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Laurent series

From Wikipedia, the free encyclopedia
Power series with negative powers
This article is about doubly infinite power series. For power series with finitely many negative exponents, seeFormal Laurent series.
A Laurent series is defined with respect to a particular pointc{\displaystyle c} and a path of integration γ. The path of integration must lie in an annulus, indicated here by the red color, inside whichf(z){\displaystyle f(z)} isholomorphic (analytic).
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Inmathematics, theLaurent series of acomplex functionf(z){\displaystyle f(z)} is a representation of that function as apower series which includes terms of negative degree. It may be used to express complex functions in cases where aTaylor series expansion cannot be applied. The Laurent series was named after and first published byPierre Alphonse Laurent in 1843.Karl Weierstrass had previously described it in a paper written in 1841 but not published until 1894.[1]

Definition

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The Laurent series for a complex functionf(z){\displaystyle f(z)} about an arbitrary pointc{\displaystyle c} is given by[2][3]f(z)=n=an(zc)n,{\displaystyle f(z)=\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n},}where the coefficientsan{\displaystyle a_{n}} are defined by acontour integral that generalizesCauchy's integral formula:an=12πiγf(z)(zc)n+1dz.{\displaystyle a_{n}={\frac {1}{2\pi i}}\oint _{\gamma }{\frac {f(z)}{(z-c)^{n+1}}}\,dz.}

The path of integrationγ{\displaystyle \gamma } is counterclockwise around aJordan curve enclosingc{\displaystyle c} and lying in anannulusA{\displaystyle A} in whichf(z){\displaystyle f(z)} isholomorphic (analytic). The expansion forf(z){\displaystyle f(z)} will then be valid anywhere inside the annulus. The annulus is shown in red in the figure on the right, along with an example of a suitable path of integration labeledγ{\displaystyle \gamma }. Whenγ{\displaystyle \gamma } is defined as thecircle|zc|=ϱ{\displaystyle |z-c|=\varrho }, wherer<ϱ<R{\displaystyle r<\varrho <R}, this amountsto computing the complexFourier coefficients of the restriction off{\displaystyle f} toγ{\displaystyle \gamma }.[4] The fact that these integrals are unchanged by a deformation of the contourγ{\displaystyle \gamma } is an immediate consequence ofGreen's theorem.

One may also obtain the Laurent series for a complex functionf(z){\displaystyle f(z)} atz={\displaystyle z=\infty }. However, this is the same as whenR{\displaystyle R\rightarrow \infty }.

The above integral formula may not offer the most practical method for computing the coefficientsan{\displaystyle a_{n}} for a given functionf(z){\displaystyle f(z)}; instead, one often pieces together the Laurent series by combining known Taylor expansions. Because the Laurent expansion of a function isunique wheneverit exists, any expression of this form that equals the given functionf(z){\displaystyle f(z)} in some annulus must actually be the Laurent expansion off(z){\displaystyle f(z)}.

Convergence

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e−1/x2 and its Laurent approximations (labeled) with the negative degree rising. The neighborhood around the zero singularity can never be approximated.
e−1/x2 and its Laurent approximations. As the negative degree of the Laurent series rises, it approaches the correct function.

Laurent series with complex coefficients are an important tool incomplex analysis, especially to investigate the behavior of functions nearsingularities.

Consider for instance the functionf(x)=e1/x2{\displaystyle f(x)=e^{-1/x^{2}}} withf(0)=0{\displaystyle f(0)=0}. As a real function, it is infinitely differentiable everywhere; as a complex function however it is not differentiable atx=0{\displaystyle x=0}. The Laurent series off(x){\displaystyle f(x)} is obtained via thepower series representation,e1/x2=n=0(1)nx2nn!,{\displaystyle e^{-1/x^{2}}=\sum _{n=0}^{\infty }(-1)^{n}\,{x^{-2n} \over n!},}which converges tof(x){\displaystyle f(x)} for allxC{\displaystyle x\in \mathbb {C} } except at the singularityx=0{\displaystyle x=0}. The graph on the right showsf(x){\displaystyle f(x)} in black and its Laurent approximationsn=0N(1)nx2nn!,NN+.{\displaystyle \sum _{n=0}^{N}(-1)^{n}\,{x^{-2n} \over n!},\quad \forall N\in \mathbb {N} ^{+}.}AsN{\displaystyle N\to \infty }, the approximation becomes exact for all (complex) numbersx{\displaystyle x} except at the singularityx=0{\displaystyle x=0}.

More generally, Laurent series can be used to expressholomorphic functions defined on anannulus, much aspower series are used to express holomorphic functions defined on adisc.

Supposen=an(zc)n{\displaystyle \sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n}}is a given Laurent series with complex coefficientsan{\displaystyle a_{n}} and a complex centerc{\displaystyle c}. Then there exists aunique inner radiusr{\displaystyle r} and outer radiusR{\displaystyle R} such that:

It is possible thatr{\displaystyle r} may be zero orR{\displaystyle R} may be infinite; at the other extreme, it's not necessarily true thatr{\displaystyle r} is less thanR{\displaystyle R}.These radii can be computed by taking thelimit superior of the coefficientsan{\displaystyle a_{n}} such that:r=lim supn|an|1n,1R=lim supn|an|1n.{\displaystyle {\begin{aligned}r&=\limsup _{n\to \infty }|a_{-n}|^{\frac {1}{n}},\\{\frac {1}{R}}&=\limsup _{n\to \infty }|a_{n}|^{\frac {1}{n}}.\end{aligned}}}

Whenr=0{\displaystyle r=0}, the coefficienta1{\displaystyle a_{-1}} of the Laurent expansion is called theresidue off(z){\displaystyle f(z)} at the singularityc{\displaystyle c}.[6] For example, the functionf(z)=ezz+e1/z,{\displaystyle f(z)={e^{z} \over z}+e^{{1}/{z}},}is holomorphic everywhere except atz=0{\displaystyle z=0}. The Laurent expansion aboutc=0{\displaystyle c=0} can then be obtained from the power series representation:f(z)=+(13!)z3+(12!)z2+2z1+2+(12!)z+(13!)z2+(14!)z3+,{\displaystyle f(z)=\cdots +\left({1 \over 3!}\right)z^{-3}+\left({1 \over 2!}\right)z^{-2}+2z^{-1}+2+\left({1 \over 2!}\right)z+\left({1 \over 3!}\right)z^{2}+\left({1 \over 4!}\right)z^{3}+\cdots ,}hence, the residue is given bya1=2{\displaystyle a_{-1}=2}.

Conversely, for a holomorphic functionf(z){\displaystyle f(z)} defined on the annulusA={z:r<|zc|<R}{\displaystyle A=\{z:r<|z-c|<R\}}, there always exists a unique Laurent series with centerc{\displaystyle c} which converges (at least onA{\displaystyle A}) tof(z){\displaystyle f(z)}.

For example, consider the following rational function, along with itspartial fraction expansion:f(z)=1(z1)(z2i)=1+2i5(1z11z2i).{\displaystyle f(z)={\frac {1}{(z-1)(z-2i)}}={\frac {1+2i}{5}}\left({\frac {1}{z-1}}-{\frac {1}{z-2i}}\right).}

This function has singularities atz=1{\displaystyle z=1} andz=2i{\displaystyle z=2i}, where the denominator is zero and the expression is therefore undefined.ATaylor series aboutz=0{\displaystyle z=0} (which yields a power series) will only converge in a disc ofradius 1, since it "hits" the singularity atz=1{\displaystyle z=1}.

However, there are three possible Laurent expansions about 0, depending on the radius ofz{\displaystyle z}:

Uniqueness

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Suppose a functionf(z){\displaystyle f(z)} holomorphic on the annulusr<|zc|<R{\displaystyle r<|z-c|<R} has two Laurent series:f(z)=n=an(zc)n=n=bn(zc)n.{\displaystyle f(z)=\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n}=\sum _{n=-\infty }^{\infty }b_{n}(z-c)^{n}.}

Multiply both sides by(zc)k1{\displaystyle (z-c)^{-k-1}}, where k is an arbitrary integer, and integrate on a path γ inside the annulus,γn=an(zc)nk1dz=γn=bn(zc)nk1dz.{\displaystyle \oint _{\gamma }\,\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n-k-1}\,dz=\oint _{\gamma }\,\sum _{n=-\infty }^{\infty }b_{n}(z-c)^{n-k-1}\,dz.}

The series converges uniformly onr+ε|zc|Rε{\displaystyle r+\varepsilon \leq |z-c|\leq R-\varepsilon }, whereε is a positive number small enough forγ to be contained in the constricted closed annulus, so the integration and summation can be interchanged. Substituting the identityγ(zc)nk1dz=2πiδnk{\displaystyle \oint _{\gamma }\,(z-c)^{n-k-1}\,dz=2\pi i\delta _{nk}}into the summation yieldsak=bk.{\displaystyle a_{k}=b_{k}.}

Hence the Laurent series is unique.

Laurent polynomials

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Main article:Laurent polynomial

ALaurent polynomial is a Laurent series in which only finitely many coefficients are non-zero. Laurent polynomials differ from ordinarypolynomials in that they may have terms of negative degree.

Principal part

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For broader coverage of this topic, seePrincipal part.

Theprincipal part of a Laurent series is the series of terms with negative degree, that isk=1ak(zc)k.{\displaystyle \sum _{k=-\infty }^{-1}a_{k}(z-c)^{k}.}

If the principal part off{\displaystyle f} is a finite sum, thenf{\displaystyle f} has apole atc{\displaystyle c} of order equal to (negative) the degree of the highest term; on the other hand, iff{\displaystyle f} has anessential singularity atc{\displaystyle c}, the principal part is an infinite sum (meaning it has infinitely many non-zero terms).

If the inner radius of convergence of the Laurent series forf{\displaystyle f} is 0, thenf{\displaystyle f} has an essential singularity atc{\displaystyle c} if and only if the principal part is an infinite sum, and has a pole otherwise.

If the inner radius of convergence is positive,f{\displaystyle f} may have infinitely many negative terms but still be regular atc{\displaystyle c}, as in the example above, in which case it is represented by adifferent Laurent series in a disk about c{\displaystyle c}.

Laurent series with only finitely many negative terms are well-behaved—they are a power series divided byzk{\displaystyle z^{k}}, and can be analyzed similarly—while Laurent series with infinitely many negative terms have complicated behavior on the inner circle of convergence.

Multiplication and sum

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Laurent series cannot in general be multiplied.Algebraically, the expression for the terms of the product may involve infinite sums which need not converge (one cannot take theconvolution of integer sequences).Geometrically, the two Laurent series may have non-overlapping annuli of convergence.

Two Laurent series with onlyfinitely many negative terms can be multiplied: algebraically, the sums are all finite; geometrically, these have poles atc{\displaystyle c}, and inner radius of convergence 0, so they both converge on an overlapping annulus.

Thus when definingformal Laurent series, one requires Laurent series with only finitely many negative terms.

Similarly, the sum of two convergent Laurent series need not converge, though it is always defined formally, but the sum of two bounded below Laurent series (or any Laurent series on a punctured disk) has a non-empty annulus of convergence.

Also, for a fieldF{\displaystyle F}, by the sum and multiplication defined above,formal Laurent series would form a fieldF((x)){\displaystyle F((x))} which is also the field of fractions of the ringF[[x]]{\displaystyle F[[x]]} offormal power series.

See also

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Notes

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  1. ^Roy, Ranjan (2012),"§1.5 Appendix: Historical Notes by Ranjan Roy",Complex Analysis: In the Spirit of Lipman Bers, byRodríguez, Rubí E.;Kra, Irwin;Gilman, Jane P. (2nd ed.), Springer, p. 12,doi:10.1007/978-1-4419-7323-8_1,ISBN 978-1-4419-7322-1
    Weierstrass, Karl (1841),"Darstellung einer analytischen Function einer complexen Veränderlichen, deren absoluter Betrag zwischen zwei gegebenen Grenzen liegt" [Representation of an analytical function of a complex variable, whose absolute value lies between two given limits],Mathematische Werke (in German), vol. 1, Berlin: Mayer & Müller (published 1894), pp. 51–66
  2. ^Ablowitz & Fokas 2003, p. 128
  3. ^Folland, Gerald B. (1992),Fourier analysis and its applications, Pacific Grove, Calif: Wadsworth & Brooks/Cole, p. 395,ISBN 978-0-534-17094-3
  4. ^Ablowitz & Fokas 2003, pp. 196–197
  5. ^Ablowitz & Fokas 2003, p. 152
  6. ^Ablowitz & Fokas 2003, p. 130

References

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External links

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