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Shear force

From Wikipedia, the free encyclopedia
Coplanar forces acting on the same body in opposite directions
Further information:Shear stress
Shearing forces act in one direction at the top, and the opposite direction at the bottom, causing shearingdeformation.
A crack or tear may develop in a body from parallel shearing forces acting in opposite directions at different points of the body. If the forces were aligned with each other, they would elongate or shorten the body, depending on their direction, rather than tear or crack it.

Insolid mechanics,shearing forces are unalignedforces acting on one part of abody in a specific direction, and another part of the body in the opposite direction. When the forces arecollinear (aligned with each other), they are calledtension forces orcompression forces. Shear force can also be defined in terms ofplanes: "If a plane is passed through a body, a force acting along this plane is called ashear force orshearing force."[1]

Force required to shear steel

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This section calculates the force required to cut a piece of material with a shearing action. The relevant information is the area of the material being sheared, i.e. the area across which the shearing action takes place, and the shear strength of the material. A round bar of steel is used as an example. The shear strength is calculated from the tensile strength using a factor which relates the two strengths. In this case 0.6 applies to the example steel, known as EN8 bright, although it can vary from 0.58 to 0.62 depending on application.

EN8 bright has a tensile strength of 800 MPa and mild steel, for comparison, has a tensile strength of 400 MPa.

To calculate the force to shear a 25 mm diameter bar of EN8 bright steel;

area of the bar in mm2 = (12.52)(π) ≈ 490.8 mm2
0.8 kN/mm2 × 490.8 mm2 = 392.64 kN ≈ 40 tonne-force
40 tonne-force × 0.6 (to change force from tensile to shear) = 24 tonne-force

When working with ariveted or tensionedbolted joint, the strength comes from friction between the materials bolted together. Bolts are correctly torqued to maintain the friction. The shear force only becomes relevant when the bolts are not torqued.

A bolt with property class 12.9 has a tensile strength of 1200 MPa (1 MPa = 1 N/mm2) or 1.2 kN/mm2 and the yield strength is 0.90 times tensile strength, 1080 MPa in this case.

A bolt with property class 4.6 has a tensile strength of 400 MPa (1 MPa = 1 N/mm2) or 0.4 kN/mm2 and yield strength is 0.60 times tensile strength, 240 MPa in this case.

See also

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References

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  1. ^William A. Nash (1 July 1998).Schaum's Outline of Theory and Problems of Strength of Materials. McGraw-Hill Professional. p. 82.ISBN 978-0-07-046617-3. Retrieved20 May 2012.
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