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Mole fraction

From Wikipedia, the free encyclopedia
Proportion of a constituent in a mixture
mole fraction
Other names
molar fraction, amount fraction, amount-of-substance fraction
Common symbols
x
SI unit1
Other units
mol/mol

Inchemistry, themole fraction ormolar fraction, also calledmole proportion ormolar proportion, is aquantity defined as theratio between theamount of a constituent substance,ni (expressed inunit ofmoles, symbol mol), and the total amount of all constituents in a mixture,ntot (also expressed in moles):[1]

xi=nintot{\displaystyle x_{i}={\frac {n_{i}}{n_{\mathrm {tot} }}}}

It isdenotedxi (lowercaseRoman letterx), sometimesχi (lowercaseGreek letterchi).[2][3] (For mixtures of gases, the lettery is recommended.[1][4])

It is adimensionless quantity withdimension ofN/N{\displaystyle {\mathsf {N}}/{\mathsf {N}}} anddimensionless unit ofmoles per mole (mol/mol ormol⋅mol−1) or simply 1;metric prefixes may also be used (e.g., nmol/mol for10−9).[5]When expressed inpercent, it is known as themole percent ormolar percentage (unit symbol %, sometimes "mol%", equivalent to cmol/mol for10−2).The mole fraction is calledamount fraction by theInternational Union of Pure and Applied Chemistry (IUPAC)[1] andamount-of-substance fraction by the U.S.National Institute of Standards and Technology (NIST).[6] This nomenclature is part of theInternational System of Quantities (ISQ), as standardized inISO 80000-9,[4] which deprecates "mole fraction" based on the unacceptability of mixing information with units when expressing the values of quantities.[6]

The sum of all the mole fractions in a mixture is equal to 1:

i=1Nni=ntot; i=1Nxi=1{\displaystyle \sum _{i=1}^{N}n_{i}=n_{\mathrm {tot} };\ \sum _{i=1}^{N}x_{i}=1}

Mole fraction is numerically identical to thenumber fraction, which is defined as thenumber of particles (molecules) of a constituentNi divided by the total number of all moleculesNtot. Whereas mole fraction is a ratio of amounts to amounts (in units of moles per moles),molar concentration is a quotient of amount to volume (in units of moles per litre).Other ways of expressing the composition of a mixture as adimensionless quantity aremass fraction andvolume fraction.

Properties

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Mole fraction is used very frequently in the construction ofphase diagrams. It has a number of advantages:

Differential quotients can be formed at constant ratios like those above:

(x1x2)x1x3=x11x2{\displaystyle \left({\frac {\partial x_{1}}{\partial x_{2}}}\right)_{\frac {x_{1}}{x_{3}}}=-{\frac {x_{1}}{1-x_{2}}}}

or

(x3x2)x1x3=x31x2{\displaystyle \left({\frac {\partial x_{3}}{\partial x_{2}}}\right)_{\frac {x_{1}}{x_{3}}}=-{\frac {x_{3}}{1-x_{2}}}}

The ratiosX,Y, andZ of mole fractions can be written for ternary and multicomponent systems:

X=x3x1+x3Y=x3x2+x3Z=x2x1+x2{\displaystyle {\begin{aligned}X&={\frac {x_{3}}{x_{1}+x_{3}}}\\[2pt]Y&={\frac {x_{3}}{x_{2}+x_{3}}}\\[2pt]Z&={\frac {x_{2}}{x_{1}+x_{2}}}\end{aligned}}}

These can be used for solving PDEs like:

(μ2n1)n2,n3=(μ1n2)n1,n3{\displaystyle \left({\frac {\partial \mu _{2}}{\partial n_{1}}}\right)_{n_{2},n_{3}}=\left({\frac {\partial \mu _{1}}{\partial n_{2}}}\right)_{n_{1},n_{3}}}

or

(μ2n1)n2,n3,n4,,ni=(μ1n2)n1,n3,n4,,ni{\displaystyle \left({\frac {\partial \mu _{2}}{\partial n_{1}}}\right)_{n_{2},n_{3},n_{4},\ldots ,n_{i}}=\left({\frac {\partial \mu _{1}}{\partial n_{2}}}\right)_{n_{1},n_{3},n_{4},\ldots ,n_{i}}}

This equality can be rearranged to have differential quotient of mole amounts or fractions on one side.

(μ2μ1)n2,n3=(n1n2)μ1,n3=(x1x2)μ1,n3{\displaystyle \left({\frac {\partial \mu _{2}}{\partial \mu _{1}}}\right)_{n_{2},n_{3}}=-\left({\frac {\partial n_{1}}{\partial n_{2}}}\right)_{\mu _{1},n_{3}}=-\left({\frac {\partial x_{1}}{\partial x_{2}}}\right)_{\mu _{1},n_{3}}}

or

(μ2μ1)n2,n3,n4,,ni=(n1n2)μ1,n2,n4,,ni{\displaystyle \left({\frac {\partial \mu _{2}}{\partial \mu _{1}}}\right)_{n_{2},n_{3},n_{4},\ldots ,n_{i}}=-\left({\frac {\partial n_{1}}{\partial n_{2}}}\right)_{\mu _{1},n_{2},n_{4},\ldots ,n_{i}}}

Mole amounts can be eliminated by forming ratios:

(n1n2)n3=(n1n3n2n3)n3=(x1x3x2x3)n3{\displaystyle \left({\frac {\partial n_{1}}{\partial n_{2}}}\right)_{n_{3}}=\left({\frac {\partial {\frac {n_{1}}{n_{3}}}}{\partial {\frac {n_{2}}{n_{3}}}}}\right)_{n_{3}}=\left({\frac {\partial {\frac {x_{1}}{x_{3}}}}{\partial {\frac {x_{2}}{x_{3}}}}}\right)_{n_{3}}}

Thus the ratio of chemical potentials becomes:

(μ2μ1)n2n3=(x1x3x2x3)μ1{\displaystyle \left({\frac {\partial \mu _{2}}{\partial \mu _{1}}}\right)_{\frac {n_{2}}{n_{3}}}=-\left({\frac {\partial {\frac {x_{1}}{x_{3}}}}{\partial {\frac {x_{2}}{x_{3}}}}}\right)_{\mu _{1}}}

Similarly the ratio for the multicomponents system becomes

(μ2μ1)n2n3,n3n4,,ni1ni=(x1x3x2x3)μ1,n3n4,,ni1ni{\displaystyle \left({\frac {\partial \mu _{2}}{\partial \mu _{1}}}\right)_{{\frac {n_{2}}{n_{3}}},{\frac {n_{3}}{n_{4}}},\ldots ,{\frac {n_{i-1}}{n_{i}}}}=-\left({\frac {\partial {\frac {x_{1}}{x_{3}}}}{\partial {\frac {x_{2}}{x_{3}}}}}\right)_{\mu _{1},{\frac {n_{3}}{n_{4}}},\ldots ,{\frac {n_{i-1}}{n_{i}}}}}

Related quantities

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Mass fraction

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Themass fractionwi can be calculated using the formula

wi=xiMiM¯=xiMijxjMj{\displaystyle w_{i}=x_{i}{\frac {M_{i}}{\bar {M}}}=x_{i}{\frac {M_{i}}{\sum _{j}x_{j}M_{j}}}}

whereMi is the molar mass of the componenti and is the averagemolar mass of the mixture.

Molar mixing ratio

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The mixing of two pure components can be expressed introducing the amount or molarmixing ratio of themrn=n2n1{\displaystyle r_{n}={\frac {n_{2}}{n_{1}}}}. Then the mole fractions of the components will be:

x1=11+rnx2=rn1+rn{\displaystyle {\begin{aligned}x_{1}&={\frac {1}{1+r_{n}}}\\[2pt]x_{2}&={\frac {r_{n}}{1+r_{n}}}\end{aligned}}}

The amount ratio equals the ratio of mole fractions of components:

n2n1=x2x1{\displaystyle {\frac {n_{2}}{n_{1}}}={\frac {x_{2}}{x_{1}}}}

due to division of both numerator and denominator by the sum of molar amounts of components. This property has consequences for representations ofphase diagrams using, for instance,ternary plots.

Mixing binary mixtures with a common component to form ternary mixtures

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Mixing binary mixtures with a common component gives a ternary mixture with certain mixing ratios between the three components. These mixing ratios from the ternary and the corresponding mole fractions of the ternary mixture x1(123), x2(123), x3(123) can be expressed as a function of several mixing ratios involved, the mixing ratios between the components of the binary mixtures and the mixing ratio of the binary mixtures to form the ternary one.

x1(123)=n(12)x1(12)+n13x1(13)n(12)+n(13){\displaystyle x_{1(123)}={\frac {n_{(12)}x_{1(12)}+n_{13}x_{1(13)}}{n_{(12)}+n_{(13)}}}}

Mole percentage

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Multiplying mole fraction by 100 gives the mole percentage, also referred as amount/amount percent [abbreviated as (n/n)% or mol %].

Mass concentration

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The conversion to and frommass concentrationρi is given by:

xi=ρiρM¯Miρi=xiρMiM¯{\displaystyle {\begin{aligned}x_{i}&={\frac {\rho _{i}}{\rho }}{\frac {\bar {M}}{M_{i}}}\\[3pt]\Leftrightarrow \rho _{i}&=x_{i}\rho {\frac {M_{i}}{\bar {M}}}\end{aligned}}}

where is the average molar mass of the mixture.

Molar concentration

[edit]

The conversion tomolar concentrationci is given by:

ci=xic=xiρM¯=xiρjxjMj{\displaystyle {\begin{aligned}c_{i}&=x_{i}c\\[3pt]&={\frac {x_{i}\rho }{\bar {M}}}={\frac {x_{i}\rho }{\sum _{j}x_{j}M_{j}}}\end{aligned}}}

where is the average molar mass of the solution,c is the total molar concentration andρ is thedensity of the solution.

Mass and molar mass

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The mole fraction can be calculated from themassesmi andmolar massesMi of the components:

xi=miMijmjMj{\displaystyle x_{i}={\frac {\frac {m_{i}}{M_{i}}}{\sum _{j}{\frac {m_{j}}{M_{j}}}}}}

Spatial variation and gradient

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In aspatially non-uniform mixture, the mole fractiongradient triggers the phenomenon ofdiffusion.

References

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  1. ^abcIUPAC,Compendium of Chemical Terminology, 5th ed. (the "Gold Book") (2025). Online version: (2006–) "amount fraction".doi:10.1351/goldbook.A00296
  2. ^Zumdahl, Steven S. (2008).Chemistry (8th ed.). Cengage Learning. p. 201.ISBN 978-0-547-12532-9.
  3. ^Rickard, James N.; Spencer, George M.; Bodner, Lyman H. (2010).Chemistry: Structure and Dynamics (5th ed.). Hoboken, N.J.: Wiley. p. 357.ISBN 978-0-470-58711-9.
  4. ^ab"ISO 80000-9:2019 Quantities and units — Part 9: Physical chemistry and molecular physics".ISO. 2013-08-20. Retrieved2023-08-29.
  5. ^"SI Brochure".BIPM. Retrieved2023-08-29.
  6. ^abThompson, A.; Taylor, B. N. (2 July 2009)."The NIST Guide for the use of the International System of Units". National Institute of Standards and Technology. Retrieved5 July 2014.
Mole concepts
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