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Symmetric tensor

From Wikipedia, the free encyclopedia
Tensor invariant under permutations of vectors it acts on

Inmathematics, asymmetric tensor is anunmixedtensor that is invariant under apermutation of its vector arguments:

T(v1,v2,,vr)=T(vσ1,vσ2,,vσr){\displaystyle T(v_{1},v_{2},\ldots ,v_{r})=T(v_{\sigma 1},v_{\sigma 2},\ldots ,v_{\sigma r})}

for every permutationσ of the symbols{1, 2, ...,r}. Alternatively, a symmetric tensor of orderr represented in coordinates as a quantity withr indices satisfies

Ti1i2ir=Tiσ1iσ2iσr.{\displaystyle T_{i_{1}i_{2}\cdots i_{r}}=T_{i_{\sigma 1}i_{\sigma 2}\cdots i_{\sigma r}}.}

The space of symmetric tensors of orderr on a finite-dimensionalvector spaceV isnaturally isomorphic to the dual of the space ofhomogeneous polynomials of degreer onV. Overfields ofcharacteristic zero, thegraded vector space of all symmetric tensors can be naturally identified with thesymmetric algebra onV. A related concept is that of theantisymmetric tensor oralternating form. Symmetric tensors occur widely inengineering,physics andmathematics.

Definition

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LetV be a vector space and

TVk{\displaystyle T\in V^{\otimes k}}

a tensor of orderk. ThenT is a symmetric tensor if

τσT=T{\displaystyle \tau _{\sigma }T=T\,}

for thebraiding maps associated to every permutationσ on the symbols {1,2,...,k} (or equivalently for everytransposition on these symbols).

Given abasis {ei} ofV, any symmetric tensorT of rankk can be written as

T=i1,,ik=1NTi1i2ikei1ei2eik{\displaystyle T=\sum _{i_{1},\ldots ,i_{k}=1}^{N}T_{i_{1}i_{2}\cdots i_{k}}e^{i_{1}}\otimes e^{i_{2}}\otimes \cdots \otimes e^{i_{k}}}

for some unique list of coefficientsTi1i2ik{\displaystyle T_{i_{1}i_{2}\cdots i_{k}}} (thecomponents of the tensor in the basis) that are symmetric on the indices. That is to say

Tiσ1iσ2iσk=Ti1i2ik{\displaystyle T_{i_{\sigma 1}i_{\sigma 2}\cdots i_{\sigma k}}=T_{i_{1}i_{2}\cdots i_{k}}}

for everypermutationσ.

The space of all symmetric tensors of orderk defined onV is often denoted bySk(V) or Symk(V). It is itself a vector space, and ifV has dimensionN then the dimension of Symk(V) is thebinomial coefficient

dimSymk(V)=(N+k1k).{\displaystyle \dim \operatorname {Sym} ^{k}(V)={N+k-1 \choose k}.}

We then construct Sym(V) as thedirect sum of Symk(V) fork = 0,1,2,...

Sym(V)=k=0Symk(V).{\displaystyle \operatorname {Sym} (V)=\bigoplus _{k=0}^{\infty }\operatorname {Sym} ^{k}(V).}

Examples

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There are many examples of symmetric tensors. Some include, themetric tensor,gμν{\displaystyle g_{\mu \nu }}, theEinstein tensor,Gμν{\displaystyle G_{\mu \nu }} and theRicci tensor,Rμν{\displaystyle R_{\mu \nu }}.

Manymaterial properties andfields used in physics and engineering can be represented as symmetric tensor fields; for example:stress,strain, andanisotropicconductivity. Also, indiffusion MRI one often uses symmetric tensors to describe diffusion in the brain or other parts of the body.

Ellipsoids are examples ofalgebraic varieties; and so, for general rank, symmetric tensors, in the guise ofhomogeneous polynomials, are used to defineprojective varieties, and are often studied as such.

Given aRiemannian manifold(M,g){\displaystyle (M,g)} equipped with its Levi-Civita connection{\displaystyle \nabla }, thecovariant curvature tensor is a symmetric order 2 tensor over the vector spaceV=Ω2(M)=2TM{\textstyle V=\Omega ^{2}(M)=\bigwedge ^{2}T^{*}M} of differential 2-forms. This corresponds to the fact that, viewingRijk(TM)4{\displaystyle R_{ijk\ell }\in (T^{*}M)^{\otimes 4}}, we have the symmetryRijk=Rkij{\displaystyle R_{ij\,k\ell }=R_{k\ell \,ij}} between the first and second pairs of arguments in addition to antisymmetry within each pair:Rjik=Rijk=Rijk{\displaystyle R_{jik\ell }=-R_{ijk\ell }=R_{ij\ell k}}.[1]

Symmetric part of a tensor

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SupposeV{\displaystyle V} is a vector space over a field ofcharacteristic 0. IfTVk is a tensor of orderk{\displaystyle k}, then the symmetric part ofT{\displaystyle T} is the symmetric tensor defined by

SymT=1k!σSkτσT,{\displaystyle \operatorname {Sym} \,T={\frac {1}{k!}}\sum _{\sigma \in {\mathfrak {S}}_{k}}\tau _{\sigma }T,}

the summation extending over thesymmetric group onk symbols. In terms of a basis, and employing theEinstein summation convention, if

T=Ti1i2ikei1ei2eik,{\displaystyle T=T_{i_{1}i_{2}\cdots i_{k}}e^{i_{1}}\otimes e^{i_{2}}\otimes \cdots \otimes e^{i_{k}},}

then

SymT=1k!σSkTiσ1iσ2iσkei1ei2eik.{\displaystyle \operatorname {Sym} \,T={\frac {1}{k!}}\sum _{\sigma \in {\mathfrak {S}}_{k}}T_{i_{\sigma 1}i_{\sigma 2}\cdots i_{\sigma k}}e^{i_{1}}\otimes e^{i_{2}}\otimes \cdots \otimes e^{i_{k}}.}

The components of the tensor appearing on the right are often denoted by

T(i1i2ik)=1k!σSkTiσ1iσ2iσk{\displaystyle T_{(i_{1}i_{2}\cdots i_{k})}={\frac {1}{k!}}\sum _{\sigma \in {\mathfrak {S}}_{k}}T_{i_{\sigma 1}i_{\sigma 2}\cdots i_{\sigma k}}}

with parentheses () around the indices being symmetrized. Square brackets [] are used to indicate anti-symmetrization.

Symmetric product

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IfT is a simple tensor, given as a pure tensor product

T=v1v2vr{\displaystyle T=v_{1}\otimes v_{2}\otimes \cdots \otimes v_{r}}

then the symmetric part ofT is the symmetric product of the factors:

v1v2vr:=1r!σSrvσ1vσ2vσr.{\displaystyle v_{1}\odot v_{2}\odot \cdots \odot v_{r}:={\frac {1}{r!}}\sum _{\sigma \in {\mathfrak {S}}_{r}}v_{\sigma 1}\otimes v_{\sigma 2}\otimes \cdots \otimes v_{\sigma r}.}

In general we can turn Sym(V) into analgebra by defining the commutative and associative product ⊙.[2] Given two tensorsT1 ∈ Symk1(V) andT2 ∈ Symk2(V), we use the symmetrization operator to define:

T1T2=Sym(T1T2)(Symk1+k2(V)).{\displaystyle T_{1}\odot T_{2}=\operatorname {Sym} (T_{1}\otimes T_{2})\quad \left(\in \operatorname {Sym} ^{k_{1}+k_{2}}(V)\right).}

It can be verified (as is done by Kostrikin and Manin[2]) that the resulting product is in fact commutative and associative. In some cases the operator is omitted:T1T2 =T1T2.

In some cases an exponential notation is used:

vk=vvvk times=vvvk times=vk.{\displaystyle v^{\odot k}=\underbrace {v\odot v\odot \cdots \odot v} _{k{\text{ times}}}=\underbrace {v\otimes v\otimes \cdots \otimes v} _{k{\text{ times}}}=v^{\otimes k}.}

Wherev is a vector.Again, in some cases the ⊙ is left out:

vk=vvvk times=vvvk times.{\displaystyle v^{k}=\underbrace {v\,v\,\cdots \,v} _{k{\text{ times}}}=\underbrace {v\odot v\odot \cdots \odot v} _{k{\text{ times}}}.}

Decomposition

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In analogy with the theory ofsymmetric matrices, a (real) symmetric tensor of order 2 can be "diagonalized". More precisely, for any tensorT ∈ Sym2(V), there is an integerr, non-zero unit vectorsv1,...,vr ∈ V and weightsλ1,...,λr such that

T=i=1rλivivi.{\displaystyle T=\sum _{i=1}^{r}\lambda _{i}\,v_{i}\otimes v_{i}.}

The minimum numberr for which such a decomposition is possible is the (symmetric) rank ofT. The vectors appearing in this minimal expression are theprincipal axes of the tensor, and generally have an important physical meaning. For example, the principal axes of theinertia tensor define thePoinsot's ellipsoid representing the moment of inertia. Also seeSylvester's law of inertia.

For symmetric tensors of arbitrary orderk, decompositions

T=i=1rλivik{\displaystyle T=\sum _{i=1}^{r}\lambda _{i}\,v_{i}^{\otimes k}}

are also possible. The minimum numberr for which such a decomposition is possible is thesymmetricrank ofT.[3] This minimal decomposition is called a Waring decomposition; it is a symmetric form of thetensor rank decomposition. For second-order tensors this corresponds to the rank of the matrix representing the tensor in any basis, and it is well known that the maximum rank is equal to the dimension of the underlying vector space. However, for higher orders this need not hold: the rank can be higher than the number of dimensions in the underlying vector space. Moreover, the rank and symmetric rank of a symmetric tensor may differ.[4]

See also

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Notes

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  1. ^Carmo, Manfredo Perdigão do (1992).Riemannian geometry. Francis J. Flaherty. Boston: Birkhäuser.ISBN 0-8176-3490-8.OCLC 24667701.
  2. ^abKostrikin, Alexei I.;Manin, Iurii Ivanovich (1997).Linear algebra and geometry. Algebra, Logic and Applications. Vol. 1. Gordon and Breach. pp. 276–279.ISBN 9056990497.
  3. ^Comon, P.; Golub, G.; Lim, L. H.; Mourrain, B. (2008). "Symmetric Tensors and Symmetric Tensor Rank".SIAM Journal on Matrix Analysis and Applications.30 (3): 1254.arXiv:0802.1681.doi:10.1137/060661569.S2CID 5676548.
  4. ^Shitov, Yaroslav (2018)."A Counterexample to Comon's Conjecture".SIAM Journal on Applied Algebra and Geometry.2 (3):428–443.arXiv:1705.08740.doi:10.1137/17m1131970.ISSN 2470-6566.S2CID 119717133.

References

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External links

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