Inmathematics, ameasure is said to besaturated if every locally measurable set is alsomeasurable.^[1] A set${\displaystyle E}$, not necessarily measurable, is said to be alocally measurable set if for every measurable set${\displaystyle A}$ of finite measure,${\displaystyle E\cap A}$ is measurable.${\displaystyle \sigma }$-finite measures and measures arising as the restriction ofouter measures are saturated.

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