19) Joules, but then it says something about 1eV= 6.25x10(18)eV/Joules...Does anybody know what this is supposed to mean, and if so could they add it to the article? Thanks
1 eV = 1.6x10(-19) J, therefore 1 Joule = 6.25x10(18)eV. Hope that helps... I'm not sure what they mean by eV/J though as both eV and J are units of energy. The definition means that multiplying one eV by e, the charge on an electron (not the natural logarithmic e) gives you Joules. e = 1.6x10(-19) Coulombs. There. Clear as mud.MilleauRekiir15:23, 11 August 2006 (UTC)[reply]
I am trying to understand what is going on with the Large Hadron Collider. I saw something that said 1 tetraelectronvolt was equal to the energy of a flying mosquito. I don't have a realistic idea of how much energy that is. Is there a generally recognizable equivalent to how much energy is contained in a tetraelectronvolt?claimman75 (talk)02:03, 1 December 2009 (UTC)[reply]
I have never before heard anyone pronounce GeV as jev, I would say its commonly refered to G-E-V, at least Canadian particle physics curcits.As well, the proton is not a typical baryon, in fact it is probably the least typical of them all because it and the neutron are the only ones that don't decay. I would probably go a little further and say that no baryon can be seen as representative of them all, the only thing they all have in common is each having three quarks.--Jason
There are some errors in theElectronvolts and time section. First of all, expressing time and distance in inverse eV units is based on the usual "particle physics units" hbar = c = 1. Then time is hbar/E, not hbar/2E. Likewise, distance is hbar*c/E. It's true that eV units are used as an alternate way to express the lifetimes of unstable particles, in the form of the (total) width where is the lifetime (not the half-life). Also, what's anexotic kernel?HEL00:30, 9 October 2006 (UTC)[reply]
Here are the relevant numbers:
Citation is K. Hagiwara et al,Review of Particle Physics, Phys. Rev. D66, 010001 (2002). The parentheses notation (26) means the uncertainty is plus or minus 26 in the last two digits quoted. fm is a Fermi or femtometer, 10-15 m. Also thelifetime is the thing that appears in the decay exponential, exp(-t/). The half-life is related to the lifetime by. (By the way, does anyone know how to get rid of those spurious dashes that sometimes follow math-mode expressions?)HEL02:40, 9 October 2006 (UTC)[reply]
I rewrote this section. The old content is here: (forgot to sign comment - sorry!HEL17:54, 9 October 2006 (UTC) )[reply]
A very brief length of time can be measured with eV. Theuncertainty principle gives. A time can correspond to an energy, and when the length of time is very brief (less than anattosecond), the measure is less significant for the observer if expressed in seconds. The conversion is carried out by :
This kind of length is encountered inhalf-lifes of exotic kernels. For example, the half-life of the8C is 230keV (1.43×10-21 s).
one kilogram, or ten thousand kilograms?Im referring to this section 1.0000 kg = 89.876 PJ194.145.96.51 (talk)15:26, 31 January 2008 (UTC)[reply]
Eutactic (talk)03:26, 9 May 2008 (UTC)[reply]
Nobody outside of a government building has ever, to my knowledge, called it an "electronvolt".Likebox (talk)19:33, 18 July 2008 (UTC)[reply]
Maybe back in 2002, the CODATA value was 1.602 176 53(14)×10−19 J, but it's 2008 now, and the value is 1.602 176 487(40)×10−19 J. Some of the equations need to be reworked because of this.
67.171.43.170 (talk)23:10, 5 September 2008 (UTC)[reply]
In SI units, it is the number which measures the charge of the electron with the unit changed from C to J. Is this really a good thing to write it that way? This suggests the (unaware) reader, that you can simply exchange C with J. However, C is unit of Charge (coulomb), J is unit of work (joule). Any suggestions to word this better? -andy92.229.100.244 (talk)12:18, 24 October 2008 (UTC)[reply]
I found that electron volt was first used in 1912 and in that time it was called "equivalent volt". Does anybody know who was the person to use it for the first time and in which publication did it appear? Thank you.Jan.Kamenicek (talk)22:34, 13 April 2009 (UTC)[reply]
Ummh, this seems to completely miss the point. You have to define a new unit cause you don't know the exact ratio of 1.0 eV to 1.0 J, and if you used the same unit of measure you would be asserting that you did. The electron-volt can be used when you know the number of electrons, through counting, but not exact conversions, which can be continually improved. Just like theAvogadro constant.
Just look above at how the old number has become obsolete due to better measurements, this is the reason there has to be two different units.
I propose that a quote that just tells people to accept things on faith, accept things because that's the way its done, should be removed, even if it is from a lecturer with lots of credibility. The quote really says nothing besides that the two units are measuring the same thing.Scientus (talk)16:11, 18 September 2009 (UTC)[reply]
Could just be me, but the energy released from fusion seems like it should be much higher than quoted... it should be greater than fission... in the GeV range maybe? It says that fission produces more per particle than fusion, but fusion produces more energy per kilogram... just sounds like somebody's in the wrong order of magnitude? Does anyone have a source?Patricius12 (talk)05:21, 2 November 2009 (UTC)[reply]
I find this section very confusing. "17.6 MeV: total energy released in fusion of deuterium and tritium to form helium-4 (also on average); this is 0.41 petajoule per kilogram of product produced, which is equivalent to the energy released in a 100-kiloton explosion of TNT." What the heck does that mean? Is 17.6 = to 100-kt of TNT? If not, why even mention TNT? If so, then how can one teraelectronvolt only been the same kinetic energy of a flying mosquito?—Precedingunsigned comment added by70.68.138.99 (talk)04:32, 25 November 2009 (UTC)[reply]
100-kt of TNT is equivalent to the energy released in fusion of tritium and deuterium, if in the process a kilogram of helium is produced. I agree it is a bit confusing.Terminus0 (talk)18:47, 7 December 2009 (UTC)[reply]
Exa=10^18, so 300 EeV=300,000 PeV = 300,000,000 TeV = 3x10^20 eV, while Peta = 10^15, so 600 PeV = 600,000 TeV = 6x10^17 eV. comment added by78.159.199.31 (talk)09:17, 31 May 2010 (UTC)[reply]
100 J is not 8000 TeV (or 8 PeV = 8*10^15 eV)—Precedingunsigned comment added by72.92.76.143 (talk)00:13, 2 April 2010 (UTC)[reply]
The result of the move request was:page moved.Anthony Appleyard (talk)14:01, 14 February 2010 (UTC)[reply]
Electron volt →Electronvolt —. It is the name used throughout all of science as far as I'm aware. All my textbooks, and all the journals I read, regardless of field (chemistry, thermodynamics, particle physics, solid state physics, ...) spell it that way. All other authoritative sources (such asBIPM,IUPAC, ...) also spell it that way. I don't ever recall seeing it spell "electron volt", other than in vulgarization articles found in magazines such asPopular Science from time to time. —Headbomb {ταλκκοντριβς – WP Physics}05:27, 6 February 2010 (UTC)[reply]
I was trying to find the eV of a terahertz frequency signal. This led me to the NIST CODATA conversion factor[1] and several examples[2][3][4] which seem to support using the Planck's constant h, not h/2pi, for the conversion factor. This makes sense to me in that the hertz here seem to be for the full revolution of a circle, not a unit length. I didn't want to mess with this article because I'm out of my expertise and I don't know if you have a different calculation more in mind, but that's the way I did it for theradio spectrum article to provide an eV reference.Wnt (talk)19:37, 18 April 2011 (UTC)[reply]
The rational for the previous move is incorrect. I am a physics student and all my textbooks and lecturers use electron Volt, not electronvolt. Electron Volt is clearly the most common term used by both physicists and the public at large. Unless anybody objects I will be moving this page. Electronvolt makes no sense linguistically either.The Proffesor (talk)11:45, 23 May 2011 (UTC)[reply]
I think this article would benefit from a section on converting eV to velocity, most especially in reference to a free electon.
KE = 1/2 m v^2 where the mass of an electon is .511 MeV/c^2, and the kinetic energy of the electron is (just to make it easy) 511 eV, would result in a speed of
v = (2 KE/m) ^1/2 (with v in terms of c, the speed of light)
= (2 511 eV/(511 * 10^3) ^1/2 = .04 times the speed of light
or, to put it in terms people have a gut feel for,
= .04 c * (671 million miles per hour)
= 26 million miles per hour
Also, doing the same thing for higher energies, like 1MeV, which is a typical value for an emitted beta particle, which requires calculating it assuming relativistic speed, but is too hard for me.— Precedingunsigned comment added by74.38.229.40 (talk)10:27, 3 September 2011 (UTC)[reply]
The name of the unit must beelectron-volt because those two (the charge on the electron and the volt) aremultiplied together. This is just like the following:
newton-meter, foot-pound, pound-foot, kilowatt-hour, and ampere-hour.
If you have a hard time understanding the ampere-hour, this is a rating for storage batteries. At a fixed "bus voltage" at the output (set by the power electronics), volts times ampere-hours works out in energy, and if multiplied by 3600, the result works out in joules. The real job of a storage battery is to store energy, and then release it as required.
The foot-pound is a unit of energy, but the pound-foot is a unit of torque. In the SI, energy is measured in joules, but the newton-meter is a unit of torque. The electron-volt (abbreviated eV) is a unit of energy.
98.67.162.130 (talk)20:48, 1 September 2012 (UTC)[reply]
The result of the move request was:not moved.(non-admin closure)Hot Stoptalk-contribs03:56, 14 July 2013 (UTC)[reply]
Electronvolt →Electron volt – Most commonly used term for this unit of energy.Apteva (talk)17:48, 7 July 2013 (UTC)[reply]
*'''Support'''
or*'''Oppose'''
, then sign your comment with~~~~
. Sincepolling is not a substitute for discussion, please explain your reasons, taking into accountWikipedia's policy on article titles.So first and foremost, this section begins by making the statement:
"By mass–energy equivalence, the electronvolt is also a unit of mass."
though it is true that energy and mass can be converted between eachother, mass units and energy units are not the same thing. You can never write "x electronvolts = y kilograms", It just doesn't work that way. Saying that electronvolts are a UNIT of mass is always wrong, saying mass can be expressed in terms of energy and energy can be (sort of) expressed in terms of mass is significantly more correct. The current wordage could prove to be misleading to readers who don't understand what is actually meant to be said.
Now, I don't think this section even really belongs in an article on a unit of measure, since it is something which pertains to energy in general and the units used have next to no relevance on the matter. In other words, talking about this does not tell someone anything more about electronvolts. If the statement about electronvolts also being a unit of mass were true, then that would be another matter altogether, but since it doesn't, I believe this section doesn't really add anything to the article. I could be in the minority with this opinion but thought I'd put it out there, since I don't really believe in unnecessary clutter.Ionic1337 (talk)00:34, 28 July 2015 (UTC)[reply]
Hello fellow Wikipedians,
I have just added archive links to one external link onElectronvolt. Please take a moment to reviewmy edit. If necessary, add{{cbignore}}
after the link to keep me from modifying it. Alternatively, you can add{{nobots|deny=InternetArchiveBot}}
to keep me off the page altogether. I made the following changes:
When you have finished reviewing my changes, please set thechecked parameter below totrue to let others know.
This message was posted before February 2018.After February 2018, "External links modified" talk page sections are no longer generated or monitored byInternetArchiveBot. No special action is required regarding these talk page notices, other thanregular verification using the archive tool instructions below. Editorshave permission to delete these "External links modified" talk page sections if they want to de-clutter talk pages, but see theRfC before doing mass systematic removals. This message is updated dynamically through the template{{source check}}
(last update: 5 June 2024).
Cheers. —cyberbot IITalk to my owner:Online00:56, 26 August 2015 (UTC)[reply]
Shouldn't a mol (6.02 × 1023) of protons weigh about 1g? The units given show 10-36kg, which is a long way from 10-23. Or is this one of those "relativistic" things where once the electron joins the party and the proton is now a "nucleus", the mass changes?
Riventree (talk)16:45, 5 June 2016 (UTC)[reply]
Hello fellow Wikipedians,
I have just modified one external link onElectronvolt. Please take a moment to reviewmy edit. If you have any questions, or need the bot to ignore the links, or the page altogether, please visitthis simple FaQ for additional information. I made the following changes:
When you have finished reviewing my changes, please set thechecked parameter below totrue orfailed to let others know (documentation at{{Sourcecheck}}
).
This message was posted before February 2018.After February 2018, "External links modified" talk page sections are no longer generated or monitored byInternetArchiveBot. No special action is required regarding these talk page notices, other thanregular verification using the archive tool instructions below. Editorshave permission to delete these "External links modified" talk page sections if they want to de-clutter talk pages, but see theRfC before doing mass systematic removals. This message is updated dynamically through the template{{source check}}
(last update: 5 June 2024).
Cheers.—InternetArchiveBot(Report bug)08:33, 22 December 2016 (UTC)[reply]
energy consumed by a single 100-watt light bulb in one second
If this is what I think it is, in many countries they don't sell those any more, and it's not much of a relatable standard for our youngest readers. —MaxEnt01:12, 26 May 2018 (UTC)[reply]
The article reads:"a unit of energy equal to exactly 1.602176634×10−19 joules (symbol J) in SI units."and"Like the elementary charge on which it is based, it is not an independent quantity".
Is the latter still correct, or only historically correct? J is aderived unit, but based upon N×m, and neither of these depend upon the electron's charge.
—DIV (1.129.107.117 (talk)03:43, 30 May 2019 (UTC))[reply]
"In physics, an electronvolt (symbol eV, also written electron-volt and electron volt) is the amount of kinetic energy gained (or lost) by a single electron accelerating from rest through an electric potential difference of one volt in vacuum."
1. Is eV a unit? If so, that's probably the first fact that should be mentioned.
2. Presumably measurements using the unit eV can range over positive or negative values. Hence the unit must have a positive sense. So is the positive sense a gain of energy, or loss of energy? That determination may be complicated by the fact that the electron carries a negative charge. So eV = e x V might well be negative in terms of Joules, when V is positive.
3. Is it only the energy gained(/lost) when the electron is accelerated from rest? Or is it the gain(/loss) when moving through a 1V field, regardless of the starting velocity?
4. If we take the sentence literally to mean only starting from rest, then how does an electron at rest actually lose energy?
"When used as a unit of energy, the numerical value of 1 eV in joules (symbol J) is equivalent to the numerical value of the charge of an electron in coulombs (symbol C). Under the 2019 redefinition of the SI base units, this sets 1 eV equal to 1.602176634×10−19 J."
5. The preceding sentence told us that eV is an amount of energy. So why does this new sentence qualify "when used as a unit of energy". Does this suggest that eV is sometimes not a unit, or sometimes not a unit of energy?
6. Are there any circumstances where 1 eV expressed in Joules is not 1.602...x 10^-19?
7. What is even the point of "the numerical value of 1 eV in joules (symbol J) is equivalent to the numerical value of the charge of an electron in coulombs (symbol C)". That bunch of words is simply a complicated way of saying 1.602 x 10^-19 = 1 x 1.602 x 10^-19. Obviously the numerical value will be the same on both sides of the equation.Gwideman (talk)08:20, 20 July 2020 (UTC)[reply]
The following Wikimedia Commons file used on this page or its Wikidata item has been nominated for deletion:
Participate in the deletion discussion at thenomination page. —Community Tech bot (talk)22:39, 7 January 2022 (UTC)[reply]
Perusing the various foregoing comments, it seems pertinent to provide a reminder of two relevant sets of Wikipedia guidelines:
—DIV (1.145.110.31 (talk)04:12, 26 October 2023 (UTC))[reply]