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Skewes's number

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Unsolved problem in mathematics
What is the smallest Skewes's number?
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Large number used in number theory

Innumber theory,Skewes's number is the smallestnatural numberx{\displaystyle x} for which theprime-counting functionπ(x){\displaystyle \pi (x)} exceeds thelogarithmic integral functionli(x).{\displaystyle \operatorname {li} (x).} It is named for theSouth African mathematicianStanley Skewes who first computed anupper bound on its value.

The exact value of Skewes's number is still not known, but it is known that there is a crossing betweenπ(x)<li(x){\displaystyle \pi (x)<\operatorname {li} (x)} andπ(x)>li(x){\displaystyle \pi (x)>\operatorname {li} (x)} neare727.95133<1.397×10316.{\displaystyle e^{727.95133}<1.397\times 10^{316}.} It is not known whether this is the smallest crossing.

The name is sometimes also applied to either of thelarge number bounds which Skewes found.

Skewes's bounds

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Although nobody has ever found a value ofx{\displaystyle x} for whichπ(x)>li(x),{\displaystyle \pi (x)>\operatorname {li} (x),} Skewes's research supervisorJ.E. Littlewood had proved inLittlewood (1914) that there is such a number (and so, a first such number); and indeed found that the sign of the differenceπ(x)li(x){\displaystyle \pi (x)-\operatorname {li} (x)} changes infinitely many times. Littlewood's proof did not, however, exhibit a concrete such numberx{\displaystyle x}, nor did it even give any bounds on the value.

Skewes's task was to make Littlewood's existence proofeffective: exhibit some concrete upper bound for the first sign change. According toGeorg Kreisel, this was not considered obvious even in principle at the time.[1]

Skewes (1933) proved that, assuming that theRiemann hypothesis is true, there exists a numberx{\displaystyle x} violatingπ(x)<li(x),{\displaystyle \pi (x)<\operatorname {li} (x),} below

eee79<10101034.{\displaystyle e^{e^{e^{79}}}<10^{10^{10^{34}}}.}

Without assuming the Riemann hypothesis,Skewes (1955) later proved that there exists a value ofx{\displaystyle x} below

eeee7.705<101010964.{\displaystyle e^{e^{e^{e^{7.705}}}}<10^{10^{10^{964}}}.}

More recent bounds

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These upper bounds have since been reduced considerably by using large-scale computer calculations ofzeros of theRiemann zeta function. The first estimate for the actual value of a crossover point was given byLehman (1966), who showed that somewhere between1.53×101165{\displaystyle 1.53\times 10^{1165}} and1.65×101165{\displaystyle 1.65\times 10^{1165}} there are more than10500{\displaystyle 10^{500}} consecutiveintegersx{\displaystyle x} withπ(x)>li(x){\displaystyle \pi (x)>\operatorname {li} (x)}.Without assuming the Riemann hypothesis,H. J. J. te Riele (1987) proved an upper bound of7×10370{\displaystyle 7\times 10^{370}}. A better estimate was1.39822×10316{\displaystyle 1.39822\times 10^{316}} discovered byBays & Hudson (2000), who showed there are at least10153{\displaystyle 10^{153}} consecutive integers somewhere near this value whereπ(x)>li(x){\displaystyle \pi (x)>\operatorname {li} (x)}. Bays and Hudson found a few much smaller values ofx{\displaystyle x} whereπ(x){\displaystyle \pi (x)} gets close toli(x){\displaystyle \operatorname {li} (x)}; the possibility that there are crossover points near these values does not seem to have been definitely ruled out yet, though computer calculations suggest they are unlikely to exist.Chao & Plymen (2010) gave a small improvement and correction to the result of Bays and Hudson.Saouter & Demichel (2010) found a smaller interval for a crossing, which was slightly improved byZegowitz (2010). The same source shows that there exists a numberx{\displaystyle x} violatingπ(x)<li(x),{\displaystyle \pi (x)<\operatorname {li} (x),} belowe727.9513468<1.39718×10316{\displaystyle e^{727.9513468}<1.39718\times 10^{316}}. This can be reduced toe727.9513386<1.39717×10316{\displaystyle e^{727.9513386}<1.39717\times 10^{316}} assuming the Riemann hypothesis.Stoll & Demichel (2011) conducted an analysis with up to 2×1011 complex zeros which gives computational evidence that a crossover may exist near1.397162914×10316{\displaystyle 1.397162914\times 10^{316}}.

Interval of crossing
Year# of complex
zeros used
byInterval# of consecutive integers withπ(x)>li(x){\displaystyle \pi (x)>\operatorname {li} (x)} given
2000106Bays and Hudson[1.39821924×10316, 1.39821925×10316]> 1×10153
2010107Chao and Plymen[exp(727.951858), exp(727.952178)]1×10154
20102.2×107Saouter and Demichel[exp(727.95132478), exp(727.95134682)] (without RH)
[exp(727.95133239), exp(727.95133920)] (assuming RH)
6.6587×10152 (without RH)
1.2741×10151 (assuming RH)
20102.2×107Zegowitz[exp(727.951324783), exp(727.951346802)] (without RH)
[exp(727.951332973), exp(727.951338612)] (assuming RH)
6.695531258×10152 (without RH)
1.15527413×10152 (assuming RH)

Rigorously,Rosser & Schoenfeld (1962) proved that there are no crossover points belowx=108{\displaystyle x=10^{8}}, improved byBrent (1975) to8×1010{\displaystyle 8\times 10^{10}}, byKotnik (2008) to1014{\displaystyle 10^{14}}, byPlatt & Trudgian (2014) to1.39×1017{\displaystyle 1.39\times 10^{17}}, and byBüthe (2015) to1019{\displaystyle 10^{19}}.

There is no explicit valuex{\displaystyle x} known for certain to have the propertyπ(x)>li(x),{\displaystyle \pi (x)>\operatorname {li} (x),} though computer calculations suggest some explicit numbers that are quite likely to satisfy this.

Even though thenatural density of the positive integers for whichπ(x)>li(x){\displaystyle \pi (x)>\operatorname {li} (x)} does not exist,Wintner (1941) showed that thelogarithmic density of these positive integers does exist and is positive.Rubinstein & Sarnak (1994) showed that this proportion is about2.6×10−7, which is surprisingly large given how far one has to go to find the first example.

Riemann's formula

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Riemann gave anexplicit formula forπ(x){\displaystyle \pi (x)}, whose leading terms are (ignoring some subtle convergence questions)

π(x)=li(x)12li(x)ρli(xρ)+smaller terms{\displaystyle \pi (x)=\operatorname {li} (x)-{\tfrac {1}{2}}\operatorname {li} ({\sqrt {x\,}})-\sum _{\rho }\operatorname {li} (x^{\rho })+{\text{smaller terms}}}

where the sum is over allρ{\displaystyle \rho } in the set ofnon-trivial zeros of the Riemann zeta function.

The largest error term in the approximationπ(x)li(x){\displaystyle \pi (x)\approx \operatorname {li} (x)} (if theRiemann hypothesis is true) is negative12li(x){\displaystyle {\tfrac {1}{2}}\operatorname {li} ({\sqrt {x\,}})}, showing thatli(x){\displaystyle \operatorname {li} (x)} is usually larger thanπ(x){\displaystyle \pi (x)}. The other terms above are somewhat smaller, and moreover tend to have different, seemingly random complexarguments, so mostly cancel out. Occasionally however, several of the larger ones might happen to have roughly the same complex argument, in which case they will reinforce each other instead of cancelling and will overwhelm the term12li(x){\displaystyle {\tfrac {1}{2}}\operatorname {li} ({\sqrt {x\,}})}.

The reason why the Skewes number is so large is that these smaller terms are quite alot smaller than the leading error term, mainly because the firstcomplex zero of the zeta function has quite a largeimaginary part, so a large number (several hundred) of them need to have roughly the same argument in order to overwhelm the dominant term. The chance ofN{\displaystyle N} random complex numbers having roughly the same argument is about 1 in2N{\displaystyle 2^{N}}.This explains whyπ(x){\displaystyle \pi (x)} is sometimes larger thanli(x),{\displaystyle \operatorname {li} (x),} and also why it is rare for this to happen.It also shows why finding places where this happens depends on large scale calculations of millions of high precision zeros of the Riemann zeta function.

The argument above is not a proof, as it assumes the zeros of the Riemann zeta function are random, which is not true. Roughly speaking, Littlewood's proof consists ofDirichlet's approximation theorem to show that sometimes many terms have about the same argument.In the event that the Riemann hypothesis is false, the argument is much simpler, essentially because the termsli(xρ){\displaystyle \operatorname {li} (x^{\rho })} for zeros violating the Riemann hypothesis (withreal part greater than1/2) are eventually larger thanli(x1/2){\displaystyle \operatorname {li} (x^{1/2})}.

The reason for the term12li(x1/2){\displaystyle {\tfrac {1}{2}}\mathrm {li} (x^{1/2})} is that, roughly speaking,li(x){\displaystyle \mathrm {li} (x)} actually counts powers ofprimes, rather than the primes themselves, withpn{\displaystyle p^{n}} weighted by1n{\displaystyle {\frac {1}{n}}}. The term12li(x1/2){\displaystyle {\tfrac {1}{2}}\mathrm {li} (x^{1/2})} is roughly analogous to a second-order correction accounting forsquares of primes.

Equivalent for primek-tuples

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An equivalent definition of Skewes's number exists forprimek-tuples (Tóth (2019)). LetP=(p,p+i1,p+i2,...,p+ik){\displaystyle P=(p,p+i_{1},p+i_{2},...,p+i_{k})} denote a prime (k + 1)-tuple,πP(x){\displaystyle \pi _{P}(x)} the number of primesp{\displaystyle p} belowx{\displaystyle x} such thatp,p+i1,p+i2,...,p+ik{\displaystyle p,p+i_{1},p+i_{2},...,p+i_{k}} are all prime, letliP(x)=2xdt(lnt)k+1{\displaystyle \operatorname {li_{P}} (x)=\int _{2}^{x}{\frac {dt}{(\ln t)^{k+1}}}} and letCP{\displaystyle C_{P}} denote its Hardy–Littlewood constant (seeFirst Hardy–Littlewood conjecture). Then the first primep{\displaystyle p} that violates the Hardy–Littlewood inequality for the (k + 1)-tupleP{\displaystyle P}, i.e., the first primep{\displaystyle p} such that

πP(p)>CPliP(p),{\displaystyle \pi _{P}(p)>C_{P}\operatorname {li} _{P}(p),}

(if such a prime exists) is theSkewes number forP.{\displaystyle P.}

The table below shows the currently known Skewes numbers for primek-tuples:

Primek-tupleSkewes numberFound by
(p,p + 2)1369391Wolf (2011)
(p,p + 4)5206837Tóth (2019)
(p,p + 2,p + 6)87613571Tóth (2019)
(p,p + 4,p + 6)337867Tóth (2019)
(p,p + 2,p + 6,p + 8)1172531Tóth (2019)
(p,p + 4,p +6 ,p + 10)827929093Tóth (2019)
(p,p + 2,p + 6,p + 8,p + 12)21432401Tóth (2019)
(p,p +4 ,p +6 ,p + 10,p + 12)216646267Tóth (2019)
(p,p + 4,p + 6,p + 10,p + 12,p + 16)251331775687Tóth (2019)
(p,p+2,p+6,p+8,p+12,p+18,p+20)7572964186421Pfoertner (2020)
(p,p+2,p+8,p+12,p+14,p+18,p+20)214159878489239Pfoertner (2020)
(p,p+2,p+6,p+8,p+12,p+18,p+20,p+26)1203255673037261Pfoertner / Luhn (2021)
(p,p+2,p+6,p+12,p+14,p+20,p+24,p+26)523250002674163757Luhn / Pfoertner (2021)
(p,p+6,p+8,p+14,p+18,p+20,p+24,p+26)750247439134737983Pfoertner / Luhn (2021)

The Skewes number (if it exists) forsexy primes(p,p+6){\displaystyle (p,p+6)} is still unknown.

It is also unknown whether all admissiblek-tuples have a corresponding Skewes number.

See also

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References

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  1. ^Kreisel (1951) quotes A. E. Ingham (1932) and J. E. Littlewood (1948) as stating "that the proof was believed to be 'non-constructive', or to require 'new ideas' of proof to make it constructive."

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